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JEE • PHYSICS • WAVE OPTICS

Wave optics practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 418 questions

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361 Medium
361 of 418
Application +4 | -1
Monochromatic light of wavelength 600 nm600 \mathrm{~nm} is incident from air on a glass surface (refractive index of glass is 1.51.5). The speed of the refracted light will be
View answer and explanation
Correct option: C
2×108 ms−12 \times 10^{8} \mathrm{~ms}^{-1}
Option C (2×108 ms−12 \times 10^{8} \mathrm{~ms}^{-1}) is correct because the speed of light in a medium is the speed of light in vacuum divided by the refractive index of the medium.
362 Medium
362 of 418
Understanding +4 | -1
The conditions for producing sustained interference are

I. Phase difference between interfering waves remains constant with time.

II. Interfering waves have nearly same amplitude levels.

III. Interfering waves are of same frequency.

IV. Interfering waves are moving of opposite directions.
View answer and explanation
Correct option: A
I, II and III
Option A (I, II and III) is correct because sustained interference requires constant phase difference, nearly same amplitudes, and same frequency.
363 Medium
363 of 418
Understanding +4 | -1
When light ray moving from air to medium is incident at polarising angle then
(a) Reflected light is completely polarised
(b) Refracted light is partial polarised
(c) Both reflected and refracted light are perpendicular to each other.
(d) Brewster's Law μ=tan⁡ip\mu=\tan \mathrm{i}_{\mathrm{p}} is obeyed
Choose the most correct option.
View answer and explanation
Correct option: C
a, b, c, d are correct
Option C (a, b, c, d are correct) is correct because at the polarizing angle, reflected light is completely polarized, refracted light is partially polarized, they are perpendicular, and Brewster's law is obeyed.
364 Medium
364 of 418
Understanding +4 | -1
Electromagnetic waves are transverse in nature is evident by
View answer and explanation
Correct option: A
Polarization
Option A (Polarization) is correct because polarization demonstrates that electromagnetic waves are transverse, as only transverse waves can be polarized.
365 Medium
365 of 418
Application +4 | -1
In the Young’s double slit experiment, a mica slip of thickness t and refractive index μ\mu is introduced in the ray from first source S1{S_1}. By how much distance fringes pattern will be displaced.
View answer and explanation
Correct option: B
Dd(μ−1)t\frac{D}{d}\left( {\mu - 1} \right)t
Option B (Dd(μ−1)t\frac{D}{d}\left( {\mu - 1} \right)t) is correct because the fringe shift is directly proportional to the thickness of the mica slip and the refractive index minus 1.
366 Medium
366 of 418
Application +4 | -1
An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The separation between the objective and eye-piece is 36 cm36 \mathrm{~cm} and the final image is formed at infinity:
(a) the focal length of objective is 30 cm30 \mathrm{~cm}
(b) the focal length of objective is 25 cm25 \mathrm{~cm}
(c) the focal length of eye piece is 6 cm6 \mathrm{~cm}
(d) the focal length of eye piece is 12 cm12 \mathrm{~cm}
View answer and explanation
Correct option: D
(a) and (c) are correct
Option D ((a) and (c) are correct) is correct because the focal lengths of the objective and eyepiece are 30 cm and 6 cm respectively, satisfying the magnification and length conditions.
367 Medium
367 of 418
Remembering +4 | -1
Conditions of diffraction is
View answer and explanation
Correct option: A
aλ=1\frac{a}{\lambda}=1
Option A (aλ=1\frac{a}{\lambda}=1) is correct because diffraction occurs when the size of the aperture or obstacle is comparable to the wavelength of the wave, meaning their ratio is approximately 1.
368 Medium
368 of 418
Understanding +4 | -1
Two sources of waves are called coherent if
View answer and explanation
Correct option: C
Both produce waves of the same wavelength having constant phase difference
Option C is correct because coherent sources must have the same wavelength (or frequency) and a constant phase difference to produce sustained interference.
369 Medium
369 of 418
Understanding +4 | -1
Which statement is correct for a zone plate and a lens
View answer and explanation
Correct option: A
Zone plate has multi focii whereas lens has one
The correct answer is A (Zone plate has multi focii whereas lens has one) because a zone plate diffracts light to create multiple focal points, unlike a lens which typically has a single focal point.
370 Medium
370 of 418
Application +4 | -1
Maximum intensity in YDSE is I0{I}_0. The intensity at a point on the sereen where the path difference between the two interfering waves is λ3\frac{\lambda}{3} will be;
View answer and explanation
Correct option: D
I04\frac{I_0}{4}
Option D (I04\frac{I_0}{4}) is correct because the intensity at a point with a path difference of λ3\frac{\lambda}{3} is I04\frac{I_0}{4}.
371 Medium
371 of 418
Understanding +4 | -1
The phenomenon which does not take place in sound waves is
View answer and explanation
Correct option: D
Polarisation
Option D (Polarisation) is correct because polarization is a phenomenon that occurs only in transverse waves, not longitudinal sound waves.
372 Medium
372 of 418
Application +4 | -1
If prism angle α=1∘,μ=1.54\alpha=1^{\circ}, \mu=1.54, distance between screen and prism (b) =0.7 m=0.7 \mathrm{~m}, distance between prism and source a=0.3 m,λ=180πnma=0.3 \mathrm{~m}, \lambda=180 \pi \mathrm{nm} then in Fresnal biprism find the value of β\beta (fringe width)
View answer and explanation
Correct option: C
10−4×πm10^{-4} \times \pi \mathrm{m}
Option C (10−4×π m10^{-4} \times \pi \mathrm{~m}) is correct because it is the fringe width calculated using the Fresnel biprism formula.
373 Medium
373 of 418
Understanding +4 | -1
In the context of Doppler effect in light, the term ‘red shift’ signifies
View answer and explanation
Correct option: A
Decrease in frequency
Option A (Decrease in frequency) is correct because red shift in the Doppler effect for light signifies an increase in wavelength, which corresponds to a decrease in frequency.
374 Medium
374 of 418
Understanding +4 | -1
The phase difference between two wave trains giving rise to a dark fringe in Young's double slit interference experiment is (n\mathrm{n} integer):
View answer and explanation
Correct option: B
2πn+π2 \pi \mathrm{n}+\pi
Option B (2πn+π2 \pi \mathrm{n}+\pi) is correct because a dark fringe (destructive interference) occurs when the phase difference is an odd multiple of π\pi.
375 Medium
375 of 418
Understanding +4 | -1
Which of the following is conserved when light waves interfere
View answer and explanation
Correct option: B
Energy
Option B (Energy) is correct because the total energy is conserved during the interference of light waves, even though intensity varies spatially.
376 Medium
376 of 418
Application +4 | -1
Two coherent sources each emitting light of Intensity I0I_0 interfere in a medium at a point where phase difference between them is 2π3\frac{2 \pi}{3}. The resultant intensity at the point is
View answer and explanation
Correct option: A
IoI_o
Option A (IoI_o) is correct because the resultant intensity is calculated using the formula I=4I0cos⁡2(ϕ2)I = 4I_0 \cos^2(\frac{\phi}{2}) with ϕ=2π3\phi = \frac{2\pi}{3}.
377 Medium
377 of 418
Understanding +4 | -1
Select the right option in the following
View answer and explanation
Correct option: B
Maxwell provided the theoretical evidence that light is transverse wave
Option B (Maxwell provided the theoretical evidence that light is transverse wave) is correct because Maxwell's equations demonstrated the transverse nature of electromagnetic waves, including light.
378 Medium
378 of 418
Understanding +4 | -1
If LL is the coherence length and cc the velocity of light, the coherent time is
View answer and explanation
Correct option: B
Lc\frac{L}{c}
Option B is correct because coherence time is defined as the coherence length divided by the speed of light.
379 Medium
379 of 418
Understanding +4 | -1
Which if the following phenomena is not common to sound and light waves?
View answer and explanation
Correct option: D
Polarisation
Option D (Polarisation) is correct because polarization is a property of transverse waves, like light, but not longitudinal waves, like sound.
380 Medium
380 of 418
Application +4 | -1
If two waves represented by y1=4sin⁡ωt  and  y2=3sin⁡(ωt+π3){y_1} = 4\sin \omega t\;and\;{y_2} = 3\sin \left( {\omega t + \frac{\pi }{3}} \right) interfere at a point, the amplitude of the resulting wave will be about
View answer and explanation
Correct option: B
6
Option B (6) is correct because the amplitude of the resulting wave is calculated using the superposition principle and the given phase difference.
381 Medium
381 of 418
Application +4 | -1
In Young’s double slit experiment, if the widths of the slits are in the ratio 4:9\mathrm{4 }:\mathrm{ 9}, the ratio of the intensity at maxima to the intensity at minima will be
View answer and explanation
Correct option: C
25:125\mathrm{ }:\mathrm{ }1
Option C (25:125\mathrm{ }:\mathrm{ }1) is correct because it is calculated by finding the ratio of intensities at maxima and minima using the given slit width ratio.
382 Medium
382 of 418
Understanding +4 | -1
Which of following can not be polarized
View answer and explanation
Correct option: D
Ultrasonic waves
Option D (Ultrasonic waves) is correct because ultrasonic waves are longitudinal waves and cannot be polarized.
383 Medium
383 of 418
Application +4 | -1
In Young's double-slit experiment, the ratio of intensities of a bright band and a dark band is 16:116: 1. The ratio of amplitudes of interfering waves will be
View answer and explanation
Correct option: D
5:35: 3
Option D (5:3) is correct because the ratio of amplitudes is derived from the ratio of maximum and minimum intensities in the interference pattern.
384 Medium
384 of 418
Application +4 | -1
Among the two interfering monochromatic sources A  and  BA\;and\;B; AA is ahead of BB in phase by 66∘66^\circ. If the observation be taken from point PP, such that PB−PA=λ/4PB - PA = \lambda /4. Then the phase difference between the waves from A  and  BA\;and\;B reaching PP is
View answer and explanation
Correct option: A
156∘156^\circ
Option A (156∘156^\circ) is correct because the total phase difference is the sum of the initial phase difference and the phase difference due to the path difference.
385 Medium
385 of 418
Understanding +4 | -1
If numerical aperture of a microscope is increased then its
View answer and explanation
Correct option: C
Limit of resolution is decreased
Option C is correct because increasing the numerical aperture (NA) of a microscope decreases the limit of resolution, allowing for finer details to be observed.
386 Medium
386 of 418
Understanding +4 | -1
Assertion: In Young's double slit experiment interference pattern disappears when one of the lits is closed.

Reason: Interference occuts due to super imposition of light waves from two coherent sources.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because interference requires two coherent sources, and closing one slit eliminates the second source, thus stopping the interference pattern.
387 Medium
387 of 418
Understanding +4 | -1
If white light is used in the Newton’s rings experiment, the colour observed in the reflected light is complementary to that observed in the transmitted light through the same point. This is due to
View answer and explanation
Correct option: B
180∘180^\circ change of phase in one of the reflected waves
Option B (180∘180^\circ) is correct because the phase change of 180∘180^\circ (or π\pi) occurs upon reflection from a denser medium, leading to complementary colors in reflected and transmitted light.
388 Medium
388 of 418
Analyzing +4 | -1
Statement A: In the interference pattern the intensity is same at all points in a bright band

Statement B: In Young's double slit experiment, as we move away from the central maximum, the third maximum always comes before the third minimum.
View answer and explanation
Correct option: A
A and B are correct
Option B (A and B are wrong) is correct because the intensity varies within a bright band, and the third maximum appears after the third minimum in YDSE.
389 Medium
389 of 418
Remembering +4 | -1
The wave theory of light was given by
View answer and explanation
Correct option: C
Huygen
Option C (Huygen) is correct because Christiaan Huygens proposed the wave theory of light in the 17th century.
390 Medium
390 of 418
Application +4 | -1
How far in advance can one detect two headlights of a car if they are separated by a distance of 1.57 m1.57 \mathrm{~m}?
View answer and explanation
Correct option: A
5.4 km5.4 \mathrm{~km}
Option A (5.4 km5.4 \mathrm{~km}) is correct because it is the distance at which two headlights can be resolved, calculated using the angular resolution of the human eye.
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