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JEE • PHYSICS • WAVE OPTICS

Wave optics practice · Medium

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Showing 151-180 of 396 questions

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151 Medium
151 of 396
Application +4 | -1
Ratio of intensities of two waves from slits S1S_1 and S2S_2 is 4:14: 1 respectively. Then the ratio of maximum to that of minimum intensities in YDSEYDSE is
View answer and explanation
Correct option: B
9:19: 1
Option B (9:19: 1) is correct because it is the ratio of the maximum to minimum intensities calculated from the given ratio of intensities of the two waves.
152 Medium
152 of 396
Understanding +4 | -1
The rectilinear propagation of light in a medium is due to
View answer and explanation
Correct option: C
Its high velocity
Option C (Its high velocity) is correct because light travels at a very high speed, causing it to experience negligible gravitational force and thus propagate in a straight line.
153 Medium
153 of 396
Understanding +4 | -1
Two beams of light will not give rise to an interference pattern, if
View answer and explanation
Correct option: D
They are not monochromatic
The correct answer is D (They are not monochromatic) because interference requires coherent and monochromatic light sources.
154 Medium
154 of 396
Application +4 | -1
Two points, separated by a distance of 0.1  mm\mathrm{0}\mathrm{.1}\,\,\mathrm{mm}, can just be inspected on a microscope when light of wavelength 6000 A∘6000\,\mathop \mathrm{A}\limits^ \circ is used. If the light of wavelength 4800 A∘4800\,\mathop \mathrm{A}\limits^ \circ is used, the limit of resolution is
View answer and explanation
Correct option: B
0.08  mm\mathrm{0}\mathrm{.08}\,\,\mathrm{mm}
Option B (0.08 mm\mathrm{0}\mathrm{.08}\,\mathrm{mm}) is correct because the limit of resolution is directly proportional to the wavelength of light used.
155 Medium
155 of 396
Application +4 | -1
Two waves of amplitude 3 mm3 \mathrm{~mm} and 2 mm2 \mathrm{~mm} reach a point in the same phase. The resultant amplitude is
View answer and explanation
Correct option: B
5 mm5 \mathrm{~mm}
Option B (5 mm) is correct because when waves are in phase, their amplitudes add directly.
156 Medium
156 of 396
Remembering +4 | -1
According to Huygens, medium through which light waves travel is
View answer and explanation
Correct option: B
luminiferous ether
Option B (luminiferous ether) is correct because Huygens proposed that light waves travel through a hypothetical medium called luminiferous ether.
157 Medium
157 of 396
Remembering +4 | -1
A wave can transmit ………. from one place to another
View answer and explanation
Correct option: B
Amplitude
Option A (Energy) is correct because waves transfer energy from one location to another without transferring matter.
158 Medium
158 of 396
Application +4 | -1
Unpolarised light incident on transparent glass at incident angle 60∘60^{\circ}. If reflected ray is completely polarised, then angle of refraction is
View answer and explanation
Correct option: C
30∘30^{\circ}
Option C (30∘30^{\circ}) is correct because, according to Brewster's law, the angle of incidence plus the angle of refraction equals 90 degrees when the reflected ray is completely polarized.
159 Medium
159 of 396
Application +4 | -1
In a diffraction pattern due to a single slit of width ‘a’, the first minimum is observed at an angle 30o{30^\mathrm{o}} when light of wavelength 5000 Ao\mathop \mathrm{A}\limits^\mathrm{o} is incident on the slit. The first secondary maximum is observed at an angle of:
View answer and explanation
Correct option: D
sin⁡−1 (34){\sin ^{ - 1}}\,\left( {\frac{3}{4}} \right)
Option D (sin⁡−1 (34){\sin ^{ - 1}}\,\left( {\frac{3}{4}} \right)) is correct because it satisfies the condition for the first secondary maximum in a single-slit diffraction pattern.
160 Medium
160 of 396
Application +4 | -1
A Young's double slit apparatus has slits separated by 0.28 mm0.28 \mathrm{~mm} and a screen 48 cm48 \mathrm{~cm} away from the slits. The whole apparatus is immersed in water and the slits are illuminated by the red light ( λ=700 nm\lambda=700 \mathrm{~nm} in vacuum). Find the fringe-width of the pattern formed on the screen.
View answer and explanation
Correct option: A
0.90 mm
Option A (0.90 mm) is correct because it is calculated using the formula for fringe width in Young's double-slit experiment, considering the refractive index of water.
161 Medium
161 of 396
Understanding +4 | -1
If the sodium light in Young’s double slit experiment is replaced by red light, the fringe width will
View answer and explanation
Correct option: B
Increase
Option B is correct because the fringe width in Young's double-slit experiment is directly proportional to the wavelength of light, and red light has a longer wavelength than sodium light.
162 Medium
162 of 396
Understanding +4 | -1
To observe diffraction, the size of an aperture
View answer and explanation
Correct option: A
Should be of the same orders wavelength should be much larger than the wavelength
The correct answer is A (Should be of the same orders wavelength should be much larger than the wavelength) because diffraction is most prominent when the aperture size is comparable to the wavelength of the wave.
163 Medium
163 of 396
Application +4 | -1
Two incoherent waves of intensities I0I_0 and 4I04 I_0 superimpose at a place. What is resultant intensity at that point?
View answer and explanation
Correct option: B
5I05I_0
Option B (5I05I_0) is correct because the resultant intensity of incoherent waves is the sum of their individual intensities.
164 Medium
164 of 396
Understanding +4 | -1
Resolving power of reflecting type telescope increases with
View answer and explanation
Correct option: D
Both 1 &\& 3
Option D is correct because the resolving power of a telescope is inversely proportional to the wavelength of light and directly proportional to the diameter of the objective mirror.
165 Medium
165 of 396
Understanding +4 | -1
The phenomenon of interference is shown by
View answer and explanation
Correct option: D
All the above types of waves
Option D (All the above types of waves) is correct because interference is a phenomenon exhibited by all types of waves, including longitudinal and transverse mechanical waves, as well as electromagnetic waves.
166 Medium
166 of 396
Understanding +4 | -1
Statement-I: The sound waves do not exhibit the property of polarization.
Statement-II: The sound waves do not have the transverse nature.
View answer and explanation
Correct option: C
Both statement-I &\& II are correct
Option C (Both statement-I &IIarecorrect)iscorrectbecausesoundwavesarelongitudinalandcannotbepolarized.\& II are correct) is correct because sound waves are longitudinal and cannot be polarized.
167 Medium
167 of 396
Understanding +4 | -1
Angular width (β) of central maximum of a diffraction pattern on a single slit does not depend upon
View answer and explanation
Correct option: A
Distance between slit and source
Option A (Distance between slit and source) is correct because the angular width of the central maximum in single-slit diffraction depends on the wavelength of light and the width of the slit, but not on the distance between the slit and the source.
168 Medium
168 of 396
Understanding +4 | -1
What is the effect on Fresnel’s biprism experiment when the use of white light is made
View answer and explanation
Correct option: C
Central fringe is white and all are coloured
Option C (Central fringe is white and all are coloured) is correct because with white light, the central fringe has zero path difference, resulting in white, while other fringes are colored due to different wavelengths.
169 Medium
169 of 396
Understanding +4 | -1
In order to see diffraction the thickness of the film is
View answer and explanation
Correct option: B
10000  A∘10000\;\mathop \mathrm{A}\limits^ \circ
Option B is correct because for diffraction to be observable, the size of the obstacle (film thickness) should be comparable to the wavelength of visible light, which is around 10000A∘10000 \mathop \mathrm{A}\limits^ \circ.
170 Medium
170 of 396
Understanding +4 | -1
A parallel monochromatic beam of light is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the first minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of the slit is
View answer and explanation
Correct option: D
2π2\pi
Option D (2π2\pi) is correct because for the first minimum in a single-slit diffraction pattern, the path difference between the rays from the edges of the slit is one wavelength, which corresponds to a phase difference of 2π2\pi.
171 Medium
171 of 396
Application +4 | -1
In a single slit diffraction experiment first minimum for red light (660  nm)\left( {660\;nm} \right) coincides with first maximum of some other wavelength λ{\lambda}. The value of λ{\lambda} is
View answer and explanation
Correct option: A
4400  A∘4400\;\mathop \mathrm{A}\limits^ \circ
Option A (4400  A∘4400\;\mathop \mathrm{A}\limits^ \circ) is correct because it is the wavelength calculated by equating the position of the first minimum of red light to the first maximum of the other wavelength.
172 Medium
172 of 396
Understanding +4 | -1
If n represents the order of a half period zone, the area of this zone is approximately proportional to nm{n^m} where m is equal to
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because the area of a half-period zone is approximately constant and independent of the order of the zone.
173 Medium
173 of 396
Understanding +4 | -1
In Young’s double slit interference pattern the fringe width
View answer and explanation
Correct option: C
Can be changed either by changing the wavelength or by changing the separation between two sources
Option C (Can be changed either by changing the wavelength or by changing the separation between two sources) is correct because the fringe width in Young's double-slit experiment depends on both the wavelength of light and the slit separation.
174 Medium
174 of 396
Remembering +4 | -1
The resolving power of a telescope depends on
View answer and explanation
Correct option: D
Diameter of the objective lens
Option D (Diameter of the objective lens) is correct because the resolving power of a telescope is directly proportional to the diameter of its objective lens.
175 Medium
175 of 396
Understanding +4 | -1
Consider the following statements in case of Young’s double slit experiment.
I. A slit S is necessary if we use an ordinary extended source of light.
II. A slit S is not needed if we use an ordinary but well collimated beam of light.
III. A slit S is not needed if we use a spetially coherent source of light.
Which of the above statement are correct?
View answer and explanation
Correct option: D
(i), (ii) and (iii)
Option D is correct because all three statements are correct regarding the necessity of a slit in Young's double-slit experiment depending on the light source.
176 Medium
176 of 396
Remembering +4 | -1
For the sustained interference of light, the necessary condition is that the two sources should
View answer and explanation
Correct option: A
Have constant phase difference
Option A (Hot wire voltmeter) is correct because hot wire voltmeters are designed to measure AC voltages.
177 Medium
177 of 396
Remembering +4 | -1
Refractive index of material is equal to tangent of polarising angle. It is called
View answer and explanation
Correct option: A
Brewster's law
Option A (Brewster's law) is correct because Brewster's law states that the refractive index of a material is equal to the tangent of the polarizing angle.
178 Medium
178 of 396
Understanding +4 | -1
Assertion: The phase difference between any two poitns on a wave front is zero.

Reason: Light from the source reaches every point ofthe wave front at the same time.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because a wavefront is defined as a surface of constant phase, reached at the same time by light from the source.
179 Medium
179 of 396
Application +4 | -1
A light wave is incident normally over a slit of width 24×10−5  cm24 \times {10^{ - 5}}\;cm. The angular position of second dark fringe from the central maxima is 30∘30^\circ. What is the wavelength of light
View answer and explanation
Correct option: A
6000A∘6000\mathop \mathrm{A}\limits^ \circ
Option A (6000A∘6000\mathop \mathrm{A}\limits^ \circ) is correct because it is the wavelength calculated using the formula for the angular position of the second dark fringe in single-slit diffraction.
180 Medium
180 of 396
Remembering +4 | -1
The wavefront of a distant source of light is of shape
View answer and explanation
Correct option: D
plane
The correct answer is D (plane) because at a large distance from the source, the wavefront appears as a plane wave.
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