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JEE • PHYSICS • WAVE OPTICS

Wave optics practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 396 questions

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181 Medium
181 of 396
Understanding +4 | -1
For light diverging from a point source
View answer and explanation
Correct option: A
The wavefront is spherical
Option A (The wavefront is spherical) is correct because light diverging from a point source creates spherical wavefronts.
182 Medium
182 of 396
Understanding +4 | -1
The total angular width of central maxima in diffraction at a single slit is
View answer and explanation
Correct option: B
2λa\frac{2 \lambda}{a}
Option B is correct because the angular width of the central maxima in single-slit diffraction is given by 2λa\frac{2 \lambda}{a}, where λ\lambda is the wavelength and a is the slit width.
183 Medium
183 of 396
Understanding +4 | -1
Suppose you are using a microscope to view two closely spaced cells. For a given lens diameter, which color of light would you use to achieve the best possible resolving power?
View answer and explanation
Correct option: D
Blue
Option D (Blue) is correct because resolving power is inversely proportional to the wavelength of light, and blue light has the shortest wavelength.
184 Medium
184 of 396
Application +4 | -1
A slit of width ' aa ' is illuminated by light of wavelength 6000A06000 A^0 For What value of 'a will the :- 
(i) First maximum fall at an angle of diffraction of 30∘30^{\circ} ? 
(ii) First minimum fall at an angle of diffraction 30∘30^{\circ} ?
View answer and explanation
Correct option: A
1.8μm1.8 \mu \mathrm{m} , 1.2μm1.2 \mu \mathrm{m}
Option A (1.8μm1.8 \mu \mathrm{m} , 1.2μm1.2 \mu \mathrm{m}) is correct because it correctly applies the conditions for the first maximum and first minimum in single-slit diffraction.
185 Medium
185 of 396
Understanding +4 | -1
What should be refractive index of a transparent medium to be invisible in vacuum?
View answer and explanation
Correct option: A
1
Option A (1) is correct because the refractive index of vacuum is 1, and for a medium to be invisible, its refractive index must match that of the surrounding medium.
186 Medium
186 of 396
Analyzing +4 | -1
Yellow light is used in single slit diffraction experiment with slit width 0.6  mm\mathrm{0}\mathrm{.6}\;\mathrm{mm}. If yellow light is replaced by X\mathrm{X}-rays, then the pattern will reveal that
View answer and explanation
Correct option: A
No diffraction pattern
Option A (No diffraction pattern) is correct because the wavelength of X-rays is much smaller than the slit width, resulting in negligible diffraction.
187 Medium
187 of 396
Understanding +4 | -1
If a star is moving towards the earth, then the lines are shifted towards
View answer and explanation
Correct option: C
Blue
Option C (Blue) is correct because when a star moves towards the Earth, the light waves are compressed, resulting in a blueshift (shorter wavelength).
188 Medium
188 of 396
Understanding +4 | -1
In Fresnel diffraction, if the distance between the disc and the screen is decreased, the intensity of central bright spot will
View answer and explanation
Correct option: B
Decrease
Option A (Increase) is incorrect. In Fresnel diffraction, decreasing the distance between the disc and the screen increases the number of blocked half-period zones, thus decreasing the intensity of the central bright spot.
189 Medium
189 of 396
Understanding +4 | -1
The resolving power of an astronomical telescope is 0.2  seconds\mathrm{0}.\mathrm{2}\,\,\mathrm{seconds}. If the central half portion of the objective lens is covered, the resolving power will be
View answer and explanation
Correct option: A
0.1  sec⁡0.1\,\,\sec
The correct answer is B (0.2 sec) because the resolving power of a telescope depends on the diameter of the objective lens, not the area. Covering the central portion doesn't change the effective diameter.
190 Medium
190 of 396
Application +4 | -1
A single slit Fraunhoffer diffraction pattern is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the second secondary maximum in the pattern for red light of wavelength 6500 A∘6500\,\mathop \mathrm{A}\limits^ \circ
View answer and explanation
Correct option: C
4642.8 A∘4642.8\,\mathop \mathrm{A}\limits^ \circ
Option C (4642.8A∘4642.8\mathop \mathrm{A}\limits^ \circ) is correct because the position of the maxima in a single-slit diffraction pattern depends on the wavelength.
191 Medium
191 of 396
Understanding +4 | -1
Two coherent sources of light can be obtained by
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because coherent sources require a single original source split into two to maintain a constant phase relationship, which cannot be achieved with two different lamps.
192 Medium
192 of 396
Understanding +4 | -1
Statement A: Sharp edge of a fine needle doesn't cast clear shadow.

Statement B: Sharp edge of needle capable to diffract radio wave.
View answer and explanation
Correct option: C
A is correct and B is wrong
Option C (A is correct and B is wrong) is correct because sharp edges of fine needles do not cast clear shadows due to diffraction, but needles are not capable of diffracting radio waves because radio waves have much larger wavelengths.
193 Medium
193 of 396
Application +4 | -1
In Young’s double slit experiment we get 60 fringes in the field of view of monochromatic light of wavelength 4000  A∘{4000\;\mathop \mathrm{A}\limits^ \circ }. If we use monochromatic light of wavelength 6000  A∘{6000\;\mathop \mathrm{A}\limits^ \circ }, then the number of fringes obtained in the same field of view are
View answer and explanation
Correct option: C
40
Option C (40) is correct because the number of fringes is inversely proportional to the wavelength of light used.
194 Medium
194 of 396
Understanding +4 | -1
The way the fringe pattern changes when the screen is moved away from the slits is
View answer and explanation
Correct option: A
Width of fringe increases
Option A (Width of fringe increases) is correct because the fringe width is directly proportional to the distance between the slits and the screen.
195 Medium
195 of 396
Understanding +4 | -1
Through quantum theory of light we can explain a number of phenomena observed with light, it is necessary to retain the wave nature of light to explain the phenomenon of
View answer and explanation
Correct option: B
Diffraction
Option B (Diffraction) is correct because diffraction is a phenomenon that can only be explained by the wave nature of light.
196 Medium
196 of 396
Understanding +4 | -1
As a result of interference of two coherent sources of light, energy is
View answer and explanation
Correct option: B
Redistributed and the distribution does not vary with time
Option B is correct because interference redistributes energy, creating regions of constructive and destructive interference without changing the total energy.
197 Medium
197 of 396
Understanding +4 | -1
In the following four statements are regarding well defined observable interference pattern.

A) Condition for sustained interference : The two waves should be coherent.

B) Condition for good observation : The separation between light sources should be as small as possible.

C) Condition for good contrast: The amplitudes of interfering waves should be equal (or) at least very nearly equal.

D) Condition for good contrast : Slit width must be very narrow considerably less than the fringe width.
View answer and explanation
Correct option: A
All the above are correct
Option A (All the above are correct) is correct because all the listed conditions (coherence, small separation, equal amplitudes, narrow slit width) are necessary for observing a well-defined interference pattern.
198 Medium
198 of 396
Understanding +4 | -1
In a diffraction pattern by a wire, on increasing diameter of wire, fringe width
View answer and explanation
Correct option: A
Decreases
Option C is correct because the dimensional formula for entropy is derived from the formula S=QTS = \frac{Q}{T}, where Q is heat (energy) and T is temperature.
199 Medium
199 of 396
Understanding +4 | -1
From Brewster's law, except for polished metallic surface, the polarising angle
View answer and explanation
Correct option: A
Depends on wave length and is different for different colours
Option A is correct because Brewster's angle, which is the polarizing angle, depends on the refractive index of the material, which in turn depends on the wavelength of light, making it different for different colors.
200 Medium
200 of 396
Application +4 | -1
The maximum number of possible interference maxima for slit separation equal to 2.5 times the wavelength in young's double slit experiment is
View answer and explanation
Correct option: B
Five
Option B (Five) is correct because the maximum number of interference maxima is determined by the condition dsin⁡θ=nλd \sin \theta = n \lambda, and with d=2.5λd = 2.5\lambda, the possible integer values for n are -2, -1, 0, 1, and 2.
201 Medium
201 of 396
Understanding +4 | -1
What should be refractive index of a transparent medium to be invisible in vacuum?
View answer and explanation
Correct option: A
1
Option A (1) is correct because for a medium to be invisible in vacuum, its refractive index must match that of vacuum, which is 1.
202 Medium
202 of 396
Understanding +4 | -1
If the source of light used in a Young’s double slit experiment is changed from red to violet, then
View answer and explanation
Correct option: A
the consecutive fringe lines will come closer
Option D (Is reduced by a factor of 1/4) is correct because the probable error is inversely proportional to the square root of the number of readings.
203 Medium
203 of 396
Understanding +4 | -1
The radius r of half period zone is proportional to
View answer and explanation
Correct option: A
n\sqrt n
Option A (n\sqrt n) is correct because the radius of the nth half-period zone is directly proportional to the square root of n.
204 Medium
204 of 396
Understanding +4 | -1
When an unpolarized light of intensity I0{I_0} is incident on a polarizing sheet, the intensity of the light which does not get transmitted is
View answer and explanation
Correct option: C
12I0\frac{1}{2}{I_0}
Option C (12I0\frac{1}{2}{I_0}) is correct because when unpolarized light passes through a polarizing sheet, its intensity is reduced by half.
205 Medium
205 of 396
Remembering +4 | -1
If microwaves, X rays, infrared, gamma rays, ultra-violet, radio waves and visible parts of the electromagnetic spectrum are denoted by M, X, I, G, U, R and V then which of the following is the arrangement in ascending order of wavelength?
View answer and explanation
Correct option: C
G, X, U, V, I, M and R
Option C (G, X, U, V, I, M and R) is correct because it represents the electromagnetic spectrum in ascending order of wavelength, from gamma rays to radio waves.
206 Medium
206 of 396
Analyzing +4 | -1
Given below two statements: One is labelled as Assertion (A) and other is labelled as Reason (R).
Assertion (A): Non-polar materials do not have any permanent dipole moment.
Reason (R): When a non-polar material is placed in an electric field, the centre of the positive charge distribution of it’s individual atom or molecule coincides with the centre of the negative charge distribution.
In the light of above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: C
(A) is correct but (R) is not correct.
Option C ((A) is correct but (R) is not correct) is correct because non-polar materials do not have a permanent dipole moment, but the reason incorrectly states that the charge distributions coincide even when an electric field is applied.
207 Medium
207 of 396
Understanding +4 | -1
Which of the following cannot be explained on the basis of wave nature of light? I. Polarization II. Optical activity III. Photoelectric effect IV. Compton effect
View answer and explanation
Correct option: A
(iii) and (iv)
Option A is correct because the photoelectric effect and Compton effect require the particle nature of light for explanation, while polarization and optical activity are explained by the wave nature.
208 Medium
208 of 396
Understanding +4 | -1
The dual nature of light is exhibited by
View answer and explanation
Correct option: D
Diffraction and photoelectric effect
Option D (Diffraction and photoelectric effect) is correct because diffraction demonstrates the wave nature of light, while the photoelectric effect demonstrates the particle nature of light.
209 Medium
209 of 396
Understanding +4 | -1
In YDSE the centre of the screen can be identified:
View answer and explanation
Correct option: D
By using white light instead of single
wavelength light
Option A is correct because both statements are true: the angle of repose is equal to the angle of limiting friction, and limiting friction is the friction force when the body is just about to move.
210 Medium
210 of 396
Understanding +4 | -1
Statement A: If a person wants to observe sharp and clear fringes of good contrast then interference experiment is preferable compared to diffraction.

Statement B: In diffraction intensity after the central maxima decreases rapidly, so fringe pattern become blurred.
View answer and explanation
Correct option: A
A and B are correct
Option A (A and B are correct) is correct because interference experiments provide sharper fringes with better contrast compared to diffraction, where intensity decreases rapidly after the central maxima, blurring the pattern.
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