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JEE • PHYSICS • WAVES

Waves practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 541-543 of 543 questions
541 Medium
541 of 543
Application +4 | -1
A 100 Hz100 \mathrm{~Hz} sinusoidal wave is travelling in the positive xx-direction along a string with a linear mass density of 3.5×10−3 kg/m3.5 \times 10^{-3} \mathrm{~kg} / \mathrm{m} and a tension of 35 N35 \mathrm{~N}. At time t=0t=0, the point x=0x=0, has maximum displacement in the positive yy-direction. Next when this point has zero displacement, the slope of the string is π/20\pi / 20. Which of the following expression represent (s) the displacement of string as a function of xx (in metre) and tt (in second)
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Correct option: A
y=0.025cos⁡(200πt−2πx)y=0.025 \cos (200 \pi t-2 \pi x)
Option D (Will be one-fourth in number) is correct because the number of ejected electrons is proportional to the intensity of light, which decreases with the square of the distance.
542 Medium
542 of 543
Understanding +4 | -1
Out of the given waves (1), (2), (3) and (4)
y=asin⁡(kx+ωt)y = a\sin \left( {kx + \omega t} \right) ...(11)
y=asin⁡(ωt−kx)y = a\sin \left( {\omega t - kx} \right) …(22)
y=acos⁡(kx+ωt)y = a\cos \left( {kx + \omega t} \right) …(33)
y=acos⁡(ωt−kx)y = a\cos \left( {\omega t - kx} \right) …(44)
Emitted by four different sources S1,S2,S3  and  S4{S_1},{S_2},{S_3}\,\,and\,\,{S_4} respectively, interference phenomena would be observed in space under appropriate conditions when
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Correct option: C
Source S2{S_2} emits wave (22) and S4{S_4}  emits wave (44)
Option C is correct because for interference to occur, the waves must have a constant phase relationship, and waves (2) and (4) maintain a constant phase difference.
543 Medium
543 of 543
Application +4 | -1
A string of length 2x2 \mathrm{x} is stretched by 0.1x0.1 \mathrm{x} and the velocity of a transverse wave along it is vv. When it is stretched by 0.4x0.4 \mathrm{x} the velocity of the wave is
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Correct option: C
327v\sqrt{\frac{32}{7}} v
Option C (327v\sqrt{\frac{32}{7}} v) is correct because it correctly relates the wave velocity to the tension in the string, which depends on the extension.
Revision notes and key takeaways

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