In the reaction ${{\rm{B}}_2}{{\rm{O}}_3} + {\rm{C}} + {\rm{C}}{{\rm{l}}_2} \to A + {\rm{CO}}.$ The A is

${{\rm{B}}_2}{\rm{C}}{{\rm{l}}_2}$

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NEET • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)

13 th group elements (p-block) practice · Medium

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1 Medium

1 of 59

Remembering +4 | -1

The hardest compound of boron is:

View answer and explanation

Correct option: C

Boron carbide

Option C (Boron carbide) is correct because Boron carbide (

B_4C

) is known to be one of the hardest materials, exhibiting extreme hardness and wear resistance.

2 Medium

2 of 59

Understanding +4 | -1

Which does not show inert pair effect?

View answer and explanation

Correct option: A

\mathrm{Al}

Option A (

\mathrm{Al}

) is correct because Aluminium does not exhibit the inert pair effect, unlike Sn, Pb, and Tl.

3 Medium

3 of 59

Application +4 | -1

On strong heating of

{H}_3 {PO}_4

and

{H}_3 {BO}_3

, sum of oxidation number of

{P}\, \& {~B}

in the final product obtained is

View answer and explanation

Correct option: A

The correct answer is A (8) because after strong heating, H3PO4 forms metaphosphoric acid (HPO3) and H3BO3 forms B2O3. The oxidation states of P and B are +5 and +3 respectively, summing to 8.

4 Medium

4 of 59

Analyzing +4 | -1

Compound ‘X’ reacts with

N{H_3}

to 473 K give another compound ‘Y’. X can be prepared by heating

B{F_3}

with sodium hydride. The compound ‘Y’ is represented by the formula

View answer and explanation

Correct option: A

{B_3}{N_3}{H_6}

Option A (

{B_3}{N_3}{H_6}

) is correct because compound X is diborane (

B_2H_6

), which reacts with

NH_3

to give borazine (

{B_3}{N_3}{H_6}

5 Medium

5 of 59

Analyzing +4 | -1

Assertion: Electronegativity first increases from B to Al and then decreases from Al to

\mathrm{TI}

.

Reason: Due to poor shielding by inner

\mathrm{d}

and

\mathrm{f}

electrons.

View answer and explanation

Correct option: D

Assertion is false, but Reason is true

Option D (Assertion is false, but Reason is true) is correct because electronegativity generally decreases down the group due to increasing atomic size and shielding, and the poor shielding by inner d and f electrons is a valid reason for irregularities.

6 Medium

6 of 59

Understanding +4 | -1

+1 oxidation state is most stable for

View answer and explanation

Correct option: A

Option A (Tl) is correct because thallium (Tl) exhibits a stable +1 oxidation state due to the inert pair effect, making it the most stable among the given options.

7 Medium

7 of 59

Application +4 | -1

B—F bond order in

\mathrm{B}{\mathrm{F}_3}

is:

View answer and explanation

Correct option: D

4/3

Option D (

4/3

) is correct because the B-F bond in

BF_3

has resonance structures, resulting in a bond order of 4/3.

8 Medium

8 of 59

Understanding +4 | -1

Aluminium does not react with:

View answer and explanation

Correct option: D

\mathrm{HN}{\mathrm{O}_3}

Option D (

\mathrm{HN}{\mathrm{O}_3}

) is correct because aluminium becomes passive due to the formation of a protective oxide layer with nitric acid.

9 Medium

9 of 59

Remembering +4 | -1

{13^{th}}

group element with least melting point is:

View answer and explanation

Correct option: A

Option A (Ga) is correct because Gallium has an unusually low melting point (29.76 °C) compared to other elements in Group 13.

10 Medium

10 of 59

Remembering +4 | -1

Borax bead test is responded by:

View answer and explanation

Correct option: D

Metal which forms coloured metaborates

Option D (Metal which forms coloured metaborates) is correct because the borax bead test relies on the formation of colored metal metaborates to identify the metal.

11 Medium

11 of 59

Understanding +4 | -1

Amorphous boron on burning in air forms:

View answer and explanation

Correct option: B

Mixture of

{\mathrm{B}_2}{\mathrm{O}_3}

and BN

Option B (Mixture of

B_2O_3

and BN) is correct because amorphous boron reacts with both oxygen and nitrogen in the air upon burning.

12 Medium

12 of 59

Analyzing +4 | -1

Which of the following statement(s) is/are not correct ?

(i) Valence shell electronic configuration of p-block elements is

{ns}^2 {np}^{1-6}

(ii) Non metals and metalloids exist only in the p-block of the periodic table.

(iii) In boron, carbon and nitrogen families the group oxidation state is the most stable state for the lighter elements in the group.

(iv) For heavier elements in each group oxidation state two unit less than the group oxidation state becomes more stable due to inert pair effect

View answer and explanation

Correct option: D

All given statements are correct

Option D is correct because all the given statements are correct regarding the p-block elements and their properties.

13 Medium

13 of 59

Remembering +4 | -1

Boron was isolated by:

View answer and explanation

Correct option: B

Davy

Option B (Davy) is correct because Sir Humphry Davy is credited with isolating Boron.

14 Medium

14 of 59

Understanding +4 | -1

Boric acid is an acid because its molecule

View answer and explanation

Correct option: D

Accepts

O{H^ - }

from water releasing proton

Option D (Accepts

OH^-

from water releasing proton) is correct because boric acid acts as a Lewis acid, accepting

OH^-

ions from water and releasing protons.

15 Medium

15 of 59

Application +4 | -1

In the reaction

{\mathrm{B}_2}{\mathrm{O}_3} + \mathrm{C} + \mathrm{C}{\mathrm{l}_2} \to A + \mathrm{CO}.

The A is

View answer and explanation

Correct option: B

\mathrm{BC}{\mathrm{l}_3}

Option B (

\mathrm{BCl}_3

) is correct because the reaction of

B_2O_3

with carbon and chlorine produces boron trichloride and carbon monoxide.

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16 Medium

16 of 59

Understanding +4 | -1

Thallium shows different oxidation states because:

View answer and explanation

Correct option: B

Of inert pair of electron

Option B (Of inert pair of electron) is correct because thallium exhibits different oxidation states due to the inert pair effect.

17 Medium

17 of 59

Analyzing +4 | -1

The incorrect statement reading ‘x’ in the reaction is

B{F_3} + LiAl{H_4}\xrightarrow{{\mathrm{Ether}}}\left( x \right) + LiF + Al{F_3}

View answer and explanation

Correct option: D

Structure of ‘x’ is similar to

{C_2}{H_6}

The correct answer is D (Structure of ‘x’ is similar to

{C_2}{H_6}

) because the product 'x' is diborane (B2H6), which has a different structure than ethane (C2H6) due to its electron-deficient nature.

18 Medium

18 of 59

Application +4 | -1

Colemanite is an important mineral of boron. It is represented

\mathrm{Ca}_2 \mathrm{~B}_x \mathrm{O}_{11} \cdot 6 \mathrm{H}_2 \mathrm{O}

. What is the value of

x

View answer and explanation

Correct option: A

Option A (6) is correct because the formula of Colemanite is

Ca_2B_6O_{11} \cdot 5H_2O

, so x = 6.

19 Medium

19 of 59

Analyzing +4 | -1

\mathrm{BX}_3+\mathrm{NH}_3 \stackrel{\text { R.T. }}{\longrightarrow} \mathrm{BX}_3 \cdot \mathrm{NH}_3+

Heat of adduct formation

(\Delta \mathrm{H}).

The numerical value of

\Delta \mathrm{H}

is found to be maximum for:

View answer and explanation

Correct option: D

\mathrm{BI}_3

The correct answer is D (BI3) because BI3 has the least pi-backbonding, leading to the strongest Lewis acid character and thus the maximum heat of adduct formation.

20 Medium

20 of 59

Analyzing +4 | -1

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) In

Tl{I_3}

, isomorphous to

Cs{I_3}

, the metal is present in + 1 oxidation state.
Reason (R)

Tl

metal has fourteen

f -

electrons in the electronic configuration.
In the light of the above statements, choose the most appropriate answer from the options given below.

View answer and explanation

Correct option: B

Both A and R are correct and R is the correct explanation of A.

Option A is correct because Tl in TlI3 exists as Tl+ and I3- due to the inert pair effect, and the presence of 14 f-electrons contributes to this effect.

21 Medium

21 of 59

Analyzing +4 | -1

Assertion (A):

\mathrm{HBF}_4

is a very strong acid.

Reason

(\mathbf{R}): \mathrm{B}(\mathrm{OH})_3

behaves as an acid in the following reaction :

\mathrm{B}(\mathrm{OH})_3+4 \mathrm{HF} \longrightarrow \mathrm{H}_3 \mathrm{O}^{+}+\left[\mathrm{BF}_4 \right]^{-}+2 \mathrm{H}_2 \mathrm{O}.

View answer and explanation

Correct option: C

\mathbf{A}

is true but

\mathbf{R}

is false.

The correct answer is C (A is true but R is false) because HBF4 is a strong acid, but the reaction provided demonstrates B(OH)3 acting as a Lewis acid, not a Bronsted-Lowry acid.

22 Medium

22 of 59

Understanding +4 | -1

Which is electron deficient compound?

View answer and explanation

Correct option: B

{\mathrm{B}_2}{\mathrm{H}_6}

Option B (

{\mathrm{B}_2}{\mathrm{H}_6}

) is correct because Diborane (

{\mathrm{B}_2}{\mathrm{H}_6}

) is an electron-deficient compound with bridging hydrogen atoms.

23 Medium

23 of 59

Analyzing +4 | -1

Which of the following statement(s) is/are incorrect ?

(i) Trichlorides on hydrolysis in water form tetrahedral

\left[\mathrm{M}(\mathrm{OH})_4\right]^{-}

species.

(ii) Hybridisation state of metal in tetrahedral species is

\mathrm{sp}^3

.

(iii) Aluminium chloride in acidified aqueous solution forms

\left[\mathrm{Al}(\mathrm{OH})_4\right]^{-}

ion.

View answer and explanation

Correct option: C

(iii) only

Option C ((iii) only) is correct because Aluminium chloride in acidified aqueous solution forms

\left[\mathrm{Al}(\mathrm{H}_2\mathrm{O})_6\right]^{3+}

ion, not

\left[\mathrm{Al}(\mathrm{OH})_4\right]^{-}

ion.

24 Medium

24 of 59

Remembering +4 | -1

The 13th group element which has the least melting point is

View answer and explanation

Correct option: C

Option C is correct because Gallium (Ga) has the lowest melting point among the group 13 elements listed.

25 Medium

25 of 59

Analyzing +4 | -1

Which of the following ions do not exist?

\begin{array}{cccccccccccccccccccc} {{\text{i}}.\,\,\,{B^{3 + }}}&{{\text{ii}}.\,\,\,A{l^{ + 3}}}&{{\text{iii}}.\,\,\,G{a^{3 + }}}&{{\text{iv}}.\,\,\,T{l^{3 + }}} \end{array}

View answer and explanation

Correct option: D

i,iv

Option D (i,iv) is correct because

B^{3+}

is highly unlikely due to the high ionization energy required to remove 3 electrons from Boron, and

Tl^{3+}

is less stable than

Tl^+

due to the inert pair effect.

26 Medium

26 of 59

Remembering +4 | -1

Boric acid is prepared from borax by the action of:

View answer and explanation

Correct option: A

Hydrochloric acid

Option A (Hydrochloric acid) is correct because boric acid is prepared from borax by reacting it with hydrochloric acid.

27 Medium

27 of 59

Remembering +4 | -1

In Gold Schmidt reaction, certain metallic oxides are reduced to the metallic state by-heating with:

View answer and explanation

Correct option: B

Metallic aluminium

Option B (Metallic aluminium) is correct because in the Goldschmidt reaction, metallic oxides are reduced by heating with metallic aluminum.

28 Medium

28 of 59

Analyzing +4 | -1

Assertion (A) :

{B}_2 {Cl}_4, {GaCl}_2, {GaS}

are diamagnetic.

Reason (R) : They show +2 oxidation state.

View answer and explanation

Correct option: B

Both

\mathbf{A}

and

\mathbf{R}

are true but

\mathbf{R}

is not the correct explanation of

\mathbf{A}

Option B is correct because both the assertion and the reason are true, but the reason is not the correct explanation for the assertion. The diamagnetic nature arises from the pairing of electrons, not solely the +2 oxidation state.

29 Medium

29 of 59

Remembering +4 | -1

Alum is not used:

View answer and explanation

Correct option: B

As an insecticide

Option B (As an insecticide) is correct because alum is not used as an insecticide; it is used as a mordant, in water purification, and in leather tanning.

30 Medium

30 of 59

Understanding +4 | -1

Boron nitride on reacting with caustic alkali gives:

View answer and explanation

Correct option: A

\mathrm{N}{\mathrm{H}_3}

Option A (

\mathrm{N}{\mathrm{H}_3}

) is correct because boron nitride reacts with caustic alkali to produce ammonia.

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