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JEE • PHYSICS • WAVES

Waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 481-510 of 524 questions
481 Medium
481 of 524
Application +4 | -1
A man is standing on the platform and one train is approaching and another train is going away with speed of 4  ms−14\,\,m{s^{ - 1}}, frequency of sound produced by train is 240Hz240\mathrm{ }Hz. What will be the number of beats heard by him per second?
View answer and explanation
Correct option: C
66
Option C (6) is correct because the number of beats heard is the difference between the frequencies of the approaching and receding trains, calculated using the Doppler effect.
482 Medium
482 of 524
Understanding +4 | -1
If the intensities of two interfering waves be I1\mathrm{I}_1 and I2\mathrm{I}_2, the contrast between maximum and minimum intensity is maximum, when
View answer and explanation
Correct option: C
I1=I2\mathrm{I}_1=\mathrm{I}_2
Option B is correct because conductors have minimal or no band gap, semiconductors have a moderate band gap, and insulators have a large band gap.
483 Medium
483 of 524
Analyzing +4 | -1
If x=asin⁡[ωt+(π/3)]x=a \sin [\omega t+(\pi / 3)] and x′=acos⁡ωtx^{\prime}=a \cos \omega t, then what is the phase difference between two waves?
View answer and explanation
Correct option: B
π/6\quad \pi / 6
Option B (π/6\quad \pi / 6) is correct because the phase difference is calculated by converting cosine to sine and then finding the difference in the phase angles.
484 Medium
484 of 524
Analyzing +4 | -1
Two sound waves are represented by y=a  sin⁡(ωt−kx)y = a\,\,\sin \left( {\omega t - kx} \right) and y=a  cos⁡(ωt−kx)y = a\,\,\cos \left( {\omega t - kx} \right). The wavelength of waves in water are
View answer and explanation
Correct option: A
π2\frac{\pi }{2}
Option A (π2\frac{\pi }{2}) is correct because the phase difference between the two waves is 90 degrees or π2\frac{\pi}{2} radians.
485 Medium
485 of 524
Understanding +4 | -1
If the temperature increases, then what happens to the frequency of the sound produced by the organ pipe
View answer and explanation
Correct option: A
Increases
Option A (Increases) is correct because the frequency of sound produced by an organ pipe increases with temperature due to the increase in the speed of sound.
486 Medium
486 of 524
Remembering +4 | -1
Vibrations of air column above the surface of water in the tube of a resonance apparatus are
View answer and explanation
Correct option: C
Longitudinal
Option C (Longitudinal) is correct because sound waves, including those in a resonance tube, are longitudinal waves.
487 Medium
487 of 524
Application +4 | -1
A wave travelling in positive XX-direction with A=0.2 mA = 0.2\,m has a velocity of 360  m/sec.360\,\,m/sec.. If λ=60  m,\lambda = 60\,\,m,, then correct expression for the wave is
View answer and explanation
Correct option: C
y=0.2sin⁡[2π(6t−x60)]y = 0.2\sin \left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]
Option C (y=0.2sin⁡[2π(6t−x60)]y = 0.2\sin \left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]) is correct because it represents a wave traveling in the positive X-direction with the given amplitude, velocity, and wavelength.
488 Medium
488 of 524
Application +4 | -1
A bullet passes past a person at a speed of 220 m/s220 \mathrm{~m} / \mathrm{s}. Find the fractional change in the frequency of the whistling sound heard by the person as the bullet crosses the person. Speed of sound in air =330 m/s=330 \mathrm{~m} / \mathrm{s}.
View answer and explanation
Correct option: A
0.8
Option A (0.8) is correct because the fractional change in frequency is calculated by considering the Doppler effect before and after the bullet passes the person.
489 Medium
489 of 524
Remembering +4 | -1
Of the following, the equation of plane progressive wave is
View answer and explanation
Correct option: B
y=r  sin⁡(ωt−kx)y = r\,\,\sin \left( {\omega t - kx} \right)
Option B is correct because the equation of a plane progressive wave includes a sinusoidal function with both time and position variables.
490 Medium
490 of 524
Application +4 | -1
A radar sends radio waves of frequency vv towards an aeroplane moving with velocity vAv_A. A change Δv\Delta v is observed in the frequency of reflected wave which is higher than the original frequency. The velocity of aeroplane (vA<<c)\left(v_A < < c\right) is
View answer and explanation
Correct option: C
cΔv2vc \frac{\Delta v}{2 v}
Option C (cΔv2vc \frac{\Delta v}{2 v}) is correct because it is derived from the Doppler effect formula for reflected waves.
491 Medium
491 of 524
Understanding +4 | -1
A travelling wave is partly reflected and partly transmitted from a rigid boundary. Let ai,ara_i, a_r and ata_t be the amplitudes of incident wave, reflected wave and transmitted wave and Ii,IrI_i, I_r and ItI_t be the corresponding intensities. Then, choose the correct alternative
View answer and explanation
Correct option: A
IiIr=(aiar)2\frac{I_i}{I_r}=\left(\frac{a_i}{a_r}\right)^2
Option A is correct because the ratio of intensities is the square of the ratio of amplitudes when the medium is the same for both waves.
492 Medium
492 of 524
Understanding +4 | -1
The equation of a resultant wave obtained after superposition of two waves is given by y(x,t)=2asin⁡kxcos⁡ωty(x, t)=2 a \sin k x \cos \omega t. The position of nodes will be given by:
View answer and explanation
Correct option: B
sin⁡kx=0\sin k x=0
Option B is correct because nodes occur where the displacement is zero, which corresponds to sin⁡kx=0\sin kx = 0 in the given equation.
493 Medium
493 of 524
Understanding +4 | -1
Assertion (A) : Standing waves are formed when amplitudes of two constituent waves are equal.

Reason (R) : At any point net displacement at a given time is resultant of displacement of constituent waves.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D (If Assertion is false but the Reason is true) is correct because standing waves can be formed with different amplitudes, and the net displacement is indeed the resultant of constituent waves.
494 Medium
494 of 524
Understanding +4 | -1
A wave travelling along a string is described by the equation y=asin⁡(ωt−kx)y = a\sin \left( {\omega t - kx} \right) the maximum particle velocity is
View answer and explanation
Correct option: A
aωa\omega
Option A (aωa\omega) is correct because the maximum particle velocity is obtained by differentiating the given wave equation with respect to time and finding the maximum value.
495 Medium
495 of 524
Application +4 | -1
A sonometer wire resonates with frequency f0\mathrm{f}_0 in its fundamental mode. If length of the wire is decreased to the value 0.95 m0.95 \mathrm{~m}, the resonating frequency increases by 5 Hz5 \mathrm{~Hz} and if length is increased to the value 1.0 m1.0 \mathrm{~m}, the resonating frequency decreases by 5 Hz5 \mathrm{~Hz}. Find the length (in cm\mathrm{cm} ) of the wire for the resonating frequency f0f_0. The speed of the wave in the wire is 382.2 m/s382.2 \mathrm{~m} / \mathrm{s}.
View answer and explanation
Correct option: A
98
Option A (98) is correct because it's calculated using the relationship between frequency, length, and velocity in a sonometer wire.
496 Medium
496 of 524
Application +4 | -1
Two similar sonometer wires given fundamental frequencies of 500  Hz500\,\,Hz. These have same tensions. By what amount the tension be increased in one wire so that the two wires produce 5  beats/sec⁡5\,\,beats/\sec
View answer and explanation
Correct option: B
2  %2\,\,\%
Option D (2 2\,\\%) is correct because the percentage change in tension is twice the percentage change in frequency, which is calculated from the beat frequency.
497 Medium
497 of 524
Understanding +4 | -1
When a sound wave travels from water to air, it
View answer and explanation
Correct option: A
bends towards normal
Option B (bends away from normal) is incorrect. The correct answer is that it bends away from the normal because sound travels faster in water than in air, so air is the rarer medium and water is the denser medium.
498 Medium
498 of 524
Analyzing +4 | -1
A,BA, B and CC are three tuning forks. Frequency of AA is 350 Hz350 \mathrm{~Hz}. Beats produced by AA and BB are 5/s5 / \mathrm{s} and by BB and CC are 4/s4 / \mathrm{s}. When a wax is put on AA beat frequency between AA and BB is 2 Hz2 \mathrm{~Hz} and between AA and CC is 6 Hz6 \mathrm{~Hz}. Then, frequency of BB and CC respectively, are
View answer and explanation
Correct option: B
345 Hz,341 Hz345 \mathrm{~Hz}, 341 \mathrm{~Hz}
Option B (345 Hz, 341 Hz) is correct because after putting wax on A, its frequency decreases, and the beat frequencies with B and C change accordingly, leading to these values.
499 Medium
499 of 524
Understanding +4 | -1
Sound waves in air always longitudinal because
View answer and explanation
Correct option: B
Air does not have a modulus of rigidity
Option B is correct because air lacks a modulus of rigidity, meaning it cannot sustain shear stress, which is necessary for transverse waves.
500 Medium
500 of 524
Understanding +4 | -1
In a stationary wave all the particles
View answer and explanation
Correct option: B
In the region between two nodes vibrate in same phase
Option B (In the region between two nodes vibrate in same phase) is correct because in a stationary wave, particles between two consecutive nodes vibrate in the same phase.
501 Medium
501 of 524
Understanding +4 | -1
There are two organ pipes of exactly the same length and material but of different radii. The loss of sound will be
View answer and explanation
Correct option: A
More from a wider pipe
Option A is correct because a wider pipe has a larger cross-sectional area, leading to greater sound energy dissipation.
502 Medium
502 of 524
Understanding +4 | -1
When stationary waves are set up, pick out the correct statement from the following
View answer and explanation
Correct option: B
The particles with an interval between two consecutive nodes are in phase, but the particles in two such consecutive intervals are of opposite phase
Option B (The particles with an interval between two consecutive nodes are in phase, but the particles in two such consecutive intervals are of opposite phase) is correct because in stationary waves, particles between consecutive nodes vibrate in phase, while those in adjacent segments are out of phase.
503 Medium
503 of 524
Understanding +4 | -1
Doppler effect of sound depends on
View answer and explanation
Correct option: C
Relative velocity between source and listener
Option C (Relative velocity between source and listener) is correct because the Doppler effect depends on the relative motion between the source of the sound and the listener.
504 Medium
504 of 524
Application +4 | -1
The equation of stationary wave along a stretched string is given by y=5   sin⁡πx3cos⁡  40πty = 5\,\,\,\sin \frac{{\pi x}}{3}\cos \,\,40\pi t where xx and yy are in cm and tt in second. The separation between two adjacent nodes is
View answer and explanation
Correct option: B
3  cm3\,\,cm
Option B (3 cm) is correct because the distance between two adjacent nodes in a stationary wave is half of the wavelength, which is calculated from the given equation.
505 Medium
505 of 524
Understanding +4 | -1
When a string fixed at its two ends vibrates in 1 loop, 2 loops, 3 loops and 4 loops, the frequencies are in the ratio
View answer and explanation
Correct option: B
1:2:3:4
Option B (1:2:3:4) is correct because the frequencies of vibration in a string fixed at both ends are in the ratio of integers.
506 Medium
506 of 524
Understanding +4 | -1
Assertion: Sound would travel faster on a hot summer day than on a cold winter day.
Reason: Velocity of sound is directly proportional to the square of absolute temperature.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
Option C (If assertion is true, but reason is false) is correct because sound does travel faster on a hot day, but the velocity is proportional to the square root of the absolute temperature, not the square.
507 Medium
507 of 524
Application +4 | -1
A plane progressive wave is represented by the equation y=0.1  sin⁡(200 πt−20 πx17)y = 0.1\,\,\sin \left( {200\,\pi t - \frac{{20\,\pi x}}{{17}}} \right) where yy is displacement in m,tm,t in second and xx is distance from a fixed origin in meter. The frequency, wavelength and speed of the wave respectively are
View answer and explanation
Correct option: A
100  Hz,  1.7  m,  170  m/s100\,\,Hz,\,\,1.7\,\,m,\,\,170\,\,m/s
Option A (100 Hz, 1.7 m, 170 m/s) is correct because the frequency, wavelength, and speed are derived from the given wave equation by comparing it to the standard form.
508 Medium
508 of 524
Understanding +4 | -1
Two waves are given by y1=a  sin⁡(ωt−kx){y_1} = a\,\,\sin \left( {\omega t - kx} \right) and y2=a   cos⁡(ωt−kx){y_2} = a\,\,\,\cos \left( {\omega t - kx} \right)

The phase difference between the two waves is
View answer and explanation
Correct option: D
π/2\pi /2
Option D (π/2\pi /2) is correct because the cosine function is a sine function shifted by π/2\pi/2.
509 Medium
509 of 524
Understanding +4 | -1
The frequency of a sound wave is nn and its velocity is vv. If the frequency is increased to 4n4n, the velocity of the wave will be
View answer and explanation
Correct option: A
vv
Option A (vv) is correct because the velocity of a sound wave in a given medium depends on the properties of the medium, not the frequency.
510 Medium
510 of 524
Remembering +4 | -1
The phase velocity (vp)\left( {{v_p}} \right) of travelling wave is
View answer and explanation
Correct option: A
vp=ωk{v_p} = \frac{\omega }{k}
Option A (vp=ωk{v_p} = \frac{\omega }{k}) is correct because the phase velocity of a traveling wave is defined as the ratio of angular frequency to wave number.
Revision notes and key takeaways

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