a segment of wire vibrates with a fundamental frequency of $450\,\,Hz$ under a tension of $9{\rm{ }}kg - wt$. then tension at which the fundamental frequency of the same wire becomes $900\,\,Hz$ is

JEE PHYSICS MCQ: WAVES

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Application +4 | -1

a segment of wire vibrates with a fundamental frequency of

450\,\,Hz

under a tension of

9\mathrm{ }kg - wt

. then tension at which the fundamental frequency of the same wire becomes

900\,\,Hz

View answer and explanation

Correct option: A

36\mathrm{ }kg - wt

Option A (

36\mathrm{ }kg - wt

) is correct because the frequency is proportional to the square root of the tension, so doubling the frequency requires quadrupling the tension.

Practice All Chapter MCQs →

3\,\,kHz

0.5

f\mathrm{ }Hz

V\mathrm{ }m/sec

0.2\,\,V

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

(– \mathrm{ve}) \,x

y = f(kx +\omega t),

X

0.01\,\,s

5 \mathrm{~m}

245 \mathrm{~g}

1 \mathrm{~kg}

g=980 \mathrm{~cm} \mathrm{~s}^{-2}

T

V