JEE PHYSICS MCQ: WAVE OPTICS

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In a Young’s double slit experiment, the ratio of the slit’s width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be

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Correct option: C

0.375694444

Option C (09:01) is correct because the ratio of intensities is calculated based on the ratio of slit widths in Young's double-slit experiment.

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