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JEE • PHYSICS • WAVES

Waves practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 543 questions

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301 Medium
301 of 543
Understanding +4 | -1
When a stationary wave is formed then its frequency is
View answer and explanation
Correct option: A
Same as that of the individual waves
Option A (Same as that of the individual waves) is correct because the frequency of a stationary wave is the same as the frequency of the interfering waves.
302 Medium
302 of 543
Application +4 | -1
When a sound wave of wavelength λ\lambda is propagating in a medium, the maximum velocity of the particle is equal to the velocity. The amplitude of wave is
View answer and explanation
Correct option: C
λ2π\frac{\mathrm{\lambda }}{{2\mathrm{\pi }}}
Option C (λ2π\frac{\mathrm{\lambda }}{{2\mathrm{\pi }}}) is correct because it is derived by equating the maximum particle velocity to the wave velocity and solving for the amplitude.
303 Easy
303 of 543
Application +4 | -1
Pulse rate of a normal person is 75 per minute. The time period of heart is [in seconds]
View answer and explanation
Correct option: A
0.8
Option A (0.8) is correct because the time period is the inverse of the frequency, which is calculated from the pulse rate.
304 Medium
304 of 543
Understanding +4 | -1
If wave y=a  cos⁡(ωt+kx)y = a\,\,\cos \left( {\omega t + kx} \right) is moving along x−axisx - axis, the shape of pulse at t=0  and  t=2 st = 0\,\,and\,\,t = 2\,s
View answer and explanation
Correct option: B
Are same
Option B (Are same) is correct because the shape of the wave remains the same at different times, only its position changes.
305 Medium
305 of 543
Application +4 | -1
A tuning fork of frequency 200Hz200\mathrm{ }Hz is in unison with a sonometer wire. The number of beats heard per second when the tension is increased by 1%1\% is
View answer and explanation
Correct option: A
11
Option A (1) is the correct answer because the number of beats is equal to the difference in frequencies, which is calculated to be 1 Hz when the tension is increased by 1%.
306 Medium
306 of 543
Understanding +4 | -1
Assertion: Due to end correction fundamental frequency of any pipe becomes less than frequency without end correction.
Reason: Due to end correction effective length of pipe increases.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
The correct answer is A (If both Assertion & reason are True & the Reason is a correct explanation of the Assertion) because end correction increases the effective length of the pipe, which lowers the fundamental frequency.
307 Medium
307 of 543
Understanding +4 | -1
Two points P and Q have a phase difference of π\pi when a travelling sine wave passes through the region.
Statement-I: P and Q move in opposite directions.
Statement-II: P oscillates at half the frequency of Q.
View answer and explanation
Correct option: A
Statement-I is correct
Option A (Statement-I is correct) is correct because two points with a phase difference of π\pi in a traveling sine wave move in opposite directions.
308 Medium
308 of 543
Analyzing +4 | -1
The mathematical form of three travelling waves are given by

y1=(2 cm)sin⁡(3x−6t),y2=(3 cm)sin⁡(4x−12t),  and y3=(4 cm)sin⁡(5x−11t)\begin{aligned} & y_1=(2 {~cm}) \sin (3 x-6 t), \\ & y_2=(3 {~cm}) \sin (4 x-12 t) \text {, } \\ & \text { and } y_3=(4 {~cm}) \sin (5 x-11 t) \\ \end{aligned}

of these waves,
View answer and explanation
Correct option: D
Wave 2 has greatest wave speed and wave 3 has maximum transverse string speed
Option D (Wave 2 has greatest wave speed and wave 3 has maximum transverse string speed) is correct because wave speed is ω/k\omega/k and maximum transverse speed is AωA\omega.
309 Medium
309 of 543
Understanding +4 | -1
What is the phase difference between the displacement wave and pressure wave in a sound wave?
View answer and explanation
Correct option: B
π2\frac{\pi}{2}
Option B (π2\frac{\pi}{2}) is correct because the pressure wave is 90 degrees out of phase with the displacement wave in a sound wave.
310 Medium
310 of 543
Application +4 | -1
The equation of sound wave is
y=0.0015  sin⁡(62.4x  +  316 t)y = 0.0015\,\,\sin \left( {62.4x\,\, + \,\,316\,t} \right)
The wavelength of this wave is
View answer and explanation
Correct option: B
0.1unit\begin{array}{llllllllllllllllllll} {0.1\mathrm{ }unit} \end{array}
Option B (0.1unit\begin{array}{llllllllllllllllllll}{0.1\mathrm{ }unit}\end{array}) is correct because the wavelength is calculated from the wave number (k) in the given equation.
311 Medium
311 of 543
Application +4 | -1
The equation of a simple harmonic wave is given by y=6  sin⁡  2π(2t−0.1x)y = 6\,\,\sin \,\,2\pi \left( {2t - 0.1x} \right) where x and y are in mm and t is in seconds. The phase difference between two particles 2 mm apart at any instant is
View answer and explanation
Correct option: B
72∘72^\circ
Option B (72∘72^\circ) is correct because the phase difference is calculated using the wave number and the distance between the particles.
312 Medium
312 of 543
Application +4 | -1
A plane wave is described by the equation y=3cos⁡(x4−10t−π2)y = 3\cos \left( {\frac{x}{4} - 10t - \frac{\pi }{2}} \right). The maximum velocity of the particles of the medium due to this wave is
View answer and explanation
Correct option: A
30
Option A (30) is correct because the maximum particle velocity is the product of the amplitude and the angular frequency.
313 Medium
313 of 543
Remembering +4 | -1
Echo is based on which amongst the given phenomenon that sound wave follows?
View answer and explanation
Correct option: B
Reflection
Option B (Reflection) is correct because an echo is formed when sound waves bounce off a surface and return to the listener, which is the definition of reflection.
314 Medium
314 of 543
Understanding +4 | -1
When a tuning fork produces sound waves in air, which one of the following is same in the material of tuning fork as well as in air?
View answer and explanation
Correct option: B
frequency
Option B (frequency) is correct because the frequency of a sound wave is determined by the source (tuning fork) and remains constant regardless of the medium it travels through.
315 Medium
315 of 543
Application +4 | -1
A sound wave of frequency vv propagating through air with a velocity cc, is reflected from a surface which is moving away from the source with a constant speed vv. the frequency of the reflected wave, measured by the observed at the position of the source, is
View answer and explanation
Correct option: C
v(c+2v)c+v\frac{{v\left( {c + 2v} \right)}}{{c + v}}
Option C (v(c+2v)c+v\frac{{v\left( {c + 2v} \right)}}{{c + v}}) is correct because it correctly applies the Doppler effect formula for a wave reflected from a moving surface, considering both the moving source and moving observer.
316 Medium
316 of 543
Application +4 | -1
The fundamental note produced by a closed organ pipe is of frequency ff. The fundamental note produced by an open organ pipe of same length will be of frequency
View answer and explanation
Correct option: C
2f2f
Option C (2f2f) is correct because the fundamental frequency of an open organ pipe is twice that of a closed organ pipe of the same length.
317 Medium
317 of 543
Understanding +4 | -1
Doppler shift in frequency does not depend upon
View answer and explanation
Correct option: D
Distance from the source to the listener
Option D (Distance from the source to the listener) is correct because the Doppler shift in frequency depends on the relative velocities of the source and observer, and the frequency of the wave, but not on the distance between them.
318 Medium
318 of 543
Remembering +4 | -1
The ratio of speed of source to the speed of sound is called
View answer and explanation
Correct option: B
Mach number
Option B (Mach number) is correct because the Mach number is defined as the ratio of the speed of a source to the speed of sound.
319 Medium
319 of 543
Understanding +4 | -1
Beats are produced by two travelling waves each of loudness II and nearly equal frequencies n1{n_1} and n2{n_2}. The beat frequency will be and maximum loudness hard will be
View answer and explanation
Correct option: B
(n1−n2),4I\left( {{n_1} - {n_2}} \right),4I
Option B ((n1−n2),4I\left( {{n_1} - {n_2}} \right),4I) is correct because the beat frequency is the difference in frequencies and the maximum loudness is four times the individual loudness.
320 Medium
320 of 543
Analyzing +4 | -1
Assertion: Where two vibrating tuning forks having frequencies 256 Hz256 \mathrm{~Hz} and 512 Hz512 \mathrm{~Hz} are held near each other, beats cannot be heard.
Reason: The principle of superposition is valid only if the frequencies of the oscillators are nearly equal.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
Option C (If assertion is true, but reason is false) is correct because while beats are not heard, the principle of superposition applies regardless of frequency difference.
321 Medium
321 of 543
Application +4 | -1
Two air columns (of resonance tubes) 100 cm100 \mathrm{~cm} and 101 cm101 \mathrm{~cm} long give 17 beats in 20 seconds, when each is sounding its fundanental mode. Calculate the velocity of sound.
View answer and explanation
Correct option: B
343.4 ms−1343.4 \mathrm{~ms}^{-1}
Option B (343.4 ms−1343.4 \mathrm{~ms}^{-1}) is correct because the velocity of sound is calculated using the beat frequency and the lengths of the air columns in the resonance tubes.
322 Medium
322 of 543
Remembering +4 | -1
Frequency range of the audible sound is
View answer and explanation
Correct option: B
20 Hz−20 kHz20 \mathrm{~Hz}-20 \mathrm{~kHz}
Option B (20 Hz−20 kHz20 \mathrm{~Hz}-20 \mathrm{~kHz}) is correct because this is the generally accepted range of frequencies that humans can hear.
323 Medium
323 of 543
Application +4 | -1
A wave of frequency 500  Hz500\,\,Hz has velocity 360  m/sec360\,\,m/sec. The distance between two nearest points 600{60^0} out of phase, is
View answer and explanation
Correct option: B
12  cm12\,\,cm
Option B (12  cm12\,\,cm) is correct because the distance between two points 600{60^0} out of phase is calculated using the formula Δ=λ2π×ϕ\Delta = \frac{\lambda }{{2\pi }} \times \phi.
324 Medium
324 of 543
Remembering +4 | -1
Maximum number of beats frequency heard by a human being is
View answer and explanation
Correct option: A
1010
Option A (10) is correct because the persistence of hearing is approximately 0.1 seconds, limiting the maximum distinguishable beat frequency to around 10 Hz.
325 Medium
325 of 543
Application +4 | -1
The fundamental frequency of a closed end organ pipe is nn. Its length is doubled and radius is halved. Its frequency will be become nearly
View answer and explanation
Correct option: A
n/2n/2
Option A (n/2n/2) is correct because the fundamental frequency of a closed pipe is inversely proportional to its length, and doubling the length halves the frequency.
326 Medium
326 of 543
Application +4 | -1
A standing wave is maintained in a homogeneous string of cross-sectional area ss and density ρ\rho. It is formed by the superposition of two waves travelling in opposite directions given by the equation y1=asin⁡(ωt−kx)y_1=a \sin (\omega t-k x) and y2=2asin⁡(ωt+kx)y_2=2 a \sin (\omega t+k x). The total mechanical energy confined between the sections corresponding to the adjacent antinodes is
View answer and explanation
Correct option: C
5πspω2a22k\frac{5 \pi s p \omega^2 a^2}{2 k}
The correct answer is C. The total mechanical energy is calculated by summing the energy densities of the two waves and multiplying by the volume between adjacent antinodes.
327 Medium
327 of 543
Application +4 | -1
Calculate the fundumental frequency of a sonometer wire of length =20 cm=20 \mathrm{~cm} tension 25 N25 \mathrm{~N}, crosssectional aren =10−2 cm2=10^{-2} \mathrm{~cm}^2 and density of the material of wire =104 kg m−3=10^4 \mathrm{~kg} \mathrm{~m}^{-3}.
View answer and explanation
Correct option: B
125 Hz125 \mathrm{~Hz}
Option B (125 Hz125 \mathrm{~Hz}) is correct because it is the fundamental frequency calculated using the given parameters of the sonometer wire.
328 Medium
328 of 543
Understanding +4 | -1
If waves are originating from point source, then amplitude (A)(A) at a distance (r)(r) from the source are related as
View answer and explanation
Correct option: C
A∝1rA \propto \frac{1}{r}
Option C (A∝1rA \propto \frac{{1}}{{r}}) is correct because the intensity of a wave from a point source decreases with the square of the distance, and intensity is proportional to the square of the amplitude.
329 Medium
329 of 543
Analyzing +4 | -1
Assertion: For same length but different gas COP fundamental wavelength remain same.
Reason: Here length is same.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & reason are True & the Reason is a correct explanation of the Assertion) is correct because the fundamental wavelength depends only on the length of the tube for the same mode of vibration.
330 Medium
330 of 543
Understanding +4 | -1
I. In a standing wave, energy is transmitted from one region of space to other.

II. In a standing wave, all the particles cross their mean position together.

Which of the above statement(s) is/are correct?
View answer and explanation
Correct option: B
Only II
Option B (Only II) is correct because in a standing wave, energy is not transmitted, and all particles at a node cross their mean position together.
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