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JEE • PHYSICS • WAVES

Waves practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 451-480 of 543 questions

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451 Medium
451 of 543
Application +4 | -1
A sonometer is set on the floor of a lift. When the lift is at rest, the sonometer wire vibrates with fundamental frequency 256 Hz. When the lift goes up with acceleration a=9g16a = \frac{{9g}}{{16}} vibration of the same wire changes to
View answer and explanation
Correct option: B
320 Hz
Option B (320 Hz) is correct because the frequency changes due to the effective acceleration in the lift.
452 Medium
452 of 543
Application +4 | -1
In Quincke's experiment the sound detected is changed from a maximum to a minimum when the sliding tube is moved through a distance of 2.50 cm2.50 \mathrm{~cm}. Find the frequency of sound if the speed of sound in air is 340 ms−1340 \mathrm{~ms}^{-1}.
View answer and explanation
Correct option: A
3.4 kHz
Option A (3.4 kHz) is correct because the frequency is calculated using the relationship between wavelength, speed, and the distance the sliding tube moved.
453 Medium
453 of 543
Analyzing +4 | -1
Assertion: If a vibrating tuning fork is held near the ear and given one full rotation, then intensity of sound becomes maximum four times and minimum two times.
Reason: A stationary wave transmits energy.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because the intensity of sound becomes maximum and minimum four times each, and stationary waves do not transmit energy.
454 Medium
454 of 543
Understanding +4 | -1
Which of the following statements are true for wave motion?
View answer and explanation
Correct option: C
Mechanical transverse waves can propagate through solids only
Option C (Mechanical transverse waves can propagate through solids only) is correct because transverse waves require a medium with shear strength, which is present in solids but not in fluids.
455 Medium
455 of 543
Analyzing +4 | -1
Assertion: In a medium group velocity is greater than phase velocity.
Reason: dvdλ\frac{dv}{d\lambda} is ++ve.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false; group velocity can be less than phase velocity, and dvdλ\frac{{dv}}{{d\lambda}} can be negative.
456 Medium
456 of 543
Analyzing +4 | -1
A wave pulse in string is described by the equation y1=5(3x−4t)2+2{y}_1=\frac{5}{(3 x-4 t)^2+2} and another wave pulse in the same string is described by y2=−5(3x+4t−6)2+2{y}_2=\frac{-5}{(3 x+4 t-6)^2+2}. The values of y1,y2{y}_1, {y}_2 and x{x} are in meters and t{t} is in seconds. Which of the following statement is correct?
View answer and explanation
Correct option: C
At x=1m,y1x=1 m, y_1 and y2y_2 always cancel
Option C (At x=1m,y1x=1 m, y_1 and y2y_2 always cancel) is correct because when x=1, the equations for y1 and y2 become equal in magnitude but opposite in sign, causing them to cancel each other.
457 Medium
457 of 543
Application +4 | -1
If the speed of longitudinal waves is equal to 10 times the speed of the transverse waves in a stretched wire of material which has modulus of elasticity EE, then the stress in the wire is
View answer and explanation
Correct option: D
E100\frac{E}{100}
Option D (E100\frac{E}{100}) is correct because the stress in the wire is related to the modulus of elasticity and the ratio of longitudinal and transverse wave speeds.
458 Medium
458 of 543
Application +4 | -1
A string of length 0.4 m0.4 \mathrm{~m} and mass 10−2 kg10^{-2} \mathrm{~kg} is clamped at its ends. The tension in the string is 1.6 N1.6 \mathrm{~N}. When a pulse travels along the string, the shape of the string is found to be the same at times tt and t+Δtt+\Delta t. The value of Δt\Delta t is -
View answer and explanation
Correct option: B
0.1sec0.1 \mathrm{sec}
Option B (0.1sec0.1 \mathrm{sec}) is correct because it calculates the time interval for the pulse to travel the length of the string and return, using the wave speed and string length.
459 Medium
459 of 543
Application +4 | -1
When a train is at a distance of 2 km2 \mathrm{~km}, its engine sounds a whistle. A man near the railway track hears the whistle directly and by placing his ear against the track of the train. If the two sounds are heard att an interval of 5.2 s5.2 \mathrm{~s}, the speed of the sound in iron (material of the rail track) is

(Given that velocity of sound in air is 330 ms−1330 \mathrm{~ms}^{-1})
View answer and explanation
Correct option: A
2,325.6 ms−12,325.6 \mathrm{~ms}^{-1}
Option A (2,325.6 ms−12,325.6 \mathrm{~ms}^{-1}) is correct because it is the speed of sound in iron calculated using the time difference between hearing the sound through air and the railway track.
460 Medium
460 of 543
Application +4 | -1
The displacement yy of a particle in a medium can be expressed as y=10−6  sin⁡(100t+20x+π4)my = {10^{ - 6}}\,\,\sin \left( {100t + 20x + \frac{\pi }{4}} \right)m, where tt is in second and xx in metre. The speed of the wave is
View answer and explanation
Correct option: B
5  ms−15\,\,\mathrm{m}{\mathrm{s}^{ - 1}}
Option B (5  ms−15 \,\,\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because the wave speed is calculated by dividing the angular frequency by the wave number.
461 Medium
461 of 543
Understanding +4 | -1
With propagation of longitudinal waves through a medium, the quantity transmitted is
View answer and explanation
Correct option: B
Energy
Option B (Energy) is correct because longitudinal waves transmit energy through a medium without transferring matter.
462 Medium
462 of 543
Application +4 | -1
A train moves towards a stationary observer with speed 34  ms−134\,\,m{s^{ - 1}}. The train sounds a whistle and its frequency registered by the observer is v1{v_1}. If the train’s speed is reduced to 17  ms−117\,\,m{s^{ - 1}}, the frequency registered is v2{v_2}. If the speed of sound is 340  ms−1340\,\,m{s^{ - 1}}, then the ratio v1/v2{v_1}/{v_2} is
View answer and explanation
Correct option: D
19/1819/18
Option D (19/1819/18) is correct because it is the ratio of the frequencies calculated using the Doppler effect formula for a moving source and a stationary observer.
463 Medium
463 of 543
Application +4 | -1
Four wires of identical length, diameters and of the same material are stretched on a sonometre wire. If the ratio of their tensions is 1:4:9:161\mathrm{ }:\mathrm{ }4\mathrm{ }:\mathrm{ }9\mathrm{ }:\mathrm{ }16 then the ratio of their fundamental frequencies are
View answer and explanation
Correct option: D
1:2:3:41\mathrm{ }:\mathrm{ }2\mathrm{ }:\mathrm{ }3\mathrm{ }:\mathrm{ }4
Option D (1:2:3:41\mathrm{ }:\mathrm{ }2\mathrm{ }:\mathrm{ }3\mathrm{ }:\mathrm{ }4) is correct because the fundamental frequency of a sonometer wire is directly proportional to the square root of the tension.
464 Medium
464 of 543
Understanding +4 | -1
Assertion: Longitudinal waves are called pressure waves.
Reason: Propagation of longitudinal waves through a medium involves changes in pressure (density of medium particles), when compressions and rarefactions are formed.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because longitudinal waves cause pressure variations in the medium, creating compressions and rarefactions.
465 Medium
465 of 543
Application +4 | -1
Three resonant frequencies of string with both rigid ends are 90,150 and 210 Hz210 \mathrm{~Hz}. If the length of the string is 80 cm80 \mathrm{~cm}, what is the speed of the transverse wave in the string?
View answer and explanation
Correct option: C
48 m/s48 \mathrm{~m} / \mathrm{s}
Option C (48 m/s48 \mathrm{~m} / \mathrm{s}) is correct because it is derived from the relationship between resonant frequencies, string length, and wave speed.
466 Medium
466 of 543
Understanding +4 | -1
When a sound wave goes from one medium to another, the quantity that remains unchanged is
View answer and explanation
Correct option: A
Frequency
Option A (Frequency) is correct because the frequency of a wave is determined by the source and remains constant when the wave travels from one medium to another, while speed and wavelength can change.
467 Medium
467 of 543
Understanding +4 | -1
A pulse of a wave train travels along a stretched string and reaches the fixed end of the string. It will be reflected with
View answer and explanation
Correct option: C
A phase change of 180∘180^\circ with no reversal of velocity
Option A is correct because when a wave reflects from a fixed end, it undergoes a phase change of 180 degrees, but its velocity direction remains the same.
468 Medium
468 of 543
Understanding +4 | -1
Assertion: Explosions on other planets are not heard on earth.
Reason: To hear distinct beats difference infrequencies of two sources should be less than 10.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct. Explosions need a medium to travel, and the beat frequency limit is unrelated.
469 Medium
469 of 543
Application +4 | -1
The source producing sound and an observer both are moving along the direction of propagation of sound waves. If the respective velocities of sound, source and an observer are v,vsv, v_s and vov_o, then the apparent frequency heard by the observer will be: (n=n= frequency of sound)
View answer and explanation
Correct option: B
n(v−vo)v−vs\frac{n\left(v-v_o\right)}{v-v_s}
Option B is correct because the apparent frequency is given by the Doppler effect formula when both the source and observer are moving along the direction of propagation.
470 Medium
470 of 543
Understanding +4 | -1
Statement-I: In propagation of sound waves, pressure amplitude is proportional to the displacement amplitude.
Statement-II: Suppose the source and observer both are stationary and wind is blowing in a direction from source to observer, then the observer detects an apparent increase in frequency.
View answer and explanation
Correct option: A
Statement-I is correct
Option A (Statement-I is correct) is correct because pressure amplitude is indeed proportional to the displacement amplitude in sound wave propagation.
471 Medium
471 of 543
Application +4 | -1
The equation of a wave on a string of linear mass density 0.04  kgm−10.04\,\,kg{m^{ - 1}} is given by y=0.02(m)  sin⁡[2π(t0.04(s)−x0.50(m))]y = 0.02\left( m \right)\,\,\sin \left[ {2\pi \left( {\frac{t}{{0.04\left( s \right)}} - \frac{x}{{0.50\left( m \right)}}} \right)} \right]. The tension in the string is
View answer and explanation
Correct option: A
6.25  N6.25\,\,N
Option A (6.25 N6.25\,N) is correct because it is the tension in the string calculated using the wave equation and linear mass density.
472 Medium
472 of 543
Understanding +4 | -1
If the speed of a wave doubles as it passes from shallow water deeper water, its wavelength will be
View answer and explanation
Correct option: C
Doubled
Option C (Doubled) is correct because the wavelength is directly proportional to the speed of the wave when the frequency remains constant.
473 Medium
473 of 543
Understanding +4 | -1
In a stationary wave
View answer and explanation
Correct option: B
Strain is maximum at nodes
Option B (Strain is maximum at nodes) is correct because nodes are points of zero displacement in a stationary wave, implying maximum strain or deformation.
474 Medium
474 of 543
Analyzing +4 | -1
Assertion: The change in air pressure affects the speed of sound.
Reason: The speed of sound in a gas is proportional to square root of pressure.
View answer and explanation
Correct option: D
If reason is true but assertion is false
The correct answer is D because the assertion is false (air pressure doesn't affect sound speed) while the reason is true (sound speed is proportional to the square root of pressure in the formula, but density also changes with pressure).
475 Medium
475 of 543
Application +4 | -1
A motorcyclist going around a circular track of radius 50 m50 \mathrm{~m} with a speed of 25 m/s25 \mathrm{~m} / \mathrm{s}, is at a point X{X}. A static siren at Y{Y} is emitting sound of frequency n{n}. How many times (approximately) in an hour will the motor cyclist hear the sound of actual frequency Y?{Y}?
View answer and explanation
Correct option: D
573
Option D (573) is correct because the motorcyclist hears the actual frequency twice per round, and we calculate the number of rounds per hour.
476 Medium
476 of 543
Application +4 | -1
Two aeroplanes AA and BB are approaching cach other and their velocities are 108 km h−1108 \mathrm{~km} \mathrm{~h}^{-1} and 144 km h−1144 \mathrm{~km} \mathrm{~h}^{-1} respectively. The frequency of a note emitted by AA as heard by the passengers in BB is 1170 Hz1170 \mathrm{~Hz}. Calculate the frequency of the note heard by the passenger in A. Velocity of sound =350 ms−1=350 \mathrm{~ms}^{-1}.
View answer and explanation
Correct option: A
960 Hz960 \mathrm{~Hz}
Option A (960 Hz960 \mathrm{~Hz}) is correct because it is calculated using the Doppler effect formula, considering both the source and observer are moving towards each other.
477 Medium
477 of 543
Understanding +4 | -1
The beats are the examples of
View answer and explanation
Correct option: B
interference of two or more waves having same amplitude but slightly different frequencies in the same direction
Option B is correct because beats are formed due to the interference of two or more waves with the same amplitude but slightly different frequencies traveling in the same direction.
478 Medium
478 of 543
Analyzing +4 | -1
The amplitude of a wave is given by AA =ca+b+c= \frac{c}{{a + b + c}} . Resonance will occur when
View answer and explanation
Correct option: C
b=0,a=cb = 0,a = c
The correct answer is C (b=0,a=cb = 0, a = c) because resonance occurs when the amplitude is maximized, which happens when the denominator is minimized, i.e., a + b + c is minimized.
479 Medium
479 of 543
Application +4 | -1
Two organ (open) pipes of length 50 cm and 51 cm produce ‘6’ beats/s. Then the speed of sound is nearly
View answer and explanation
Correct option: B
306 m/s
Option B (306 m/s) is correct because the speed of sound is calculated using the beat frequency and the lengths of the open organ pipes.
480 Medium
480 of 543
Application +4 | -1
Two sound sources emit the sounds of same frequency ff. An observer is at the mid-way between the sources on the line joining them. When he starts moving towards one source with speed v/20{v} / 20, where ' vv ' is speed of sound, he hears 10 beats per second. The value of ' f{f} ' is
View answer and explanation
Correct option: B
100 Hz100 {~Hz}
Option B (100 Hz100 {~Hz}) is correct because it's the frequency calculated based on the observed beat frequency and the observer's speed.
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