The stability ${\rm{of}}\,{\rm{ + }}\,{\rm{1}}$ oxidation state among $Al,\,Ga, In \,\&\, TI$ increases in the sequence:

$TI\, < \,In\, < \,Ga\, < \,Al$

$\,In\, < \,TI < Ga\, < \,Al\,$

$Ga\, < \,In\, < \,Al\, < \,TI$

The correct order of atomic radii in group ${\rm{13}}$ elements is

${\rm{B}}\,\,{\rm{ < }}\,\,{\rm{Ga}}\,\,{\rm{ < }}\,\,{\rm{Al}}\,\,{\rm{ < }}\,\,{\rm{In}}\,\,{\rm{ < }}\,\,{\rm{Tl}}$

${\rm{B}}\,\,{\rm{ < }}\,\,{\rm{Al}}\,\,{\rm{ < }}\,\,{\rm{In}}\,\,{\rm{ < }}\,\,{\rm{Ga}}\,\,{\rm{ < }}\,\,{\rm{Tl}}$

${\rm{B}}\,\,{\rm{ < }}\,\,{\rm{Ga}}\,\,{\rm{ < }}\,\,{\rm{Al}}\,\,{\rm{ < }}\,\,{\rm{Tl}}\,\,{\rm{ < }}\,\,{\rm{In}}$

${\rm{B}}\,\,{\rm{ < }}\,\,{\rm{Al}}\,\,{\rm{ < }}\,\,{\rm{Ga}}\,\,{\rm{ < }}\,\,{\rm{In}}\,\,{\rm{ < }}\,\,{\rm{Tl}}$

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NEET • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)

13 th group elements (p-block) practice · Easy

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31 Easy

31 of 52

Analyzing +4 | -1

The maximum number of atoms is lying in one plan for

\mathrm{B}_2 \mathrm{H}_6

View answer and explanation

Correct option: C

The correct answer is C (6) because in diborane (B2H6), the four terminal hydrogen atoms and the two boron atoms lie in one plane.

32 Easy

32 of 52

Understanding +4 | -1

Maximum

P\pi - P\pi

back bonding exists in

View answer and explanation

Correct option: D

B{F_3}

Option D (

B{F_3}

) is correct because Fluorine has the highest tendency to back bond due to its small size and high electronegativity, leading to maximum

P\pi - P\pi

back bonding.

33 Easy

33 of 52

Understanding +4 | -1

The stability

\mathrm{of}\,\mathrm{ + }\,\mathrm{1}

oxidation state among

Al,\,Ga, In \,\&\, TI

increases in the sequence:

View answer and explanation

Correct option: D

Al\, < \,Ga\, < \,In < \,TI

Option D (

Al\,<\,Ga\,<\,In <\,TI

) is correct because the inert pair effect becomes more prominent down the group, stabilizing the +1 oxidation state for heavier elements like Thallium.

34 Easy

34 of 52

Remembering +4 | -1

Which is used as mordant?

View answer and explanation

Correct option: C

Alum

Option C is correct because Alum is commonly used as a mordant in dyeing processes to fix the dye to the fabric.

35 Easy

35 of 52

Analyzing +4 | -1

Least basic among the following is

View answer and explanation

Correct option: C

B{\left( {OH} \right)_3}

Option C (

B{\left( {OH} \right)_3}

) is correct because boric acid is a weak Lewis acid, while the others are amphoteric or basic hydroxides.

36 Easy

36 of 52

Understanding +4 | -1

The order of Lewis acid nature

View answer and explanation

Correct option: B

B{F_3} < BC{l_3} < BB{r_3} < B{I_3}

Option B (

B{F_3} < BC{l_3} < BB{r_3} < B{I_3}

) is correct because the Lewis acidity increases down the group due to increasing bond length and decreasing π-backbonding.

37 Easy

37 of 52

Understanding +4 | -1

The correct order of atomic radii in group

\mathrm{13}

elements is

View answer and explanation

Correct option: A

\mathrm{B}\,\,\mathrm{ < }\,\,\mathrm{Ga}\,\,\mathrm{ < }\,\,\mathrm{Al}\,\,\mathrm{ < }\,\,\mathrm{In}\,\,\mathrm{ < }\,\,\mathrm{Tl}

Option A (

\mathrm{B}\,\mathrm{ < }\,\mathrm{Ga}\,\mathrm{ < }\,\mathrm{Al}\,\mathrm{ < }\,\mathrm{In}\,\mathrm{ < }\,\mathrm{Tl}

) is correct because the atomic radius generally increases down the group, but Gallium is smaller than Aluminium due to the d-block contraction.

38 Easy

38 of 52

Analyzing +4 | -1

Assertion: Boron is a nonmetal, whereas the other group of 13 elements are metals.

Reason: Boron has a smaller atomic radius than the other group of 13 elements.

View answer and explanation

Correct option: A

Both Assertion and Reason are true and Reason is the correct explanation for Assertion

Option A (Both Assertion and Reason are true and Reason is the correct explanation for Assertion) is correct because boron's smaller size leads to higher electronegativity and nonmetallic character compared to other group 13 elements.

39 Easy

39 of 52

Understanding +4 | -1

B{F_3}

on hydrolysis forms

View answer and explanation

Correct option: C

Both (1) and (2)

Option C (Both (1) and (2)) is correct because

BF_3

on hydrolysis forms both boric acid (

H_3BO_3

) and tetrafluoroboric acid (

HBF_4

40 Easy

40 of 52

Understanding +4 | -1

Which one of the following elements of unable to form

\mathrm{MF}_\mathrm{6}^{\mathrm{3 - }}

ion ?

View answer and explanation

Correct option: C

\mathrm{B}

Option C (B) is correct because Boron does not have d-orbitals to expand its coordination number to 6, and thus cannot form

\mathrm{MF}_\mathrm{6}^{\mathrm{3 - }}

ion.

41 Easy

41 of 52

Understanding +4 | -1

A mixture of boric acid with ethyl alcohol burns with green edged flame due to the formation of

View answer and explanation

Correct option: B

Ethyl borate

Option B (Ethyl borate) is correct because the green edged flame is due to the formation of volatile ethyl borate.

42 Easy

42 of 52

Application +4 | -1

A metal "

\mathrm{M}

" forms

\mathrm{M}_{2} \mathrm{O}_{3}

type oxide and

M N

type nitride. The atomic number of the metal could be

View answer and explanation

Correct option: C

Option C (13) is correct because an element with atomic number 13 is Aluminum (Al), which forms

Al_2O_3

oxide and

AlN

nitride.

43 Easy

43 of 52

Remembering +4 | -1

Thermite a mixture used for welding is:

View answer and explanation

Correct option: B

Ferric oxide and aluminium powder

Option B is correct because Thermite is a mixture of ferric oxide and aluminum powder, which reacts exothermically to produce molten iron for welding.

44 Easy

44 of 52

Remembering +4 | -1

When orthoboric acid

\left( {{\mathrm{H}_3}\mathrm{B}{\mathrm{O}_3}} \right)

is heated the residue left is:

View answer and explanation

Correct option: C

Boric anhydride

Option C (Boric anhydride) is correct because when orthoboric acid is heated strongly, it loses water molecules to form metaboric acid and finally boric anhydride (

B_2O_3

45 Easy

45 of 52

Remembering +4 | -1

Borax bead test is used to identify the Meta borates of transition metals. It is based on

View answer and explanation

Correct option: A

These Meta borates have characteristic colours

The correct answer is A (These Meta borates have characteristic colours) because the borax bead test relies on the characteristic colors of the metal metaborates formed.

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46 Easy

46 of 52

Understanding +4 | -1

Boric acid polymerises due to

View answer and explanation

Correct option: A

The presence of hydrogen bonding

Option A (The presence of hydrogen bonding) is correct because boric acid polymerizes through hydrogen bonding between the

OH

groups of different

H_3BO_3

molecules.

47 Easy

47 of 52

Understanding +4 | -1

Which one of the following elements is unable to form

MF_6^{3 - }

ion

View answer and explanation

Correct option: C

B

Option C (

B

) is correct because Boron does not have d-orbitals available to expand its coordination number to 6 and form the

MF_6^{3 - }

ion.

48 Easy

48 of 52

Remembering +4 | -1

Eka aluminium is:

View answer and explanation

Correct option: A

Gallium

Option A (Gallium) is correct because Mendeleev predicted the existence of Gallium and called it Eka-aluminum.

49 Easy

49 of 52

Understanding +4 | -1

The correct Lewis acid order for boron halides is:

View answer and explanation

Correct option: C

\mathrm{B}{\mathrm{I}_3} > \mathrm{BB}{\mathrm{r}_3} > \mathrm{BC}{\mathrm{l}_3} > \mathrm{B}{\mathrm{F}_3}

Option C (

\mathrm{B}{\mathrm{I}_3} > \mathrm{BB}{\mathrm{r}_3} > \mathrm{BC}{\mathrm{l}_3} > \mathrm{B}{\mathrm{F}_3}

) is correct because the Lewis acidity increases as the backbonding from the halide to boron decreases, which is related to the size and electronegativity of the halide.

50 Easy

50 of 52

Analyzing +4 | -1

Assertion: Boron exhibits a wide range of oxidation states, including negative and fractional oxidation states.

Reason: The small size of the boron atom and its high electronegativity make it easy to form a variety of covalent bonds and oxidation states.

View answer and explanation

Correct option: A

Both Assertion and Reason are true and Reason is the correct explanation for Assertion

The correct answer is A (Both Assertion and Reason are true and Reason is the correct explanation for Assertion) because boron's small size and high electronegativity allow for back bonding, influencing its oxidation states.

51 Easy

51 of 52

Understanding +4 | -1

An aqueous solution of potash alum gives

View answer and explanation

Correct option: D

Three types of ions

Option D (Three types of ions) is correct because potash alum (

KAl(SO_4)_2 \cdot 12H_2O

) dissociates into

K^+

Al^{3+}

, and

SO_4^{2-}

ions in aqueous solution.

52 Easy

52 of 52

Analyzing +4 | -1

Given below are two statements:

Statement I : Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement II: The green colour observed is due to the formation of copper(I) metaborate.
In the light of the above statements, choose the most appropriate answer from the options given below.

View answer and explanation

Correct option: C

Both Statement I and Statement II are false

The correct answer is C (Both Statement I and Statement II are false) because in a luminous flame, the borax bead with cupric sulfate turns blue due to copper(II) metaborate, not green, and it's copper(II), not copper(I).

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