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JEE • PHYSICS • WAVES

Waves practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 421-450 of 543 questions

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421 Medium
421 of 543
Understanding +4 | -1
Statement-I: If all the particles of a string are oscillating in same phase, the string is resonating in its fundamental tone.
Statement-II: A sound wave is propagating through the medium, when the particle moves in the opposite direction to the propagation of the wave, it is in a region of rarefaction.
View answer and explanation
Correct option: C
Both statement-I &\& II are correct
Option C is correct because both statements are true regarding string resonance and sound wave propagation.
422 Medium
422 of 543
Understanding +4 | -1
With reference to Doppler effect in sound ,when the listener is moving towards a stationary source, which of the following is true regarding frequency and wavelength of wave observed by the listener?
View answer and explanation
Correct option: D
More frequency, constant wavelength
Option D (More frequency, constant wavelength) is correct because when a listener moves towards a stationary source, the observed frequency increases, but the wavelength remains unchanged.
423 Medium
423 of 543
Application +4 | -1
A train of sound waves is propagated along a wide pipe and it is reflected from an open end. If the amplitude of the waves is 0.002 cm0.002 \mathrm{~cm}, the frequency is 1000 Hz1000 \mathrm{~Hz} and the wavelength is 40 cm40 \mathrm{~cm}, the amplitude of vibration at a point 10 cm10 \mathrm{~cm} from open end inside the pipe will be
View answer and explanation
Correct option: A
zero
Option A (zero) is correct because at a distance of λ/4\lambda/4 from an open end, there is a node where the amplitude of vibration is zero.
424 Medium
424 of 543
Understanding +4 | -1
The velocity of sound is generally greater in solids than in gases because
View answer and explanation
Correct option: B
The density of solids is high, but the elasticity of
solids is very high
Option B (The density of solids is high, but the elasticity of solids is very high) is correct because the velocity of sound depends on both density and elasticity, with elasticity having a greater impact.
425 Medium
425 of 543
Understanding +4 | -1
What is the ratio of the frequency of fourth overtone to the fundamental frequency of a stretched string?
View answer and explanation
Correct option: A
51\frac{5}{1}
Option A is correct because the frequency of the fourth overtone is five times the fundamental frequency.
426 Medium
426 of 543
Understanding +4 | -1
Assertion: Waves generated in a metal piece can be transverse or longitudinal.
Reason: Waves generated depend upon the method of creating waves in the metal.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because the type of wave generated in a metal piece (transverse or longitudinal) depends on the method used to create the wave.
427 Medium
427 of 543
Application +4 | -1
A transverse wave propagating along xx-axis is represented by y(x,t)=8.0sin⁡(0.5πx−4πt−π/4)y(x, t)=8.0 \sin (0.5 \pi x-4 \pi t-\pi / 4) where xx is in metres and tt is in seconds. The speed of the wave is
View answer and explanation
Correct option: A
8 m/s8 \mathrm{~m} / \mathrm{s}
Option A (8 m/s8 \mathrm{~m} / \mathrm{s}) is correct because the wave speed is calculated by dividing the angular frequency by the wave number.
428 Medium
428 of 543
Analyzing +4 | -1
A tuning fork produces 4 beats per second with another tuning fork of frequency 256 Hz256 \mathrm{~Hz}. The first one is now loaded with a little wax and the beat frequency is found to increase to 6 per second. What was the original frequency of the tuning fork?
View answer and explanation
Correct option: A
252 Hz
Option A (252 Hz) is correct because loading the tuning fork decreases its frequency, and the beat frequency increases from 4 to 6, indicating the original frequency was lower than 256 Hz.
429 Medium
429 of 543
Understanding +4 | -1
Which of the following equations represents a wave travelling along yy-axis
View answer and explanation
Correct option: B
x=A  sin⁡(ky−ωt)x = A\,\,\sin \left( {ky - \omega t} \right)
Option B (x=A sin⁡(ky−ωt)x = A\,\sin \left( {ky - \omega t} \right)) is correct because it represents a wave function where the displacement 'x' is a function of (ky - ω t), indicating propagation along the y-axis.
430 Medium
430 of 543
Application +4 | -1
The mass of 1 mol1 {~mol} of air is 29×10−3 kg29 \times 10^{-3} {~kg}, then the speed of sound (in m/s{m} / {s} ) in air at standard temperature and pressure is.....
View answer and explanation
Correct option: A
332.5
Option C (750 m) is correct because it is the distance the man is carried downstream, calculated by multiplying the river's speed by the time it takes the man to cross the river.
431 Medium
431 of 543
Remembering +4 | -1
In Laplace correction the propagation of sound wave in gas is an _____ process.
View answer and explanation
Correct option: A
Adiabatic
Option A (Adiabatic) is correct because Laplace corrected Newton's formula by assuming the sound wave propagation in gas is an adiabatic process.
432 Medium
432 of 543
Application +4 | -1
Standing waves are produced in 20 m20 \mathrm{~m} long stretched string fixed at both ends. If the string vibrates in 10 segments and wave velocity is 20 m/s\mathrm{m} / \mathrm{s}, then frequency of vibration is
View answer and explanation
Correct option: C
5 Hz5 \mathrm{~Hz}
Option A ((a) Ftm;\frac{F t}{m}; (b) 6Ftml\frac{6 F t}{m l}) is correct because it correctly applies the impulse-momentum theorem and the angular impulse-momentum theorem.
433 Medium
433 of 543
Application +4 | -1
If the frequency of sound produced by a siren increases from 400 Hz400 \mathrm{~Hz} to 1200 Hz1200 \mathrm{~Hz} while the wave amplitude remains constant, the ratio of the intensity of the 1200 Hz1200 \mathrm{~Hz} to that of the 400 Hz400 \mathrm{~Hz} wave will be
View answer and explanation
Correct option: D
9:19: 1
Option D (9:19: 1) is correct because the intensity of a sound wave is proportional to the square of its frequency, so when the frequency triples, the intensity increases by a factor of nine.
434 Medium
434 of 543
Analyzing +4 | -1
A wave represented by the given equation y=acos⁡(kx−ωt)y=a \cos (k x-\omega t) is superposed with another wave to form a stationary wave such that the point x=0x=0 is a node. The equation for the other wave is
View answer and explanation
Correct option: B
y=−acos⁡(kx+ωt)y=-a \cos (k x+\omega t)
Option B (y=−acos⁡(kx+ωt)y=-a \cos (k x+\omega t)) is correct because when superposed with y=acos⁡(kx−ωt)y=a \cos (k x-\omega t), it creates a stationary wave with a node at x=0 due to the phase difference of π\pi.
435 Medium
435 of 543
Analyzing +4 | -1
Assertion: On a rainy day sound travels slower than on a dry day.
Reason: When moisture is present in air the density of air increases.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because sound travels faster on a rainy day due to lower density of moist air.
436 Medium
436 of 543
Analyzing +4 | -1
Choose the correct statement from the following options.
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because all three statements regarding the speed of sound, sound absorption, and adiabatic processes are accurate.
437 Medium
437 of 543
Understanding +4 | -1
What is the effect of increase in temperature on the frequency of sound produced by an organ pipe?
View answer and explanation
Correct option: A
increases
Option A (increases) is correct because the speed of sound increases with temperature, leading to an increase in frequency.
438 Medium
438 of 543
Application +4 | -1
A set of 16 tuning forks are so arranged that each produce 4 beats with the previous one. If the frequency of last tuning fork is double that of first, the frequency of third tuning fork is
View answer and explanation
Correct option: A
68 Hz68 \mathrm{~Hz}
Option A (68 Hz) is correct because the frequency of each subsequent tuning fork increases by 4 Hz, and the frequency of the third tuning fork can be calculated accordingly.
439 Medium
439 of 543
Application +4 | -1
A Kundt's tube apparatus has a copper rod of length 1.0 m1.0 \mathrm{~m} clamped at 25 cm25 \mathrm{~cm} from one of the ends. The tube contains air in which the speed of sound is 340 m/s340 \mathrm{~m} / \mathrm{s}. The powder collects in heaps separated by a distance of 5.0 cm5.0 \mathrm{~cm}. Find the speed of sound waves in copper.
View answer and explanation
Correct option: A
3400 m/s
Option A (3400 m/s) is correct because the speed of sound waves in copper is calculated using the relationship between the speed of sound in the rod and the air, and the lengths of the rod and the distance between heaps.
440 Medium
440 of 543
Understanding +4 | -1
Statement-I: In transverse wave particle velocity is perpendicular to wave velocity.
Statement-II: In a longitudinal wave particle velocity is along the direction of propagation of wave.
View answer and explanation
Correct option: C
Both statement-I &\& II are correct
Option C (Both statement-I &IIarecorrect)iscorrectbecauseitaccuratelydescribestherelationshipbetweenparticleandwavevelocitiesintransverseandlongitudinalwaves.\& II are correct) is correct because it accurately describes the relationship between particle and wave velocities in transverse and longitudinal waves.
441 Medium
441 of 543
Understanding +4 | -1
A linearly polarised electromagnetic wave in vacuum is E=3.1cos⁡ [(1.8)z−(5.4×106)t]   i^  N/CE = 3.1\cos \,[(1.8)z - (5.4 \times {10^6})t]\,\,\widehat {\,i}\,\,N/C is incident
normally on a perfectly reflecting wall at z=az = a.
Choose the correct option.
View answer and explanation
Correct option: D
The reflected wave will be 3.1cos⁡[(1.8)z+(5.4×106)t]  i^  N/C3.1\cos [(1.8)z + (5.4 \times {10^6})t]\,\,\widehat i\;N/C
Option D is correct because the reflected wave will have the same amplitude and frequency, but the direction of propagation will be reversed, resulting in a change in sign in front of the z term.
442 Medium
442 of 543
Application +4 | -1
Each of the two strings of length 51.6  cm51.6\,\,cm and 49.1  cm49.1\,\,cm are tensioned separately by 20  N20\,\,N force. Mass per unit length of both the strings is same and equal to 1  g/m1\,\,g/m. When both the string vibrate simultaneously the number of beats is
View answer and explanation
Correct option: B
77
Option B (7) is correct because it is the number of beats calculated from the difference in frequencies of the two strings, using the formula for frequency of a vibrating string.
443 Medium
443 of 543
Application +4 | -1
A source oscillates with a frequency 25 Hz25 \mathrm{~Hz} and the wave propagates with 300 m/s300 \mathrm{~m} / \mathrm{s}. Two points AA and BB are located at distances 10 m10 \mathrm{~m} and 16 m16 \mathrm{~m} away from the source. The phase difference between AA and BB is
View answer and explanation
Correct option: C
π\pi
Option C (π\pi) is correct because the phase difference is calculated using the formula Δϕ=2πλΔx\Delta \phi = \frac{{2 \pi}}{\lambda} \Delta x, where Δx\Delta x is the path difference.
444 Medium
444 of 543
Analyzing +4 | -1
Assertion (A): The fundamental frequency of an organ pipe decreases as the temperature increases.
Reason (R): As the temperature increases, the velocity of sound increases more rapidly than length of the pipe during expansion.
View answer and explanation
Correct option: D
Assertion (A) is false, and Reason (R) is true
Option D is correct. The assertion is false because the fundamental frequency increases with temperature, while the reason is true because the velocity of sound increases more rapidly than the length of the pipe.
445 Medium
445 of 543
Application +4 | -1
If L1{L_1} and L2{L_2} are the lengths of the first and second resonating air columns in a resonance tube, then the wavelength of the note produced is
View answer and explanation
Correct option: B
2(L2−L1)2\left( {{L_2} - {L_1}} \right)
Option B (2(L2−L1)2\left( {{L_2} - {L_1}} \right)) is correct because the wavelength is twice the difference between the second and first resonating lengths in a resonance tube experiment.
446 Medium
446 of 543
Understanding +4 | -1
Which two of the given transverse waves will give stationary waves when get superimposed
z1=acos⁡(kx−ωt){z_1} = a\cos \left( {kx - \omega t} \right) …(AA)
z2=acos⁡(kx+ωt){z_2} = a\cos \left( {kx + \omega t} \right) …(BB)
z3=acos⁡(ky−ωt){z_3} = a\cos \left( {ky - \omega t} \right) …(CC)
View answer and explanation
Correct option: A
A  and  B\begin{array}{llllllllllllllllllll} {A\,\,and\,\,B} \end{array}
Option A (A and B) is correct because stationary waves are formed by the superposition of two waves with the same amplitude and frequency traveling in opposite directions.
447 Easy
447 of 543
Understanding +4 | -1
To decrease the fundamental frequency of a stretched string fixed at both ends. Which of the following option is correct?
View answer and explanation
Correct option: C
Increase its length
Option C (Increase its length) is correct because the fundamental frequency is inversely proportional to the length of the string.
448 Medium
448 of 543
Understanding +4 | -1
Two tuning forks of frequencies 512 Hz512 \mathrm{~Hz} and 524 Hz524 \mathrm{~Hz} respectively are vibrated simultaneously. The beat frequency heard will be-
View answer and explanation
Correct option: B
Beats will not be heard
Option C (12 Hz12 \mathrm{~Hz}) is correct because the beat frequency is the absolute difference between the two frequencies, which is 12 Hz.
449 Medium
449 of 543
Analyzing +4 | -1
Assertion (A) : Two waves y1=Asin⁡(ωt+kx)y_1=A \sin (\omega t+k x) and y2=Acos⁡(ωt−kx)y_2=A \cos (\omega t-k x) are superimposed, then x=0x=0 becomes a node.

Reason (R) : At node net displacement due to two waves should be zero.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D (If Assertion is false but the Reason is true) is correct because the assertion is false as x=0 is not a node, but the reason is true as a node requires zero net displacement.
450 Medium
450 of 543
Understanding +4 | -1
Assertion (A): When a transverse wave propagates along a string it transports energy in two forms : kinetic energy and potential energy.
Reason (R): A transverse pulse reflected from a fixed end gets inverted.
View answer and explanation
Correct option: B
Both Assertion and Reason are true but Reason is not the correct explanation of Assertion
Option B is correct because both the assertion and reason are true, but the reason does not explain the assertion. The energy transport and pulse inversion are independent phenomena.
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