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JEE • PHYSICS • WAVES

Waves practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 511-540 of 543 questions
511 Medium
511 of 543
Application +4 | -1
A sonometer wire resonates with frequency f0\mathrm{f}_0 in its fundamental mode. If length of the wire is decreased to the value 0.95 m0.95 \mathrm{~m}, the resonating frequency increases by 5 Hz5 \mathrm{~Hz} and if length is increased to the value 1.0 m1.0 \mathrm{~m}, the resonating frequency decreases by 5 Hz5 \mathrm{~Hz}. Find the length (in cm\mathrm{cm} ) of the wire for the resonating frequency f0f_0. The speed of the wave in the wire is 382.2 m/s382.2 \mathrm{~m} / \mathrm{s}.
View answer and explanation
Correct option: A
98
Option A (98) is correct because it's calculated using the relationship between frequency, length, and velocity in a sonometer wire.
512 Medium
512 of 543
Application +4 | -1
Two similar sonometer wires given fundamental frequencies of 500  Hz500\,\,Hz. These have same tensions. By what amount the tension be increased in one wire so that the two wires produce 5  beats/sec⁡5\,\,beats/\sec
View answer and explanation
Correct option: B
2  %2\,\,\%
Option D (2 2\,\\%) is correct because the percentage change in tension is twice the percentage change in frequency, which is calculated from the beat frequency.
513 Medium
513 of 543
Understanding +4 | -1
When a sound wave travels from water to air, it
View answer and explanation
Correct option: A
bends towards normal
Option B (bends away from normal) is incorrect. The correct answer is that it bends away from the normal because sound travels faster in water than in air, so air is the rarer medium and water is the denser medium.
514 Medium
514 of 543
Analyzing +4 | -1
A,BA, B and CC are three tuning forks. Frequency of AA is 350 Hz350 \mathrm{~Hz}. Beats produced by AA and BB are 5/s5 / \mathrm{s} and by BB and CC are 4/s4 / \mathrm{s}. When a wax is put on AA beat frequency between AA and BB is 2 Hz2 \mathrm{~Hz} and between AA and CC is 6 Hz6 \mathrm{~Hz}. Then, frequency of BB and CC respectively, are
View answer and explanation
Correct option: B
345 Hz,341 Hz345 \mathrm{~Hz}, 341 \mathrm{~Hz}
Option B (345 Hz, 341 Hz) is correct because after putting wax on A, its frequency decreases, and the beat frequencies with B and C change accordingly, leading to these values.
515 Medium
515 of 543
Understanding +4 | -1
Sound waves in air always longitudinal because
View answer and explanation
Correct option: B
Air does not have a modulus of rigidity
Option B is correct because air lacks a modulus of rigidity, meaning it cannot sustain shear stress, which is necessary for transverse waves.
516 Medium
516 of 543
Understanding +4 | -1
In a stationary wave all the particles
View answer and explanation
Correct option: B
In the region between two nodes vibrate in same phase
Option B (In the region between two nodes vibrate in same phase) is correct because in a stationary wave, particles between two consecutive nodes vibrate in the same phase.
517 Medium
517 of 543
Understanding +4 | -1
There are two organ pipes of exactly the same length and material but of different radii. The loss of sound will be
View answer and explanation
Correct option: A
More from a wider pipe
Option A is correct because a wider pipe has a larger cross-sectional area, leading to greater sound energy dissipation.
518 Medium
518 of 543
Understanding +4 | -1
When stationary waves are set up, pick out the correct statement from the following
View answer and explanation
Correct option: B
The particles with an interval between two consecutive nodes are in phase, but the particles in two such consecutive intervals are of opposite phase
Option B (The particles with an interval between two consecutive nodes are in phase, but the particles in two such consecutive intervals are of opposite phase) is correct because in stationary waves, particles between consecutive nodes vibrate in phase, while those in adjacent segments are out of phase.
519 Medium
519 of 543
Understanding +4 | -1
Doppler effect of sound depends on
View answer and explanation
Correct option: C
Relative velocity between source and listener
Option C (Relative velocity between source and listener) is correct because the Doppler effect depends on the relative motion between the source of the sound and the listener.
520 Medium
520 of 543
Application +4 | -1
The equation of stationary wave along a stretched string is given by y=5   sin⁡πx3cos⁡  40πty = 5\,\,\,\sin \frac{{\pi x}}{3}\cos \,\,40\pi t where xx and yy are in cm and tt in second. The separation between two adjacent nodes is
View answer and explanation
Correct option: B
3  cm3\,\,cm
Option B (3 cm) is correct because the distance between two adjacent nodes in a stationary wave is half of the wavelength, which is calculated from the given equation.
521 Easy
521 of 543
Application +4 | -1
A resonance air column of length 20 cm20 \mathrm{~cm} resonates with a tuning fork of frequency 450 Hz450 \mathrm{~Hz}. Ignoring the correction, the velocity of sound in air will be
View answer and explanation
Correct option: D
360 m/s360 \mathrm{~m} / \mathrm{s}
Option D (360 m/s) is correct because the velocity of sound is calculated using the formula v = fλ, where λ = 4l for a closed pipe.
522 Medium
522 of 543
Understanding +4 | -1
When a string fixed at its two ends vibrates in 1 loop, 2 loops, 3 loops and 4 loops, the frequencies are in the ratio
View answer and explanation
Correct option: B
1:2:3:4
Option B (1:2:3:4) is correct because the frequencies of vibration in a string fixed at both ends are in the ratio of integers.
523 Medium
523 of 543
Understanding +4 | -1
Assertion: Sound would travel faster on a hot summer day than on a cold winter day.
Reason: Velocity of sound is directly proportional to the square of absolute temperature.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
Option C (If assertion is true, but reason is false) is correct because sound does travel faster on a hot day, but the velocity is proportional to the square root of the absolute temperature, not the square.
524 Medium
524 of 543
Application +4 | -1
A plane progressive wave is represented by the equation y=0.1  sin⁡(200 πt−20 πx17)y = 0.1\,\,\sin \left( {200\,\pi t - \frac{{20\,\pi x}}{{17}}} \right) where yy is displacement in m,tm,t in second and xx is distance from a fixed origin in meter. The frequency, wavelength and speed of the wave respectively are
View answer and explanation
Correct option: A
100  Hz,  1.7  m,  170  m/s100\,\,Hz,\,\,1.7\,\,m,\,\,170\,\,m/s
Option A (100 Hz, 1.7 m, 170 m/s) is correct because the frequency, wavelength, and speed are derived from the given wave equation by comparing it to the standard form.
525 Medium
525 of 543
Understanding +4 | -1
Two waves are given by y1=a  sin⁡(ωt−kx){y_1} = a\,\,\sin \left( {\omega t - kx} \right) and y2=a   cos⁡(ωt−kx){y_2} = a\,\,\,\cos \left( {\omega t - kx} \right)

The phase difference between the two waves is
View answer and explanation
Correct option: D
π/2\pi /2
Option D (π/2\pi /2) is correct because the cosine function is a sine function shifted by π/2\pi/2.
526 Easy
526 of 543
Understanding +4 | -1
What is your observation when two sources are emitting sound with frequency 499 Hz499 \mathrm{~Hz} and 501 Hz501 \mathrm{~Hz}?
View answer and explanation
Correct option: A
Frequency of 500 Hz500 \mathrm{~Hz} is heard with change in intensity take place twice
Option A is correct because the frequency heard is the average of the two frequencies, and the change in intensity (beats) occurs twice per second due to the 2 Hz difference.
527 Medium
527 of 543
Understanding +4 | -1
The frequency of a sound wave is nn and its velocity is vv. If the frequency is increased to 4n4n, the velocity of the wave will be
View answer and explanation
Correct option: A
vv
Option A (vv) is correct because the velocity of a sound wave in a given medium depends on the properties of the medium, not the frequency.
528 Medium
528 of 543
Remembering +4 | -1
The phase velocity (vp)\left( {{v_p}} \right) of travelling wave is
View answer and explanation
Correct option: A
vp=ωk{v_p} = \frac{\omega }{k}
Option A (vp=ωk{v_p} = \frac{\omega }{k}) is correct because the phase velocity of a traveling wave is defined as the ratio of angular frequency to wave number.
529 Medium
529 of 543
Application +4 | -1
The speed of propagation of a wave in a medium is 300 m/s300 \mathrm{~m} / \mathrm{s}. The equation of motion of point at x=0x=0 is given by y=0.04sin⁡600πty=0.04 \sin 600 \pi t (metre). The displacement of a point x=75 cmx=75 \mathrm{~cm} at t=0.01 st=0.01 \mathrm{~s} is
View answer and explanation
Correct option: B
0.04 m0.04 \mathrm{~m}
Option B (0.04 m0.04 \mathrm{~m}) is correct because the displacement is calculated using the wave equation with given parameters.
530 Medium
530 of 543
Understanding +4 | -1
A person blows into the open end of a long pipe. As a result, a high-pressure pulse of air travels down the pipe. When this pulse reaches the other end of the pipe,
View answer and explanation
Correct option: B
A low-pressure pulse starts travelling up the pipe, if the other end of the pipe is open
Option B is correct because when a high-pressure pulse reaches the open end of a pipe, it reflects as a low-pressure pulse due to a phase change of π\pi.
531 Medium
531 of 543
Application +4 | -1
A plane wave is described by the equation y=3cos⁡(x4−10t−π2)y = 3\cos \left( {\frac{x}{4} - 10t - \frac{\pi }{2}} \right). The maximum velocity of the particles of the medium due to this wave is
View answer and explanation
Correct option: A
30
Option A (30) is correct because the maximum particle velocity is the product of the amplitude and the angular frequency.
532 Easy
532 of 543
Understanding +4 | -1
The sound carried by air from a sitar to a listener is a wave of the following type
View answer and explanation
Correct option: D
Longitudinal progressive
Option D (Longitudinal progressive) is correct because sound waves are longitudinal, and they propagate outwards from the source.
533 Medium
533 of 543
Application +4 | -1
Two transverse sinusoidal waves travel in opposite directions along a string. The speed of transverse waves in the string is 0.5 cm s−10.5 \mathrm{~cm} \mathrm{~s}^{-1}. Each has an amplitude of 3.0 cm3.0 \mathrm{~cm} and wavelength of 6.0 cm6.0 \mathrm{~cm}. The equation for the resultant wave is
View answer and explanation
Correct option: C
Both may be correct
Option C (Both may be correct) is correct because the equation represents a standing wave formed by the superposition of two waves, and the sine and cosine functions can be interchanged depending on the initial phase.
534 Medium
534 of 543
Understanding +4 | -1
Assertion (A) : If we see the oscillations of a stretched wire at higher overtone mode, frequency of oscillation increases but wavelength decreases.

Reason (R) : From v=fλ,λ∝1fv=f \lambda, \lambda \propto \frac{1}{f} as v=v= constant.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
Option A (If both Assertion and Reason are true and the Reason is correct explanation of the Assertion) is correct because increasing the overtone mode increases frequency, which decreases wavelength given a constant velocity.
535 Medium
535 of 543
Remembering +4 | -1
The relation between frequency nn, wavelength λ\lambda and velocity vv of propagation of wave is
View answer and explanation
Correct option: C
n=vλn=\frac{v}{\lambda}
Option C (n=vλn=\frac{v}{\lambda}) is correct because the frequency of a wave is equal to its velocity divided by its wavelength, a fundamental relationship in wave physics.
536 Medium
536 of 543
Remembering +4 | -1
Sound travels in rocks in the form of:
View answer and explanation
Correct option: C
Both longitudinal and transverse elastic waves
Option C (Both longitudinal and transverse elastic waves) is correct because solids, like rocks, can support both longitudinal (compressional) and transverse (shear) waves due to their rigidity.
537 Medium
537 of 543
Understanding +4 | -1
Two tuning forks of frequency 250 Hz and 256 Hz produce beats. Then beat frequency is
View answer and explanation
Correct option: A
6 Hz
Option A is correct because the beat frequency is the absolute difference between the frequencies of the two tuning forks.
538 Medium
538 of 543
Understanding +4 | -1
When a wave travelling from one medium is
refracted into other medium, which of the
following will not change?
View answer and explanation
Correct option: C
Frequency
Option C (Frequency) is correct because the frequency of a wave remains unchanged when it travels from one medium to another, while other properties like wavelength, amplitude, and velocity change.
539 Medium
539 of 543
Understanding +4 | -1
A listener is at rest with respect to the source of sound. A wind start blowing along the line joining the source and the observer. Which of the following quantities do not change?
View answer and explanation
Correct option: B
Apparent frequency of sound
Option D (All of these) is correct because the wind affects the velocity and wavelength of sound, but since both source and listener are at rest relative to each other, the apparent frequency remains unchanged.
540 Medium
540 of 543
Understanding +4 | -1
Two periodic waves of amplitudes aa and bb pass through a region at the same time in the same direction. If a>ba > b, the difference in the maximum and minimum possible amplitudes is
View answer and explanation
Correct option: D
2b2 b
Option D (2b2b) is correct because the difference between the maximum and minimum amplitudes is calculated as (a+b)−(a−b)=2b(a+b) - (a-b) = 2b.
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