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NEET • CHEMISTRY • HYDROGEN

Hydrogen practice · Hard

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1 Hard

1 of 15

Understanding +4 | -1

Consider the following statements:
1. Atomic hydrogen is obtained by passing hydrogen through an electric arc.
2. Hydrogen gas will not reduce heated aluminium oxide.
3. Finely divided palladium adsorbs large volume of hydrogen gas
4. Pure nascent hydrogen is best obtained by reacting

Na

with

C_2H_5OH

Which of the above statements is/are correct?

View answer and explanation

Correct option: C

1, 2 and 3

Option C (1, 2 and 3) is correct because statements 1, 2, and 3 are all factually accurate regarding the properties and reactions of hydrogen.

2 Hard

2 of 15

Analyzing +4 | -1

Assertion (A) : On adding zinc pieces to

{FeCl}_3(a q)

solution, colour changes from deep yellow to light green.

Reason (R) : Aqueous

{FeCl}_3

solution is acidic and on adding zinc, nascent hydrogen is produced which reduces deep yellow

m{FeCl}_3

solution to light green

{FeCl}_2

solution.

View answer and explanation

Correct option: A

Both

\mathbf{A}

and

\mathbf{R}

are true and

\mathbf{R}

is the correct explanation of

\mathbf{A}

Option A (Both

\mathbf{A}

and

\mathbf{R}

are true and

\mathbf{R}

is the correct explanation of

\mathbf{A}

) is correct because the zinc reduces the iron(III) chloride to iron(II) chloride, causing the color change.

3 Hard

3 of 15

Application +4 | -1

The hardness of a water sample (in terms of equivalents of

CaC{O_3})

containing

{10^{ - 3}}M\,CaS{O_4}

(Molar mass of

CaS{O_4} = 136\,\,g\,\,mo{l^{ - 1}})

View answer and explanation

Correct option: A

100 ppm

Option A (100 ppm) is correct because the hardness is calculated by converting the molarity of CaSO4 to ppm of CaCO3.

4 Hard

4 of 15

Application +4 | -1

100 mL of a water sample contains 0.81 g of calcium bicarbonate and 0.73 g of magnesium bicarbonate.
The hardness of this water sample expressed in terms of equivalents of

CaC{O_3}

is
(molar mass of calcium bicarbonate is

162\,g\,mo{l^{ - 1}}

and magnesium bicarbonate is

146\,g\,mo{l^{ - 1}}

)

View answer and explanation

Correct option: D

10,000 ppm

Option D (10,000 ppm) is correct because it is calculated by converting the bicarbonates to CaCO3 equivalents and then to ppm.

5 Hard

5 of 15

Application +4 | -1

1 \mathrm{~L}

of hard water (contains

\mathrm{CaSO}_4

) requires

0.286 \mathrm{~g}

of washing soda

\left(\mathrm{Na}_2 \mathrm{CO}_3 \cdot 10 \mathrm {H}_2 \mathrm{O}\right)

for softening process. What is the hardness of water in ppm?

View answer and explanation

Correct option: A

100

Option A (100) is correct because the hardness is calculated based on the amount of washing soda required to react with the CaSO4.

6 Hard

6 of 15

Application +4 | -1

Temporary hardness is due to bicarbonates of

{Mg}^{2+}

and

{Ca}^{2+}

. It is removed by addition of

{CaO}

as follows

{Ca}\left({HCO}_3\right)_2+{CaO} \longrightarrow 2 {CaCO}_3+{H}_2 {O}

Mass of

{CaO}

required to precipitate

2 {~g} \,{CaCO}_3

is:

View answer and explanation

Correct option: B

0.56 {~g}

Option B (

0.56 {~g}

) is correct because it is calculated based on the stoichiometry of the reaction between Ca(HCO3)2 and CaO.

7 Hard

7 of 15

Understanding +4 | -1

The products obtained during treatment of hard water using Clark’s method are:

View answer and explanation

Correct option: C

\mathrm{CaCO}_3

and

\mathrm{Mg}(\mathrm{OH})_2

Option C (

\mathrm{CaCO}_3

and

\mathrm{Mg}(\mathrm{OH})_2

) is correct because Clark's method precipitates calcium as calcium carbonate and magnesium as magnesium hydroxide.

8 Hard

8 of 15

Application +4 | -1

The strength in volumes of a solution containing

30.36\;g/L

{\mathrm{H}_2}{\mathrm{O}_2}

View answer and explanation

Correct option: A

10 V

Option A (10 V) is correct because the volume strength is calculated by dividing the concentration in g/L by the equivalent weight and multiplying by 11.2.

9 Hard

9 of 15

Analyzing +4 | -1

In which of the following reactions,

\mathrm{H}_2 \mathrm{O}_2

does not act as reductant?

View answer and explanation

Correct option: A

2 \mathrm{KBr}+\mathrm{H}_2 \mathrm{O}_2 \longrightarrow \mathrm{Br}_2+2 \mathrm{KOH}

Option A (

\mathrm{C}

) is correct because carbon is generally unreactive with NaOH under normal conditions.

10 Hard

10 of 15

Remembering +4 | -1

In industrial method,

1 \% \mathrm{~H}_2 \mathrm{O}_2

is obtained by auto oxidation of 2-ethyl anthraquinol.

1 \% \mathrm{~H}_2 \mathrm{O}_2

so formed is extracted with

View answer and explanation

Correct option: A

\mathrm{H}_2 \mathrm{O}

Option A is correct because in the industrial method, the

1 \% \mathrm{~H}_2 \mathrm{O}_2

formed by auto-oxidation of 2-ethyl anthraquinol is extracted with

\mathrm{H}_2 \mathrm{O}

11 Hard

11 of 15

Application +4 | -1

The volume of oxygen liberated from

15\;\mathrm{mL}

of 20 volume

{\mathrm{H}_2}{\mathrm{O}_2}

View answer and explanation

Correct option: B

300 mL

Option B (300 mL) is correct because the volume of oxygen liberated is calculated by multiplying the volume of the

H_2O_2

solution by its volume strength.

12 Hard

12 of 15

Application +4 | -1

A sample of hard water containing

{Ca}^{2+}(\mathrm{aq})

ions, having concentration

400 \, \mathrm{ppm}

is passed through cation exchange resin

({RH})

which exchanges

{Ca}^{2+}(\mathrm{aq})

ions for

{H}^{+}(\mathrm{aq})

. What is the volume of

1 \, \mathrm{M}

{NaOH}

required to neutralise

1 \mathrm{~L}

of water obtained from cation exchange resin after exchange of

{Ca}^{2+}

of hard water?

View answer and explanation

Correct option: A

20 \mathrm{~mL}

Option A (

20 \mathrm{~mL}

) is correct because the volume of NaOH required is calculated based on the amount of Ca2+ exchanged for H+ ions.

13 Hard

13 of 15

Remembering +4 | -1

The ratio of moles of water as water of crystallisation in

{CaCl}_2

and

{SrCl}_2

View answer and explanation

Correct option: C

1: 1

Option C (

1: 1

) is correct because both

{CaCl}_2

and

{SrCl}_2

typically crystallize as dihydrates, resulting in a 1:1 ratio of water molecules.

14 Hard

14 of 15

Understanding +4 | -1

Heavy water reacts respectively with

\mathrm{CO}_2, \mathrm{SO}_3

\mathrm{P}_2 \mathrm{O}_5

and

\mathrm{N}_2 \mathrm{O}_5

to give the compounds

View answer and explanation

Correct option: D

\mathrm{D}_2 \mathrm{CO}_3, \mathrm{D}_2 \mathrm{SO}_4, \mathrm{D}_3 \mathrm{PO}_4, \mathrm{DNO}_3

Option D (

\mathrm{D}_2 \mathrm{CO}_3, \mathrm{D}_2 \mathrm{SO}_4, \mathrm{D}_3 \mathrm{PO}_4, \mathrm{DNO}_3

) is correct because heavy water (

D_2O

) reacts with acidic oxides to form deuterated acids.

15 Hard

15 of 15

Application +4 | -1

The hardness of water sample containing 0.002 mole of magnesium sulphate dissolved in a litre of water is expressed as

View answer and explanation

Correct option: B

200 ppm

Option B (200 ppm) is correct because the hardness is calculated by converting moles of magnesium sulfate to ppm of calcium carbonate equivalent.

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