JEE PHYSICS MCQ: WAVES

1 Medium

1 of 1

Application +4 | -1

{n_1}

is the frequency of the pipe closed at one end and

{n_2}

is the frequency of the pipe open at both ends. If both are joined end to end, find the fundamental frequency of closed pipe so formed

View answer and explanation

Correct option: A

\frac{{{\mathrm{n}_1}{\mathrm{n}_2}}}{{{\mathrm{n}_2} + 2{\mathrm{n}_1}}}

Option A (

\frac{{{\mathrm{n}_1}{\mathrm{n}_2}}}{{{\mathrm{n}_2} + 2{\mathrm{n}_1}}}

) is correct because it represents the fundamental frequency of the closed pipe formed by joining the two pipes, derived from the individual frequencies and lengths of the open and closed pipes.

More Questions from WAVES

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The source of sound generating a frequency of

3\,\,kHz

reaches an observer with a speed of

0.5

times, the velocity of sound in air. The frequency heard by the observer is A source of sound emits waves with frequency

f\mathrm{ }Hz

and speed

V\mathrm{ }m/sec

. Two observers move away from this source in opposite directions each with a speed

0.2\,\,V

relative to the source. The ratio of frequencies heard by the two observers will be Assertion: The wave function of a pulse is given by

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

it propagates in

(– \mathrm{ve}) \,x

-direction.
Reason: The given wave function is of the form

y = f(kx +\omega t),

which represent a wave travelling in negative

X

-direction. In the fundamental mode, time taken by the wave to reach the closed end of the air filled pipe is

0.01\,\,s

. the fundamental frequency is A rope

5 \mathrm{~m}

long has a total mass of

245 \mathrm{~g}

. It is stretched with a constant tension of

1 \mathrm{~kg}

wt. If it is fixed at one end and shaken by hand at the other end, what frequency of shaking will make it break up into three vibrating segments? Take

g=980 \mathrm{~cm} \mathrm{~s}^{-2}

. If

T

is the reverberation time of an auditorium of volume

V

then