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JEE • PHYSICS • WAVE OPTICS

Wave optics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 391-418 of 418 questions

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391 Medium
391 of 418
Remembering +4 | -1
Which of the following is not a property of light
View answer and explanation
Correct option: A
It requires a material medium for propagation
Option A (It requires a material medium for propagation) is correct because light, being an electromagnetic wave, can travel through a vacuum and does not need a material medium to propagate.
392 Medium
392 of 418
Understanding +4 | -1
In Brewster's Law μ=tan⁡ip\mu=\tan i_p, polarising angle depends on
(a) Wavelength of light

(b) Nature of medium
(c) Amount of light incident on the surface.
Choose the correct option.
View answer and explanation
Correct option: C
Both a and b are correct
Option C (Both a and b are correct) is correct because the polarizing angle depends on both the wavelength of light and the nature of the medium.
393 Medium
393 of 418
Understanding +4 | -1
Which of the following is correct in YDSE?
View answer and explanation
Correct option: A
If incident is white light, then central fringe is white while all other fringes are coloured
Option A (If incident is white light, then central fringe is white while all other fringes are coloured) is correct because in YDSE with white light, the central fringe is white due to the superposition of all colors, while other fringes are colored due to different wavelengths interfering at different positions.
394 Medium
394 of 418
Application +4 | -1
The maximum intensity in the case if nn identical incoherent waves, each of intensity 2  Wm−2\mathrm{2}\;\mathrm{W}{\mathrm{m}^{ - 2}} is 32  Wm−232\;W{\mathrm{m}^{ - 2}}. The value of n is
View answer and explanation
Correct option: B
16
Option B (16) is correct because the maximum intensity of n identical incoherent waves is n times the intensity of a single wave.
395 Medium
395 of 418
Application +4 | -1
In young's double slit experiment, the two slits are coherent sources of equal amplitude and wave length λ\lambda. In another experiment with the same setup, two slits are sources of equal amplitude 'AA' and wavelength λ\lambda, but are incoherent. The ratio of intensities of light at the midpoint of the screen in the first case to that in second case, is
View answer and explanation
Correct option: A
2:12: 1
Option A (2:12: 1) is correct because the ratio of intensities is found by comparing the resultant intensity of coherent sources to that of incoherent sources at the midpoint.
396 Medium
396 of 418
Understanding +4 | -1
Which of the following phenomena can explain quantum nature of light
View answer and explanation
Correct option: A
Photoelectric effect
Option A (Photoelectric effect) is correct because the photoelectric effect demonstrates the particle-like (quantum) nature of light, where light is absorbed as discrete packets of energy (photons).
397 Medium
397 of 418
Remembering +4 | -1
The band spectra (characteristic of molecular species) is due to emission of radiation
View answer and explanation
Correct option: A
Gaseous state
Option A (Gaseous state) is correct because band spectra are characteristic of molecular species in the gaseous state.
398 Medium
398 of 418
Application +4 | -1
In a Young's double slit experiment, the slits are 2 mm2 \mathrm{~mm} apart and are illuminated with a mixture of two wavelength λ0=750 nm\lambda_0=750 \mathrm{~nm} and λ=900 nm\lambda=900 \mathrm{~nm}. The minimum distance from the common central bright fringe on a screen 2m2 m from the slits where a bright fringe from one interference pattern coincides with a bright fringe from the other is
View answer and explanation
Correct option: C
4.5 mm4.5 \mathrm{~mm}
Option C (4.5 mm4.5 \mathrm{~mm}) is correct because the minimum distance is found by equating the path differences for the two wavelengths and solving for the order of the fringe.
399 Medium
399 of 418
Remembering +4 | -1
According to corpuscular theory of light, the different colours of light are due to
View answer and explanation
Correct option: C
Different size of the corpuscles
Option C (Different size of the corpuscles) is correct because, according to Newton's corpuscular theory, different colors of light were attributed to corpuscles of different sizes.
400 Medium
400 of 418
Understanding +4 | -1
An electron microscope is superior to an optical microscope in
View answer and explanation
Correct option: A
Having better resolving power
Option A (Having better resolving power) is correct because electron microscopes use electrons with much shorter wavelengths than visible light, resulting in significantly higher resolving power.
401 Medium
401 of 418
Understanding +4 | -1
The fringe-width in a Young’s double slit experiment can be increased, if we decrease
View answer and explanation
Correct option: A
Separation between the slits
Option A (Separation between the slits) is correct because the fringe width is inversely proportional to the separation between the slits.
402 Medium
402 of 418
Understanding +4 | -1
Two waves, travelling in a medium, meet at a point to obtain sustained interference. Choose the best possible option.
View answer and explanation
Correct option: D
Frequency of two waves should be same
Option D is correct because for sustained interference, the two waves must have the same frequency to maintain a constant phase relationship.
403 Medium
403 of 418
Application +4 | -1
In young's interference experiment, if I0\mathrm{I}_0 be the intensity at the central bright fringe, β\beta be the fringe width then the intensity as the function of distance xx from the central bright frings is:
View answer and explanation
Correct option: D
I=I0cos⁡2(πxβ)\mathrm{I}=\mathrm{I}_0 \cos ^2\left(\frac{\pi x}{\beta}\right)
Option D (I=I0cos⁡2(πxβ)\mathrm{I}=\mathrm{I}_0 \cos ^2\left(\frac{\pi x}{\beta}\right)) is correct because it represents the intensity as a function of distance from the central bright fringe in Young's double-slit experiment.
404 Medium
404 of 418
Understanding +4 | -1
If β1,\beta_1, β2\beta_2 and β3\beta_3 are fringe widths for red, green and violet light respectively for the same setup of Young's double slit experiment, then
View answer and explanation
Correct option: D
β1>β2>β3\beta_1>\beta_2>\beta_3
Option D is correct because fringe width is directly proportional to wavelength, and red light has the longest wavelength.
405 Easy
405 of 418
Application +4 | -1
An objective lens of a telescope has diameter 200 cm. The limit of resolution of telescope for wavelength 600 nm is nearly
View answer and explanation
Correct option: B
3.7×10−7rad3.7\mathrm{ } \times \mathrm{ }{10^{-7}}rad
Option B (3.7×10−7rad3.7\mathrm{ } \times \mathrm{ }{10^{-7}}rad) is correct because it's the limit of resolution calculated using the formula θ=1.22λD\theta = \frac{{1.22\lambda }}{D}.
406 Medium
406 of 418
Understanding +4 | -1
In the Young’s double slit experiment, if the phase difference between the two waves interfering at a point is ϕ\phi, the intensity at that point can be expressed by the expression
View answer and explanation
Correct option: D
I=A+Bcos⁡ϕI = A + B\cos \phi
Option D (I=A+Bcos⁡ϕI = A + B\cos \phi) is correct because it represents the intensity at a point in Young's double-slit experiment as a function of the phase difference.
407 Medium
407 of 418
Understanding +4 | -1
Un polarized light of intensity I0I_0 is incident on surface of a block of glass at Brewster's angle. In this case, which one of the following statement is true.
View answer and explanation
Correct option: C
Reflected light is completely polarized with intensity less than I02\frac{I_0}{2}
Option C (Reflected light is completely polarized with intensity less than I02\frac{I_0}{2}) is correct because at Brewster's angle, the reflected light is completely polarized, and its intensity is less than half of the incident unpolarized light.
408 Medium
408 of 418
Understanding +4 | -1
Conditions of diffraction is
View answer and explanation
Correct option: A
aλ=1\frac{a}{\lambda } = 1
Option A (aλ=1\frac{a}{\lambda } = 1) is correct because diffraction occurs when the size of the obstacle or aperture is comparable to the wavelength of the wave.
409 Medium
409 of 418
Application +4 | -1
Fringe width in a YDSE is measured to be β\beta. What will be the fringe width if the wavelength of incident light is tripled, the separation between the slits is halved and the separation between the screen and the slits doubled?
View answer and explanation
Correct option: B
12β12 \beta
Option B (12β12 \beta) is correct because the fringe width is directly proportional to the wavelength and the distance to the screen, and inversely proportional to the slit separation.
410 Medium
410 of 418
Understanding +4 | -1
Assertion: The resolving power of an electron microscope is higher than that of an optical microscope.

Reason: The wavelength of electron is more than tke wavelength of visible light.
View answer and explanation
Correct option: C
Assertion is true and Reason is false
Option C is correct. The resolving power of an electron microscope is higher due to the shorter wavelength of electrons, making the assertion true and the reason false.
411 Medium
411 of 418
Understanding +4 | -1
Light from sodium lamp is passed through cold sodium vapours, the spectrum of transmitted light consists of
View answer and explanation
Correct option: D
No spectral features
Option D (No spectral features) is correct because cold sodium vapor absorbs the same wavelengths it emits, resulting in no transmitted light at those wavelengths.
412 Medium
412 of 418
Analyzing +4 | -1
Assertion : Resolving power of a telescope depends only on wavelength.

Reason : This is proportional to square of wavelength.
View answer and explanation
Correct option: D
If both Assertion and reason are false
Option D (If both Assertion and reason are false) is correct because resolving power depends on wavelength and aperture, and it's inversely proportional to wavelength.
413 Medium
413 of 418
Understanding +4 | -1
In a Young’s double slit experiment, the source illuminating the slits is changed from blue to violet. The width of the fringes
View answer and explanation
Correct option: B
Decreases
Option B (Decreases) is correct because the fringe width is directly proportional to the wavelength, and violet light has a shorter wavelength than blue light.
414 Medium
414 of 418
Remembering +4 | -1
Fraunhoffer spectrum is
View answer and explanation
Correct option: A
Line absorption spectrum
Option A (Line absorption spectrum) is correct because Fraunhofer lines are dark lines in the solar spectrum caused by absorption of specific wavelengths by elements in the Sun's atmosphere.
415 Medium
415 of 418
Understanding +4 | -1
Light of wavelength 2000 A∘2000 \mathrm{~A}^{\circ} falls on a plane reflecting surface. The wavelength of the reflected light will be
View answer and explanation
Correct option: D
2×10−7 m2 \times 10^{-7} \mathrm{~m}
Option D is correct because the wavelength of light does not change upon reflection from a plane reflecting surface.
416 Medium
416 of 418
Application +4 | -1
Two sources of light of wavelengths 2500Ao2500 \mathop {\text{A}}\limits^{\text{o}} and 3500Ao3500 \mathop {\text{A}}\limits^{\text{o}} are used in Young's double slit expt. simultaneously. Which orders of fringes of two wavelength patterns coincide?
View answer and explanation
Correct option: B
7 th order of 1st1 \mathrm{st} and 5 th order of 2nd
Option B (7 th order of 1st1 \mathrm{st} and 5 th order of 2nd) is correct because the 7th fringe of the first wavelength coincides with the 5th fringe of the second wavelength.
417 Medium
417 of 418
Understanding +4 | -1
In Fraunhofer diffraction experiment, LL is the distance between screen and the obstacle,bb is the size of obstacle and λ\lambda is wavelength of incident light. The general condition for the applicability of Fraunhofer diffraction is
View answer and explanation
Correct option: C
b2Lλ<<1\frac{{{b^2}}}{{L\lambda }} < < 1
Option C is correct because the Fraunhofer diffraction condition requires the Fresnel number to be much less than 1, which is equivalent to the given inequality.
418 Medium
418 of 418
Understanding +4 | -1
In a YDSE, if the slits are of unequal widths,
View answer and explanation
Correct option: B
the positions of minimum intensity will not be completely dark
Option B is correct. Due to unequal widths, the interfering waves have different amplitudes, leading to incomplete destructive interference and non-zero minimum intensity.
Revision notes and key takeaways

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