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JEE • PHYSICS • WAVES

Waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 524 questions

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271 Medium
271 of 524
Application +4 | -1
A transverse wave propagating on a stretched string of liner density 3×10−4kg−m−13 \times {10^{ - 4}}\mathrm{kg} - {\mathrm{m}^{ - 1}} is represented by the equation y=0.2sin⁡(1.5x+60t)y = 0.2\sin \left( {1.5x + 60t} \right) where xx is in meter and tt is in second. The tension in the string (in newton) is
View answer and explanation
Correct option: B
0.48
Option B (0.48 N) is correct because the tension in the string is calculated using the wave equation and the linear density.
272 Medium
272 of 524
Analyzing +4 | -1
Assertion(A): Speed of sound in O2\mathrm{O}_2 gas at temperature TT is vv. If temperature is increased to 2T2 T, the molecular oxygen breaks into atomic oxygen. Then, speed of sound under these conditions will become 2v2 v.

Reason(R): With increase in humidity in air, speed of sound increases.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B is correct because both Assertion and Reason are correct, but the Reason does not explain the Assertion.
273 Medium
273 of 524
Understanding +4 | -1
When sound wave is refracted from air to water, which of the following will remain unchanged?
View answer and explanation
Correct option: C
Frequency
Option C is correct because frequency is a property of the source and does not change during refraction.
274 Medium
274 of 524
Analyzing +4 | -1
Assertion: The velocity of sound in air decreases if the pressure of air decreases at constant temperature.
Reason: According to Laplace's formula as modified by Newton, velocity of sound in air is given by V=γPρ.V = \sqrt {\frac{{\gamma P}}{\rho }}.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because the velocity of sound in air increases with pressure at constant temperature, and the given formula is correct.
275 Medium
275 of 524
Analyzing +4 | -1
Given that y=Asin⁡[(2πλ(ct−x))]y = A\sin \left[ {\left( {\frac{{2\pi }}{\lambda }\left( {ct - x} \right)} \right)} \right], where yy and xx are measured in metres. Which of the following statements is true
View answer and explanation
Correct option: A
The unit of λ−1{\lambda ^{ - 1}} is same as that of 2πλ\frac{{2\pi }}{\lambda }
Option A (The unit of λ−1{\lambda ^{ - 1}} is same as that of 2πλ\frac{{2\pi }}{\lambda }) is correct because both represent inverse lengths, thus having the same units.
276 Medium
276 of 524
Understanding +4 | -1
Sound waves are travelling in a medium whose adiabatic elasticity is EE and isothermal elasticity E′E^{\prime}. The velocity of sound waves is proportional to:
View answer and explanation
Correct option: B
E\sqrt{E}
Option B (E\sqrt{E}) is correct because the velocity of sound waves is proportional to the square root of the adiabatic elasticity (E).
277 Medium
277 of 524
Remembering +4 | -1
The speed of sound in gas of density ρρ at a pressure pp is proportional to
View answer and explanation
Correct option: D
pρ\sqrt {\frac{p}{\mathrm{\rho }}}
Option D (pρ\sqrt {\frac{p}{\mathrm{\rho }}}) is correct because the speed of sound in a gas is proportional to the square root of the pressure divided by the density.
278 Medium
278 of 524
Understanding +4 | -1
In open organ pipe, if fundamental frequency is nn then the other frequencies are
View answer and explanation
Correct option: A
n,2n,3n,4nn,2n,3n,4n
Option A is correct because an open organ pipe produces all harmonics, both even and odd multiples of the fundamental frequency.
279 Medium
279 of 524
Understanding +4 | -1
If we study the vibration of a pipe open at both ends, then which of the following statements is not true ?
View answer and explanation
Correct option: C
Pressure change will be maximum at both ends
Option C (Pressure change will be maximum at both ends) is correct because in an open pipe, the pressure change is minimum at the open ends (nodes of pressure variation).
280 Medium
280 of 524
Application +4 | -1
Intensity level of sound of intensity II is 30  dB30\,\,dB. The ratio II0\frac{I}{{{I_0}}} is (Where I0{I_0} is the threshold of hearing)
View answer and explanation
Correct option: B
10001000
Option B (1000) is correct because it is the ratio of the sound intensity to the threshold of hearing, calculated using the decibel scale formula.
281 Medium
281 of 524
Application +4 | -1
Two trains, one coming towards and another going away from an observer both at 4  m/s4\,\,m/s produce whistle simultaneously of frequency 300  Hz300\,\,Hz. Find the number of beats produced
View answer and explanation
Correct option: C
77
Option C (77) is correct because it is calculated using the Doppler effect formula for both approaching and receding sources, then finding the difference in frequencies.
282 Medium
282 of 524
Understanding +4 | -1
Assertion: Standing wave does not transfer energy in the medium.
Reason: Every particle vibrates with its own energy and it does not share its energy with any other Particle.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & reason are True & the Reason is a correct explanation of the Assertion) is correct because standing waves do not transfer energy, and this is because each particle vibrates with its own energy without sharing it.
283 Medium
283 of 524
Analyzing +4 | -1
The wave function of a pulse is given by y=3(2x+3t)2y=\frac{3}{(2 x+3 t)^2} where xx and yy are in metre and tt is in second.

i) Identify the direction of propagation.

ii) Determine the wave velocity of the pulse.
View answer and explanation
Correct option: A
−1.5 m/s-1.5 \mathrm{~m} / \mathrm{s}
Option A (-1.5 m/s) is correct because the wave function is of the form f(x + vt), indicating propagation along the negative x-axis with a velocity of -1.5 m/s.
284 Medium
284 of 524
Analyzing +4 | -1
For a transverse wave travelling along a straight line, the distance between two peaks (crests) is 5 m, while the distance between one crest and one trough is 1.5 m. The possible wavelengths (in metre) of the waves are
View answer and explanation
Correct option: B
11,13,15....\frac{1}{1},\frac{1}{3},\frac{1}{5}....
Option B (11,13,15....\frac{{1}}{{1}},\frac{{1}}{{3}},\frac{{1}}{{5}}....) is correct because these wavelengths satisfy the given conditions for the distance between crests and troughs.
285 Medium
285 of 524
Application +4 | -1
A fork of frequency 340 Hz340 \mathrm{~Hz} is allowed to vibrate just above the open of resonance tube of length 120 cm120 \mathrm{~cm}. If velocity of sound =340 m/s=340 \mathrm{~m} / \mathrm{s}. Find (a) maximum number of resonance (b) maximum and minimum liquid level at resonance condition.
View answer and explanation
Correct option: A
75;95,4575;95,45
Option A (75;95,4575;95,45) is correct because it correctly calculates the maximum number of resonances and the maximum and minimum liquid levels.
286 Medium
286 of 524
Analyzing +4 | -1
A tuning fork of frequency 480  Hz480\,\,Hz produces 10    beats  per  sec\mathrm{10}{\mkern 1mu} {\mkern 1mu} \,\,\mathrm{beats}\,\,\mathrm{per}\,\,\mathrm{sec} when sounded with a vibrating sonometer string. What must have been the frequency of string if slight increase in tension produces few beats s−1{\mathrm{s}^{ - 1}} than before?
View answer and explanation
Correct option: B
470  Hz \begin{array}{llllllllllllllllllll} {470\,\,Hz} \end{array}\,
Option B (470 Hz) is correct because increasing the tension would increase the string's frequency, reducing the beat frequency only if the original frequency was lower than the tuning fork's.
287 Medium
287 of 524
Remembering +4 | -1
Doppler phenomena is related with
View answer and explanation
Correct option: A
Pitch (frequency)
Option A (Pitch (frequency)) is correct because the Doppler effect relates to the change in frequency (pitch) of a wave due to the relative motion between the source and the observer.
288 Medium
288 of 524
Understanding +4 | -1
Statement-I: When a wave is transmitted from one medium to another, the frequency does not change.
Statement-II: A wave transports energy and momentum along with matter.
View answer and explanation
Correct option: A
Statement-I is correct
Statement-I is correct because the frequency of a wave remains constant when it travels from one medium to another. Statement-II is incorrect because waves transport energy and momentum but not matter.
289 Medium
289 of 524
Understanding +4 | -1
A tuning fork produces waves in a medium. If the temperature of the medium changes, then which of the following will change
View answer and explanation
Correct option: C
Wavelength
Option C (Wavelength) is correct because the speed of a wave in a medium depends on the temperature, and since frequency remains constant, the wavelength changes.
290 Medium
290 of 524
Application +4 | -1
A tuning fork vibrating with a sonometer having 20  cm20\,\,cm wire produces 55 beats per second. The beat frequency does not change if the length of the wire is changed to 21  cm21\,\,cm. The frequency of the tuning fork (in Hertz) must be
View answer and explanation
Correct option: C
205205
Option C (205) is correct because the frequency of the tuning fork is calculated by considering the beat frequencies produced with different lengths of the sonometer wire.
291 Medium
291 of 524
Remembering +4 | -1
The type of waves that can be propagated through solid is
View answer and explanation
Correct option: C
Both (aa) and (bb)
Option C (Both (a) and (b)) is correct because solids can support both transverse and longitudinal waves due to their rigidity and elasticity.
292 Medium
292 of 524
Understanding +4 | -1
When a stationary wave is formed then its frequency is
View answer and explanation
Correct option: A
Same as that of the individual waves
Option A (Same as that of the individual waves) is correct because the frequency of a stationary wave is the same as the frequency of the interfering waves.
293 Medium
293 of 524
Application +4 | -1
When a sound wave of wavelength λ\lambda is propagating in a medium, the maximum velocity of the particle is equal to the velocity. The amplitude of wave is
View answer and explanation
Correct option: C
λ2π\frac{\mathrm{\lambda }}{{2\mathrm{\pi }}}
Option C (λ2π\frac{\mathrm{\lambda }}{{2\mathrm{\pi }}}) is correct because it is derived by equating the maximum particle velocity to the wave velocity and solving for the amplitude.
294 Medium
294 of 524
Understanding +4 | -1
If wave y=a  cos⁡(ωt+kx)y = a\,\,\cos \left( {\omega t + kx} \right) is moving along x−axisx - axis, the shape of pulse at t=0  and  t=2 st = 0\,\,and\,\,t = 2\,s
View answer and explanation
Correct option: B
Are same
Option B (Are same) is correct because the shape of the wave remains the same at different times, only its position changes.
295 Medium
295 of 524
Application +4 | -1
A tuning fork of frequency 200Hz200\mathrm{ }Hz is in unison with a sonometer wire. The number of beats heard per second when the tension is increased by 1%1\% is
View answer and explanation
Correct option: A
11
Option A (1) is the correct answer because the number of beats is equal to the difference in frequencies, which is calculated to be 1 Hz when the tension is increased by 1%.
296 Medium
296 of 524
Understanding +4 | -1
Assertion: Due to end correction fundamental frequency of any pipe becomes less than frequency without end correction.
Reason: Due to end correction effective length of pipe increases.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
The correct answer is A (If both Assertion & reason are True & the Reason is a correct explanation of the Assertion) because end correction increases the effective length of the pipe, which lowers the fundamental frequency.
297 Medium
297 of 524
Understanding +4 | -1
Two points P and Q have a phase difference of π\pi when a travelling sine wave passes through the region.
Statement-I: P and Q move in opposite directions.
Statement-II: P oscillates at half the frequency of Q.
View answer and explanation
Correct option: A
Statement-I is correct
Option A (Statement-I is correct) is correct because two points with a phase difference of π\pi in a traveling sine wave move in opposite directions.
298 Medium
298 of 524
Analyzing +4 | -1
The mathematical form of three travelling waves are given by

y1=(2 cm)sin⁡(3x−6t),y2=(3 cm)sin⁡(4x−12t),  and y3=(4 cm)sin⁡(5x−11t)\begin{aligned} & y_1=(2 {~cm}) \sin (3 x-6 t), \\ & y_2=(3 {~cm}) \sin (4 x-12 t) \text {, } \\ & \text { and } y_3=(4 {~cm}) \sin (5 x-11 t) \\ \end{aligned}

of these waves,
View answer and explanation
Correct option: D
Wave 2 has greatest wave speed and wave 3 has maximum transverse string speed
Option D (Wave 2 has greatest wave speed and wave 3 has maximum transverse string speed) is correct because wave speed is ω/k\omega/k and maximum transverse speed is AωA\omega.
299 Medium
299 of 524
Understanding +4 | -1
What is the phase difference between the displacement wave and pressure wave in a sound wave?
View answer and explanation
Correct option: B
π2\frac{\pi}{2}
Option B (π2\frac{\pi}{2}) is correct because the pressure wave is 90 degrees out of phase with the displacement wave in a sound wave.
300 Medium
300 of 524
Application +4 | -1
The equation of sound wave is
y=0.0015  sin⁡(62.4x  +  316 t)y = 0.0015\,\,\sin \left( {62.4x\,\, + \,\,316\,t} \right)
The wavelength of this wave is
View answer and explanation
Correct option: B
0.1unit\begin{array}{llllllllllllllllllll} {0.1\mathrm{ }unit} \end{array}
Option B (0.1unit\begin{array}{llllllllllllllllllll}{0.1\mathrm{ }unit}\end{array}) is correct because the wavelength is calculated from the wave number (k) in the given equation.
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