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JEE • PHYSICS • WAVE OPTICS

Wave optics practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Easy

1 of 13

Application +4 | -1

A beam of monochromatic light of wavelength

5.82 \times 10^{-7} \mathrm{~m}

falls normally on a glass wedge with the wedge angle of 20 second of an arc. If the refractive index of glass is

1.5,

find the number of dark interference fringes per

\mathrm{cm}

of the wedge length:

View answer and explanation

Correct option: B

5 per cm

Option B (5 per cm) is correct because it correctly calculates the number of dark fringes per cm based on the given parameters.

2 Easy

2 of 13

Understanding +4 | -1

In young's double slit experiment with a source of light of wavelength

6320\,\mathop {\text{A}}\limits^ \circ

, the first maxima will occur when

View answer and explanation

Correct option: C

Path difference is

6320\,\mathop {\text{A}}\limits^ \circ

Option C (Path difference is

6320\,\mathop {\text{A}}\limits^ \circ

) is correct because the first maxima occurs when the path difference is equal to one wavelength.

3 Easy

3 of 13

Understanding +4 | -1

If the monochromatic source in Young's double slit experiment is replaced by white light, then

View answer and explanation

Correct option: B

There will be a central bright white fringe surrounded by a few coloured fringes

The correct answer is B (There will be a central bright white fringe surrounded by a few coloured fringes) because at the central point, the path difference is zero for all wavelengths, resulting in a white fringe, while other fringes depend on wavelength and become colored.

4 Easy

4 of 13

Understanding +4 | -1

Statement-1: In interference experiment, the fringe system will shift, if a glass plate is interposed in the path of the one of the interfering beams and the shift will be on the side of the glass plate.
Statement-2: The velocity of light in glass is smaller than in air.

View answer and explanation

Correct option: A

Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1

Option A is correct because Statement-1 and Statement-2 are true, and Statement-2 correctly explains Statement-1 regarding the shift in the fringe system due to the glass plate.

5 Easy

5 of 13

Understanding +4 | -1

A thin air film is formed by putting the convex surface of a plane-convex lens over a plane glass plate. With monochromatic light, this film gives an interference pattern due to light reflected from the top (convex) surface and the bottom (glass plate) surface of the film.

Statement I : When light reflects from the air-glass plate interface, the reflected wave suffers a phase change of

\pi

.

Statement II : The centre of the interference pattern is dark.

View answer and explanation

Correct option: B

Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I

Option B (Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I) is correct because both statements are true, but the dark center is due to a phase change upon reflection and the small air gap at the center.

6 Easy

6 of 13

Analyzing +4 | -1

Four independent light waves are expressed as

\mathrm{y}_1=\mathrm{a}_1 \sin \omega \mathrm{t}, \mathrm{y}_2=\mathrm{a}_2 \sin \omega \mathrm{t}, \mathrm{y}_3=\mathrm{a}_3 \cos \omega \mathrm{t}

and

\mathrm{y}_4=\mathrm{a}_4 \sin (\omega \mathrm{t}+\pi / 3)

. The interference is possible between

View answer and explanation

Correct option: D

Not possible at all

The correct answer is D (Not possible at all) because independent light waves are generally incoherent and cannot produce sustained interference patterns.

7 Easy

7 of 13

Application +4 | -1

Monochromatic light of wavelength

600 \mathrm{~nm}

is incident from air on a glass surface (refractive index of glass is

1.5

). The frequency of the refracted light will be

View answer and explanation

Correct option: A

5 \times 10^{14} \mathrm{~Hz}

Option A (

5 \times 10^{14} \mathrm{~Hz}

) is correct because the frequency of light remains the same when it is refracted.

8 Easy

8 of 13

Analyzing +4 | -1

Statement-1: In Young's double slit experiment the two slits are at distance

d

apart. Interference pattern is observed on a screen at distance

D

from the slits. At a point on the screen when it is directly opposite to one of the slits, a dark fringe is observed. Then the wavelength of wave is proportional to square of distance between the two slits.
Statement-2: For a dark fringe intensity is zero.

View answer and explanation

Correct option: C

Statement-1 is true, Statement-2 is false

Option D (Statement-1 is false, Statement-2 is true) is correct because the wavelength is proportional to the square of the distance between the slits, and intensity is indeed zero for a dark fringe.

9 Easy

9 of 13

Application +4 | -1

A parallel beam of monochromatic unpolarised
light is incident on a transparent plate of
refractive index

\sqrt{3}.

The reflected beam is
completely polarized. The angle of incidence
is

View answer and explanation

Correct option: B

60^\circ

Option B (

60^\circ

) is correct because the angle of incidence at which the reflected light is completely polarized is Brewster's angle, given by

\mu = \tan \theta_P

, where

\mu

is the refractive index.

10 Easy

10 of 13

Understanding +4 | -1

Assertion: Incoming light reflected by earth is partially polarized.
Reason: Atmospheric particle polarize the light.

View answer and explanation

Correct option: A

If both Assertion and Reason are true and Reason is the correct explanation of Assertion

Option A (If both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because atmospheric particles scatter sunlight, causing it to become partially polarized.

11 Easy

11 of 13

Understanding +4 | -1

Assertion: Distance between position of bright and dark fringe remain same in YDSE
Reason: Fringe width

\beta=\frac{\lambda D}{d}

View answer and explanation

Correct option: A

If both Assertion and Reason are correct and Reason is the correct explanation of Assertion

Option A is correct because the fringe width in Young's double-slit experiment is constant and depends on wavelength, distance to the screen, and slit separation.

12 Easy

12 of 13

Remembering +4 | -1

According to Huygen’s theory of light

View answer and explanation

Correct option: B

Light is a wave

Option B (Light is a wave) is correct because Huygens' principle describes light propagation as a wave phenomenon using wavefronts.

13 Easy

13 of 13

Application +4 | -1

An objective lens of a telescope has diameter 200 cm. The limit of resolution of telescope for wavelength 600 nm is nearly

View answer and explanation

Correct option: B

3.7\mathrm{ } \times \mathrm{ }{10^{-7}}rad

Option B (

3.7\mathrm{ } \times \mathrm{ }{10^{-7}}rad

) is correct because it's the limit of resolution calculated using the formula

\theta = \frac{{1.22\lambda }}{D}

Revision notes and key takeaways

Review WAVE OPTICS in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 13 single-correct-answer MCQs on WAVE OPTICS.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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