${\rm{N}}{{\rm{a}}_2}{{\rm{B}}_4}{{\rm{O}}_7}.10{{\rm{H}}_2}{\rm{O}}$

${\rm{N}}{{\rm{a}}_2}{\rm{C}}{{\rm{O}}_3}.10{{\rm{H}}_2}{\rm{O}}$

In the reaction ${{\rm{B}}_2}{{\rm{O}}_3} + {\rm{C}} + {\rm{C}}{{\rm{l}}_2} \to A + {\rm{CO}}.$ The A is

${{\rm{B}}_2}{\rm{C}}{{\rm{l}}_2}$

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NEET • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)

13 th group elements (p-block) practice · Mixed difficulty

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Showing 1-30 of 121 questions

1 Medium

1 of 121

Remembering +4 | -1

The hardest compound of boron is:

View answer and explanation

Correct option: C

Boron carbide

Option C (Boron carbide) is correct because Boron carbide (

B_4C

) is known to be one of the hardest materials, exhibiting extreme hardness and wear resistance.

2 Medium

2 of 121

Understanding +4 | -1

Which does not show inert pair effect?

View answer and explanation

Correct option: A

\mathrm{Al}

Option A (

\mathrm{Al}

) is correct because Aluminium does not exhibit the inert pair effect, unlike Sn, Pb, and Tl.

3 Easy

3 of 121

Understanding +4 | -1

Which one of the following does not exist in the free state

View answer and explanation

Correct option: D

B{H_3}

Option D (

B{H_3}

) is correct because Borane (

B{H_3}

) exists as a dimer (

B_2H_6

) due to its electron deficiency.

4 Medium

4 of 121

Application +4 | -1

On strong heating of

{H}_3 {PO}_4

and

{H}_3 {BO}_3

, sum of oxidation number of

{P}\, \& {~B}

in the final product obtained is

View answer and explanation

Correct option: A

The correct answer is A (8) because after strong heating, H3PO4 forms metaphosphoric acid (HPO3) and H3BO3 forms B2O3. The oxidation states of P and B are +5 and +3 respectively, summing to 8.

5 Medium

5 of 121

Analyzing +4 | -1

Compound ‘X’ reacts with

N{H_3}

to 473 K give another compound ‘Y’. X can be prepared by heating

B{F_3}

with sodium hydride. The compound ‘Y’ is represented by the formula

View answer and explanation

Correct option: A

{B_3}{N_3}{H_6}

Option A (

{B_3}{N_3}{H_6}

) is correct because compound X is diborane (

B_2H_6

), which reacts with

NH_3

to give borazine (

{B_3}{N_3}{H_6}

6 Medium

6 of 121

Analyzing +4 | -1

Assertion: Electronegativity first increases from B to Al and then decreases from Al to

\mathrm{TI}

.

Reason: Due to poor shielding by inner

\mathrm{d}

and

\mathrm{f}

electrons.

View answer and explanation

Correct option: D

Assertion is false, but Reason is true

Option D (Assertion is false, but Reason is true) is correct because electronegativity generally decreases down the group due to increasing atomic size and shielding, and the poor shielding by inner d and f electrons is a valid reason for irregularities.

7 Easy

7 of 121

Remembering +4 | -1

Tincal is

View answer and explanation

Correct option: C

\mathrm{N}{\mathrm{a}_2}{\mathrm{B}_4}{\mathrm{O}_7}.10{\mathrm{H}_2}\mathrm{O}

Option C (

\mathrm{N}{\mathrm{a}_2}{\mathrm{B}_4}{\mathrm{O}_7}.10{\mathrm{H}_2}\mathrm{O}

) is correct because Tincal is the mineral name for hydrated sodium tetraborate, which is borax.

8 Medium

8 of 121

Understanding +4 | -1

+1 oxidation state is most stable for

View answer and explanation

Correct option: A

Option A (Tl) is correct because thallium (Tl) exhibits a stable +1 oxidation state due to the inert pair effect, making it the most stable among the given options.

9 Medium

9 of 121

Application +4 | -1

B—F bond order in

\mathrm{B}{\mathrm{F}_3}

is:

View answer and explanation

Correct option: D

4/3

Option D (

4/3

) is correct because the B-F bond in

BF_3

has resonance structures, resulting in a bond order of 4/3.

10 Hard

10 of 121

Understanding +4 | -1

Which of the following elements does not exist in aqueous medium, as species like tetrahedral

\left[M(\mathrm{OH})_4\right]^{-}

and octahedral

\left[M\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}

View answer and explanation

Correct option: A

Boron

Option A (Boron) is correct because boron, due to its small size and high charge density, does not form stable octahedral complexes in aqueous solution.

11 Medium

11 of 121

Understanding +4 | -1

Aluminium does not react with:

View answer and explanation

Correct option: D

\mathrm{HN}{\mathrm{O}_3}

Option D (

\mathrm{HN}{\mathrm{O}_3}

) is correct because aluminium becomes passive due to the formation of a protective oxide layer with nitric acid.

12 Easy

12 of 121

Analyzing +4 | -1

Incorrect statement in the following is

View answer and explanation

Correct option: D

Oxides of boron are amphoteric in nature

Option D (Oxides of boron are amphoteric in nature) is correct because boron oxides are acidic, not amphoteric.

13 Medium

13 of 121

Remembering +4 | -1

{13^{th}}

group element with least melting point is:

View answer and explanation

Correct option: A

Option A (Ga) is correct because Gallium has an unusually low melting point (29.76 °C) compared to other elements in Group 13.

14 Easy

14 of 121

Understanding +4 | -1

The chloride that cannot be hydrolyzed is

View answer and explanation

Correct option: B

CC{l_4}

Option B (

CC{l_4}

) is correct because carbon tetrachloride (

CC{l_4}

) does not have any d-orbitals to accept electrons from water, making it unable to be hydrolyzed.

15 Easy

15 of 121

Analyzing +4 | -1

Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that

\mathrm{B}{\mathrm{F}_3}

has no dipole moment but

\mathrm{P}{\mathrm{F}_3}

has?

View answer and explanation

Correct option: D

The

\mathrm{B}{\mathrm{F}_3}

molecule must be planar triangular

Option D (The

\mathrm{B}{\mathrm{F}_3}

molecule must be planar triangular) is correct because the absence of a dipole moment in

BF_3

indicates a symmetrical, planar triangular structure, while

PF_3

has a dipole moment due to its pyramidal shape.

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16 Easy

16 of 121

Application +4 | -1

An element

'X'

which occurs in the first short period has an outer electronic structure

{s^2}{p^1}

. What is the formula and acid-base character of its oxides?

View answer and explanation

Correct option: C

{X_2}{\mathrm{O}_3}

, acidic

Option C (

{X_2}{\mathrm{O}_3}

, acidic) is correct because the element X is Boron (B), and its oxide,

B_2O_3

, is acidic.

17 Medium

17 of 121

Remembering +4 | -1

Borax bead test is responded by:

View answer and explanation

Correct option: D

Metal which forms coloured metaborates

Option D (Metal which forms coloured metaborates) is correct because the borax bead test relies on the formation of colored metal metaborates to identify the metal.

18 Easy

18 of 121

Analyzing +4 | -1

Which of the following is not a protonic and?

View answer and explanation

Correct option: A

\mathrm{B}(\mathrm{OH})_3

Option A (

\mathrm{B}(\mathrm{OH})_3

) is correct because boric acid,

\mathrm{B}(\mathrm{OH})_3

, acts as a Lewis acid by accepting a hydroxide ion, not by donating a proton, thus it is not a protonic acid.

19 Medium

19 of 121

Understanding +4 | -1

Amorphous boron on burning in air forms:

View answer and explanation

Correct option: B

Mixture of

{\mathrm{B}_2}{\mathrm{O}_3}

and BN

Option B (Mixture of

B_2O_3

and BN) is correct because amorphous boron reacts with both oxygen and nitrogen in the air upon burning.

20 Medium

20 of 121

Analyzing +4 | -1

Which of the following statement(s) is/are not correct ?

(i) Valence shell electronic configuration of p-block elements is

{ns}^2 {np}^{1-6}

(ii) Non metals and metalloids exist only in the p-block of the periodic table.

(iii) In boron, carbon and nitrogen families the group oxidation state is the most stable state for the lighter elements in the group.

(iv) For heavier elements in each group oxidation state two unit less than the group oxidation state becomes more stable due to inert pair effect

View answer and explanation

Correct option: D

All given statements are correct

Option D is correct because all the given statements are correct regarding the p-block elements and their properties.

21 Easy

21 of 121

Remembering +4 | -1

Which of the following is called inorganic benzene

View answer and explanation

Correct option: A

Borazine

Option A (Borazine) is correct because borazine (

B_3N_3H_6

) has a structure similar to benzene and is thus called inorganic benzene.

22 Hard

22 of 121

Application +4 | -1

The number of neutrons present in the more abundant isotope of boron is

x.

Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is

y.

The value of

x+y

View answer and explanation

Correct option: D

Option D (9) is correct because the more abundant isotope of boron is

^{11}B

(x=6), and boron reacts with air to form

B_2O_3

where boron's oxidation state is +3 (y=3), so x+y = 6+3 = 9.

23 Medium

23 of 121

Remembering +4 | -1

Boron was isolated by:

View answer and explanation

Correct option: B

Davy

Option B (Davy) is correct because Sir Humphry Davy is credited with isolating Boron.

24 Medium

24 of 121

Understanding +4 | -1

Boric acid is an acid because its molecule

View answer and explanation

Correct option: D

Accepts

O{H^ - }

from water releasing proton

Option D (Accepts

OH^-

from water releasing proton) is correct because boric acid acts as a Lewis acid, accepting

OH^-

ions from water and releasing protons.

25 Easy

25 of 121

Analyzing +4 | -1

Which species does not exist?

View answer and explanation

Correct option: A

{\left[ {\mathrm{B}{\mathrm{F}_6}} \right]^{3 - }}

Option A (

{\left[ {\mathrm{B}{\mathrm{F}_6}} \right]^{3 - }}

) is correct because boron, due to its small size and lack of d-orbitals, cannot expand its coordination number to six.

26 Medium

26 of 121

Application +4 | -1

In the reaction

{\mathrm{B}_2}{\mathrm{O}_3} + \mathrm{C} + \mathrm{C}{\mathrm{l}_2} \to A + \mathrm{CO}.

The A is

View answer and explanation

Correct option: B

\mathrm{BC}{\mathrm{l}_3}

Option B (

\mathrm{BCl}_3

) is correct because the reaction of

B_2O_3

with carbon and chlorine produces boron trichloride and carbon monoxide.

27 Easy

27 of 121

Remembering +4 | -1

Colemanite is a mineral of:

View answer and explanation

Correct option: B

Option B (B) is correct because Colemanite is a hydrated calcium borate mineral, hence a mineral of Boron.

28 Medium

28 of 121

Understanding +4 | -1

Thallium shows different oxidation states because:

View answer and explanation

Correct option: B

Of inert pair of electron

Option B (Of inert pair of electron) is correct because thallium exhibits different oxidation states due to the inert pair effect.

29 Easy

29 of 121

Understanding +4 | -1

Diborane readily reacts with water forming –

View answer and explanation

Correct option: C

Boric acid and

{H_2}

Option C (Boric acid and

{H_2}

) is correct because diborane reacts with water to form boric acid and hydrogen gas.

30 Medium

30 of 121

Analyzing +4 | -1

The incorrect statement reading ‘x’ in the reaction is

B{F_3} + LiAl{H_4}\xrightarrow{{\mathrm{Ether}}}\left( x \right) + LiF + Al{F_3}

View answer and explanation

Correct option: D

Structure of ‘x’ is similar to

{C_2}{H_6}

The correct answer is D (Structure of ‘x’ is similar to

{C_2}{H_6}

) because the product 'x' is diborane (B2H6), which has a different structure than ethane (C2H6) due to its electron-deficient nature.

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