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NEET • BIOLOGY • PRINCIPLE OF INHERITANCE AND VARIATION

Principle of inheritance and variation practice · Easy

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61 Easy
61 of 111
Understanding +4 | -1
Linkage groups are always present on the
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Correct option: A
Homologous chromosomes
Option A (Homologous chromosomes) is correct because linkage groups are formed by genes present on the same homologous chromosome.
62 Easy
62 of 111
Understanding +4 | -1
When two genetic loci produce identical phenotypes in cis and trans position, they are considered to be
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Correct option: A
Pseudoalleles
Option A (Pseudoalleles) is correct because pseudoalleles produce identical phenotypes in both cis and trans configurations.
63 Easy
63 of 111
Application +4 | -1
A normal woman whose father was colour blind is married to a normal man. The sons would be
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Correct option: B
50% color blind
The correct answer is B (50% color blind) because the woman is a carrier, and the man is normal, resulting in a 50% chance of colorblind sons.
64 Easy
64 of 111
Application +4 | -1
Mahesh (who is colourblind) and Soni (who is not colourblind) have a daughter Alia. Rishi (who is not
colourblind) and Neetu (who is a carrier) have a son Ranbeer. Alia and Ranbeer get married. What is the
probability that their daughter will be colorblind?
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Correct option: B
0.25
The correct answer is B (0.25) because the probability of their daughter being colorblind depends on Alia being a carrier and Ranbeer passing on the colorblind allele.
65 Easy
65 of 111
Remembering +4 | -1
Identify a Mendelian disorder from the following.
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Correct option: C
Phenylketonuria
Option B (One X-chromosome of mother) is correct because the mother must be a carrier (XhX) and passes on the Xh chromosome to half of her sons, making them haemophilic, and to half of her daughters, making them carriers.
66 Easy
66 of 111
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Linked gene are present on
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Correct option: A
Same chromosome
Option A (Same chromosome) is correct because linked genes, by definition, are located on the same chromosome.
67 Easy
67 of 111
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Mendel’s experimental material was
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Correct option: A
Pisum sativum
Option A is correct because Mendel conducted his famous genetics experiments using the garden pea, Pisum sativum.
68 Easy
68 of 111
Understanding +4 | -1
If a genetic disease is transferred from a phenotypically normal but carrier female to only some of
the male progeny, the disease is
View answer and explanation
Correct option: D
Sex-linked recessive
Option D (Sex-linked recessive) is correct because the disease is transferred from a carrier female (meaning she has one copy of the recessive allele) to only some of her male progeny, which is characteristic of X-linked recessive inheritance.
69 Easy
69 of 111
Understanding +4 | -1
When the number of recombinant progeny is usually less than the number expected in independent assortment it is called
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Correct option: B
Incomplete linkage
Option B (Incomplete linkage) is correct because incomplete linkage occurs when genes on the same chromosome do not always segregate together due to crossing over, resulting in fewer recombinant progeny than expected with independent assortment.
70 Easy
70 of 111
Remembering +4 | -1
Which one of the following traits of garden pea studied by Mendel was a recessive feature?
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Correct option: D
Green seed colour
Option D ( Green seed colour) is correct because green seed color is a recessive trait in pea plants, while the other options (green pod color, round seed shape, and axial flower position) are dominant traits.
71 Easy
71 of 111
Understanding +4 | -1
Husband has blood group-A and wife has blood group-B. What is the blood group of children?
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Correct option: D
A, B, AB and O
Option D (A, B, AB and O) is correct because the offspring can inherit different combinations of alleles from the parents, resulting in all four blood types.
72 Easy
72 of 111
Remembering +4 | -1
In human male a spermatogonium contains ____________ chromosomes
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Correct option: A
Both X and Y
Option A (Both X and Y) is correct because a spermatogonium in a human male contains both X and Y chromosomes.
73 Easy
73 of 111
Understanding +4 | -1
Genes for colour blindness is carried by
I. Abnormal development II. Father
III. Mother IV. Autosomes
View answer and explanation
Correct option: B
II and III
Option B (II and III) is correct because genes for color blindness are carried on the X chromosome, which is inherited from the mother and can be passed on by the father.
74 Easy
74 of 111
Understanding +4 | -1
The genotype of a plant showing the dominant phenotype can by
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Correct option: A
Test cross
Option A (Test cross) is correct because a test cross involves crossing an individual with a dominant phenotype but unknown genotype with a homozygous recessive individual to determine the unknown genotype.
75 Easy
75 of 111
Remembering +4 | -1
Red green colour blindness appears due to
View answer and explanation
Correct option: B
Inheritence through X chromosome
Option B (Inheritence through X chromosome) is correct because red-green color blindness is an X-linked recessive trait.
76 Easy
76 of 111
Remembering +4 | -1
The diagrammatic representation of the chromosomes of an individual is called
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Correct option: A
Idiogram
Option A (Idiogram) is correct because an idiogram is a diagrammatic representation of chromosomes, showing their relative sizes, centromere positions, and banding patterns.
77 Easy
77 of 111
Remembering +4 | -1
Linkage was first suggested by
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Correct option: A
Sutton and Boveri
Option A (Sutton and Boveri) is correct because they first suggested the concept of linkage by associating genes with chromosomes.
78 Easy
78 of 111
Remembering +4 | -1
External morphology or appearance or descriptive term of an genotype is called
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Correct option: B
Phenotype
Option B (Phenotype) is correct because phenotype refers to the observable characteristics of an organism resulting from the interaction of its genotype with the environment.
79 Easy
79 of 111
Remembering +4 | -1
Genetics is the branch of biology which deals with
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Correct option: C
Both (1) and 2)
Option C (Both (1) and 2)) is correct because genetics deals with both variation and inheritance of traits.
80 Easy
80 of 111
Remembering +4 | -1
The phenomenon in which a single gene can exhibit multiple phenotypic expression is called
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Correct option: C
Pleiotropy
Option C (Pleiotropy) is correct because pleiotropy is defined as a single gene exhibiting multiple phenotypic expressions.
81 Easy
81 of 111
Application +4 | -1
What are all the chances of colourblind daughters of a normal man marrying normal women whose father was colourblind?
View answer and explanation
Correct option: D
50% sons are colourblind and all daughters are phenotypically normal
The correct answer is D (50% sons are colourblind and all daughters are phenotypically normal) because the mother is a carrier, and the father is normal.
82 Easy
82 of 111
Understanding +4 | -1
I. Short statured with small round head
II. Furrowed tongue and partially opened mouth
III. Palm is broad with characteristic palm crease
IV. Slow physical, psycomotor and mental development
These are the characters of
View answer and explanation
Correct option: A
Down’s syndrome
Option A (Down’s syndrome) is correct because the listed characteristics are classic symptoms of Down syndrome.
83 Easy
83 of 111
Application +4 | -1
A gene locus has two alleles A, a. If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?
View answer and explanation
Correct option: C
0.16 (AA); 0.48 (Aa); 0.36 (aa)
Option C (0.16 (AA); 0.48 (Aa); 0.36 (aa)) is correct because it correctly applies the Hardy-Weinberg equilibrium to calculate the frequencies of homozygous dominant, heterozygous, and homozygous recessive individuals.
84 Easy
84 of 111
Understanding +4 | -1
Which of the following blood groups’ person can not donate blood to other?
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Correct option: A
AB blood group
Option A (AB blood group) is correct because individuals with AB blood group have both A and B antigens on their red blood cells and therefore cannot donate to individuals with A, B, or O blood groups.
85 Easy
85 of 111
Remembering +4 | -1
Chromosomes are made up of
View answer and explanation
Correct option: C
DNA and histone
Option C (DNA and histone) is correct because chromosomes are primarily composed of DNA tightly wound around histone proteins.
86 Easy
86 of 111
Understanding +4 | -1
In Mendel's experiment the study of inheritance of one gene (cross between tall and dwarf plant) in F2\mathrm{F}_2 generation showed :
View answer and explanation
Correct option: B
75%75 \% tall and 25%25 \% dwarf plants in F2\mathrm{F}_2 progeny
Option B (75%75 \% tall and 25%25 \% dwarf plants in F2\mathrm{F}_2 progeny) is correct because in a monohybrid cross with a tall (TT) and dwarf (tt) plant, the F2 generation shows a 3:1 phenotypic ratio, resulting in 75% tall and 25% dwarf plants.
87 Easy
87 of 111
Application +4 | -1
Total number of progeny of a dihybrid cross is 640 in F2F_2 generation. How many are recombinants:
View answer and explanation
Correct option: C
240
Option C (240) is correct because in a dihybrid cross, the recombinant phenotypes occur in 6/16 of the progeny. Therefore, with a total of 640 progeny, the number of recombinants is (6/16) * 640 = 240.
88 Easy
88 of 111
Understanding +4 | -1
A person is suffering from disease phenylketonuria, which is an autosomal recessive disease. Which of these is lacking in the person?
View answer and explanation
Correct option: B
Phenylalanine hydroxylase
Option B (Phenylalanine hydroxylase) is correct because phenylketonuria is caused by a deficiency in this enzyme, which is needed to convert phenylalanine to tyrosine.
89 Easy
89 of 111
Remembering +4 | -1
Frequency of recombination between gene pairs on same chromosome as a measure of the distance
between genes to map their position on chromosome, was used for the first time by
View answer and explanation
Correct option: A
Alfred Sturtevant
Option A (Alfred Sturtevant) is correct because Alfred Sturtevant was the first to use recombination frequencies to map gene positions on chromosomes.
90 Easy
90 of 111
Remembering +4 | -1
Human females have
View answer and explanation
Correct option: A
22 pairs of autosomes and one pair of sex chromosome
Option A (22 pairs of autosomes and one pair of sex chromosome) is correct because human females have 22 pairs of autosomes and one pair of sex chromosomes (XX).
Revision notes and key takeaways

Review PRINCIPLE OF INHERITANCE AND VARIATION in your textbook or class notes, then use this set to check your understanding.

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