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JEE CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

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Understanding +4 | -1

Due to inert pair effect in 13th group

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Correct option: B

Tl shows +1 oxidation state

Option A (

{E}_{({H})}>{E}_{({Li})}>{E}_{({Na})}>{E}_{({K})}

) is correct because ionization potential decreases down the group due to increasing atomic size and decreasing effective nuclear charge, and hydrogen has the highest ionization potential.

More Questions from 13 TH GROUP ELEMENTS (P-BLOCK)

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Duralumin is an alloy of: Assertion (A) : In aqueous solution

{AlCl}_3

forms dimer

{Al}_2 {Cl}_6

.
Reason (R) : The high enthalpy of hydration is sufficient to break the covalent dimer into

\left[M\left({H}_2 {O}\right)_6\right]^{3+}

and

{Cl}^{-}

ions.

{Al}_2\left({SO}_4\right)_3

is used in the following but not Which metal will give blue colour metaborate in borax bead test? Consider the following statements about boric acid.

I. It is a weak monobasic acid

II. It is not a protonic acid

III. It acts as a lewis acid

The correct statement(s) among the following is/are The correct statements from the following are:

(A) The decreasing order of atomic radii of group 13 elements is

{Tl}>{In}>{Ga}>{Al}>{B}

(B) Down the group 13 electronegativity decreases from top to bottom

(C)

{Al}

dissolves in dil.

{HCl}

and liberate

{H}_2

but conc.

{HNO}_3

renders

{Al}

passive by forming a protective oxide layer on the surface

(D) All elements of group 13 exhibits highly stable +1 oxidation state

(E) Hybridisation of

{Al}

\left[{Al}\left({H}_2{O}\right)_6\right]^{3+}

ion is

\mathrm{sp}^3 \mathrm{d}^2

Choose the correct answer from the options given below: