Skip to main content
Back to WAVES

Your Progress

0 / 524 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • WAVES

Waves practice · Medium

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 511-524 of 524 questions
511 Medium
511 of 524
Application +4 | -1
The speed of propagation of a wave in a medium is 300 m/s300 \mathrm{~m} / \mathrm{s}. The equation of motion of point at x=0x=0 is given by y=0.04sin⁡600πty=0.04 \sin 600 \pi t (metre). The displacement of a point x=75 cmx=75 \mathrm{~cm} at t=0.01 st=0.01 \mathrm{~s} is
View answer and explanation
Correct option: B
0.04 m0.04 \mathrm{~m}
Option B (0.04 m0.04 \mathrm{~m}) is correct because the displacement is calculated using the wave equation with given parameters.
512 Medium
512 of 524
Understanding +4 | -1
A person blows into the open end of a long pipe. As a result, a high-pressure pulse of air travels down the pipe. When this pulse reaches the other end of the pipe,
View answer and explanation
Correct option: B
A low-pressure pulse starts travelling up the pipe, if the other end of the pipe is open
Option B is correct because when a high-pressure pulse reaches the open end of a pipe, it reflects as a low-pressure pulse due to a phase change of π\pi.
513 Medium
513 of 524
Application +4 | -1
A plane wave is described by the equation y=3cos⁡(x4−10t−π2)y = 3\cos \left( {\frac{x}{4} - 10t - \frac{\pi }{2}} \right). The maximum velocity of the particles of the medium due to this wave is
View answer and explanation
Correct option: A
30
Option A (30) is correct because the maximum particle velocity is the product of the amplitude and the angular frequency.
514 Medium
514 of 524
Application +4 | -1
Two transverse sinusoidal waves travel in opposite directions along a string. The speed of transverse waves in the string is 0.5 cm s−10.5 \mathrm{~cm} \mathrm{~s}^{-1}. Each has an amplitude of 3.0 cm3.0 \mathrm{~cm} and wavelength of 6.0 cm6.0 \mathrm{~cm}. The equation for the resultant wave is
View answer and explanation
Correct option: C
Both may be correct
Option C (Both may be correct) is correct because the equation represents a standing wave formed by the superposition of two waves, and the sine and cosine functions can be interchanged depending on the initial phase.
515 Medium
515 of 524
Understanding +4 | -1
Assertion (A) : If we see the oscillations of a stretched wire at higher overtone mode, frequency of oscillation increases but wavelength decreases.

Reason (R) : From v=fλ,λ∝1fv=f \lambda, \lambda \propto \frac{1}{f} as v=v= constant.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
Option A (If both Assertion and Reason are true and the Reason is correct explanation of the Assertion) is correct because increasing the overtone mode increases frequency, which decreases wavelength given a constant velocity.
516 Medium
516 of 524
Remembering +4 | -1
The relation between frequency nn, wavelength λ\lambda and velocity vv of propagation of wave is
View answer and explanation
Correct option: C
n=vλn=\frac{v}{\lambda}
Option C (n=vλn=\frac{v}{\lambda}) is correct because the frequency of a wave is equal to its velocity divided by its wavelength, a fundamental relationship in wave physics.
517 Medium
517 of 524
Remembering +4 | -1
Sound travels in rocks in the form of:
View answer and explanation
Correct option: C
Both longitudinal and transverse elastic waves
Option C (Both longitudinal and transverse elastic waves) is correct because solids, like rocks, can support both longitudinal (compressional) and transverse (shear) waves due to their rigidity.
518 Medium
518 of 524
Understanding +4 | -1
Two tuning forks of frequency 250 Hz and 256 Hz produce beats. Then beat frequency is
View answer and explanation
Correct option: A
6 Hz
Option A is correct because the beat frequency is the absolute difference between the frequencies of the two tuning forks.
519 Medium
519 of 524
Understanding +4 | -1
When a wave travelling from one medium is
refracted into other medium, which of the
following will not change?
View answer and explanation
Correct option: C
Frequency
Option C (Frequency) is correct because the frequency of a wave remains unchanged when it travels from one medium to another, while other properties like wavelength, amplitude, and velocity change.
520 Medium
520 of 524
Understanding +4 | -1
A listener is at rest with respect to the source of sound. A wind start blowing along the line joining the source and the observer. Which of the following quantities do not change?
View answer and explanation
Correct option: B
Apparent frequency of sound
Option D (All of these) is correct because the wind affects the velocity and wavelength of sound, but since both source and listener are at rest relative to each other, the apparent frequency remains unchanged.
521 Medium
521 of 524
Understanding +4 | -1
Two periodic waves of amplitudes aa and bb pass through a region at the same time in the same direction. If a>ba > b, the difference in the maximum and minimum possible amplitudes is
View answer and explanation
Correct option: D
2b2 b
Option D (2b2b) is correct because the difference between the maximum and minimum amplitudes is calculated as (a+b)−(a−b)=2b(a+b) - (a-b) = 2b.
522 Medium
522 of 524
Application +4 | -1
A 100 Hz100 \mathrm{~Hz} sinusoidal wave is travelling in the positive xx-direction along a string with a linear mass density of 3.5×10−3 kg/m3.5 \times 10^{-3} \mathrm{~kg} / \mathrm{m} and a tension of 35 N35 \mathrm{~N}. At time t=0t=0, the point x=0x=0, has maximum displacement in the positive yy-direction. Next when this point has zero displacement, the slope of the string is π/20\pi / 20. Which of the following expression represent (s) the displacement of string as a function of xx (in metre) and tt (in second)
View answer and explanation
Correct option: A
y=0.025cos⁡(200πt−2πx)y=0.025 \cos (200 \pi t-2 \pi x)
Option D (Will be one-fourth in number) is correct because the number of ejected electrons is proportional to the intensity of light, which decreases with the square of the distance.
523 Medium
523 of 524
Understanding +4 | -1
Out of the given waves (1), (2), (3) and (4)
y=asin⁡(kx+ωt)y = a\sin \left( {kx + \omega t} \right) ...(11)
y=asin⁡(ωt−kx)y = a\sin \left( {\omega t - kx} \right) …(22)
y=acos⁡(kx+ωt)y = a\cos \left( {kx + \omega t} \right) …(33)
y=acos⁡(ωt−kx)y = a\cos \left( {\omega t - kx} \right) …(44)
Emitted by four different sources S1,S2,S3  and  S4{S_1},{S_2},{S_3}\,\,and\,\,{S_4} respectively, interference phenomena would be observed in space under appropriate conditions when
View answer and explanation
Correct option: C
Source S2{S_2} emits wave (22) and S4{S_4}  emits wave (44)
Option C is correct because for interference to occur, the waves must have a constant phase relationship, and waves (2) and (4) maintain a constant phase difference.
524 Medium
524 of 524
Application +4 | -1
A string of length 2x2 \mathrm{x} is stretched by 0.1x0.1 \mathrm{x} and the velocity of a transverse wave along it is vv. When it is stretched by 0.4x0.4 \mathrm{x} the velocity of the wave is
View answer and explanation
Correct option: C
327v\sqrt{\frac{32}{7}} v
Option C (327v\sqrt{\frac{32}{7}} v) is correct because it correctly relates the wave velocity to the tension in the string, which depends on the extension.
Revision notes and key takeaways

Review WAVES in your textbook or class notes, then use this set to check your understanding.

Showing 511-524 of 524 questions
0 /524
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.