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JEE • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 363 questions

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61 Medium
61 of 363
Application +4 | -1
An electric immersion heater of 1.08 kW is immersed in water. After the water has reached a temperature of 1000C{100^0}C, how much time will be required to produce 100 g of steam
View answer and explanation
Correct option: A
210 s
Option A (210 s) is correct because it calculates the time required to produce steam using the power of the heater and the latent heat of vaporization.
62 Medium
62 of 363
Understanding +4 | -1
During an adiabatic expansion, the increase in volume is associated with which of the following possibilities w.r.t.w\mathrm{.r}\mathrm{.t}\mathrm{.} pressure and temperature 
View answer and explanation
Correct option: B
Pressure - Decrease ; Temperature - Decrease
Option B (Pressure - Decrease ; Temperature - Decrease) is correct because in an adiabatic expansion, the gas does work, reducing its internal energy and thus both temperature and pressure decrease.
63 Medium
63 of 363
Understanding +4 | -1
When heat in given to a gas in an isobaric process, then
View answer and explanation
Correct option: C
Both (a) and (b)
Option C (Both (a) and (b)) is correct because in an isobaric process, heat added increases both the internal energy and does work by the gas.
64 Medium
64 of 363
Remembering +4 | -1
First law of thermodynamics states that
View answer and explanation
Correct option: D
Heat is a form of energy
Option D (Heat is a form of energy) is correct because the first law of thermodynamics is a statement of energy conservation, where heat is a form of energy transfer.
65 Medium
65 of 363
Understanding +4 | -1
When heat is given to a gas in an isothermal change, the result will be
View answer and explanation
Correct option: A
External work done
Option A (External work done) is correct because in an isothermal process, the heat added is entirely converted into work done by the gas.
66 Medium
66 of 363
Understanding +4 | -1
In a reversible isochoric change
View answer and explanation
Correct option: A
ΔW=0\Delta W = 0
Option A is correct because in an isochoric process, the volume remains constant, and therefore no work is done by the system.
67 Medium
67 of 363
Application +4 | -1
A certain amount of heat energy is supplied to a mono atomic ideal gas which expands at constant pressure. What fraction of heat energy is converted into work.
View answer and explanation
Correct option: C
25\frac{2}{5}
Option C (2/5) is correct because for a monoatomic gas expanding at constant pressure, 2/5 of the heat energy is converted into work, based on the first law of thermodynamics.
68 Medium
68 of 363
Analyzing +4 | -1
Assertion: First law of thermodynamics does not forbid flow of heat from lower temperature to higher temperature.
Reason: Heat supplied to a system is not equal to the increase in its internal energy.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct because the first law of thermodynamics does not forbid heat flow from lower to higher temperature, but the reason is false because heat supplied to a system can be equal to the increase in internal energy if no work is done.
69 Medium
69 of 363
Application +4 | -1
The temperature of 5 moles of a gas at constant volume is changed from 100∘C^ \circ C to 120∘C^ \circ C. The change in internal energy is 80 J. the total heat capacity of the gas at constant volume will be in JK−1\mathrm{J}{\mathrm{K}^{ - 1}} is
View answer and explanation
Correct option: C
0.8
Option B (4) is the correct answer because it represents the total heat capacity calculated using the change in internal energy and temperature change.
70 Medium
70 of 363
Analyzing +4 | -1
Assertion(A): Molar heat capacity cannot be defined for isothermal process.

Reason(R): In isothermal process, p−Vp-V versus TT graph is a dot.
View answer and explanation
Correct option: B
Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B is correct because both the assertion and reason are correct, but the reason is not the correct explanation of the assertion. Molar heat capacity is undefined for an isothermal process because ΔT=0\Delta T = 0, not because the p-V versus T graph is a dot.
71 Medium
71 of 363
Understanding +4 | -1
(A): The Carnot cycle is useful to understanding the performance of heat engines.
(R): The Carnot cycle provides a ways of determining the maximum possible efficiency achievable with reservoirs of given temperatures.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because the Carnot cycle is indeed useful for understanding heat engine performance, and the reason correctly explains why: it provides the maximum possible efficiency.
72 Medium
72 of 363
Application +4 | -1
A sample of 1 mole gas at temperature T\mathrm{T} is adiabatically expanded to double its volume. If adiabatic constant for the gas is γ=32\gamma=\frac{3}{2}, then the work done by the gas in the process is:
View answer and explanation
Correct option: A
RT⁡[2−2]\operatorname{RT}[2-\sqrt{2}]
Option A (RT⁡[2−2]\operatorname{RT}[2-\sqrt{2}]) is correct because it represents the work done by the gas during the adiabatic expansion, calculated using the given adiabatic constant and temperature change.
73 Medium
73 of 363
Analyzing +4 | -1
Value of two principle specific heats of a gas in cal (molK)−1{\left( {\mathrm{mol K}} \right)^{ - 1}} determined bt different students are given. Which is most reliable?
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Correct option: C
7, 5
The correct answer is C (7, 5) because the difference between CpC_p and CvC_v should be equal to R, which is approximately 2 cal/(mol K).
74 Medium
74 of 363
Application +4 | -1
Earth receives 1400 W m−21400 \mathrm{~W} \mathrm{~m}^{-2} of solar power. If all the solar energy falling on a lens of area 0.2 m−20.2 \, \mathrm{m}^{-2} is focused on to a block of ice of mass 280 g,280 \, \mathrm{g}, then what is the time (in min) taken by the ice to melt completely? [Lfusion=3.3×105 J kg−1][\mathrm{L}_{\text {fusion}}=3.3 \times 105 \mathrm{~J} \mathrm{~kg}^{-1}]
View answer and explanation
Correct option: A
5.5
Option A (5.5) is correct because the time taken to melt the ice is calculated by dividing the total heat required by the heat received per second.
75 Medium
75 of 363
Application +4 | -1
The coefficient of performance of a refrigerator work between 10∘C{10^ \circ }Cand 20∘C{20^ \circ }C is
View answer and explanation
Correct option: A
28.3
Option A (28.3) is correct because the coefficient of performance is calculated using the formula COP = T2/(T1-T2) where T1 and T2 are the absolute temperatures of the hot and cold reservoirs, respectively.
76 Medium
76 of 363
Remembering +4 | -1
First law of thermodynamics is given by
View answer and explanation
Correct option: A
dQ=dU+PdVdQ = dU + PdV
The correct answer is A (dQ=dU+PdVdQ = dU + PdV) because this is the standard mathematical representation of the first law of thermodynamics, stating that the change in heat equals the change in internal energy plus the work done.
77 Medium
77 of 363
Application +4 | -1
The amount of heat required to convert 10 g of ice at −10∘C- {10^ \circ }C into steam at 100∘C^ \circ C is (in calories)
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Correct option: D
7250
Option D (7250) is correct because it sums the heat required for each phase change and temperature increase.
78 Medium
78 of 363
Application +4 | -1
During adiabatic expansion of 10 moles of a gas, the internal energy decreases by 50 J. Work done during the process is
View answer and explanation
Correct option: A
#ERROR!
Option A (+50 J) is correct because in an adiabatic process, the work done is equal to the negative change in internal energy, so dW=−dUdW = -dU.
79 Medium
79 of 363
Understanding +4 | -1
The radio of the slopes of p−Vp - V graphs of adiabatic and isothermal is
View answer and explanation
Correct option: D
γ\mathrm{\gamma }
Option D is correct because the ratio of the slopes of adiabatic and isothermal p-V graphs is equal to gamma (γ\gamma).
80 Medium
80 of 363
Understanding +4 | -1
If a cylinder containing a gas at high pressure explodes, the gas undergoes
View answer and explanation
Correct option: C
Irreversible adiabatic change and fall of temperature
Option C (Irreversible adiabatic change and fall of temperature) is correct because the sudden explosion is an irreversible process, and the gas does work against the surroundings, causing a temperature drop.
81 Medium
81 of 363
Application +4 | -1
At 0∘C0^{\circ} \mathrm{C} and normal atmospheric pressure, the volume of 1 g1 \mathrm{~g} of water increases from 1 cm31 \mathrm{~cm}^3 to 1.091 cm31.091 \mathrm{~cm}^3 on freezing. What will be the change in its internal energy? Normal atmospheric pressure is 1.013×105 Nm−21.013 \times 10^5 \mathrm{~Nm}^{-2} and latent heat of melting of ice =80 cal g−1=80 \mathrm{~cal} \mathrm{~g}^{-1}.
View answer and explanation
Correct option: A
−80.0022 cal-80.0022 \mathrm{~cal}
Option A (−80.0022 cal-80.0022 \mathrm{~cal}) is correct because it accounts for both the heat lost during freezing and the work done against atmospheric pressure.
82 Medium
82 of 363
Understanding +4 | -1
In changing the state of thermodynamics from AA to BB state, the heat required is QQ and the work done by the system is W . The change in its internal energy is
View answer and explanation
Correct option: B
Q−WQ - W
Option B (Q−WQ - W) is correct because, according to the first law of thermodynamics, the change in internal energy is the heat added to the system minus the work done by the system.
83 Medium
83 of 363
Remembering +4 | -1
Two systems in thermal equilibrium with a third system separately are in thermal equilibrium with each other.
View answer and explanation
Correct option: D
Zeroth law of thermodynamics
Option D (Zeroth law of thermodynamics) is correct because the zeroth law defines thermal equilibrium.
84 Medium
84 of 363
Understanding +4 | -1
A monoatomic gas of nn-moles is heated from temperature T1{T_1} to T2{T_2}under two different conditions (i) at constant volume and (ii) at constant pressure. The change in internal energy of the gas is
View answer and explanation
Correct option: C
Same in both cases
Option C (Same in both cases) is correct because the change in internal energy for an ideal gas depends only on the number of moles, the molar specific heat at constant volume, and the change in temperature, regardless of the process.
85 Medium
85 of 363
Understanding +4 | -1
Internal energy of an ideal gas does not depend upon:
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because the internal energy of an ideal gas depends only on its temperature and not on pressure or volume independently.
86 Medium
86 of 363
Understanding +4 | -1
Which of the following statements is correct for any thermodynamic system?
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Correct option: B
Internal energy and entropy are state functions
Option B (Internal energy and entropy are state functions) is correct because state functions depend only on the initial and final states of the system, not on the path taken.
87 Medium
87 of 363
Analyzing +4 | -1
Assertion: We can not change the temperature of a body without giving (or taking) heat to (or from) it.
Reason: According to principle of conservation of energy, total energy of a system should remain conserved.
View answer and explanation
Correct option: D
If reason is true but assertion is false
Option D is correct because the assertion is false; temperature can change without heat transfer (e.g., adiabatic processes), while the reason about energy conservation is true.
88 Medium
88 of 363
Application +4 | -1
What is the temperature of source in Carnot cycle of 10% efficiency when heat exhausts at 270 K?
View answer and explanation
Correct option: C
300 K
The correct answer is C (300 K) because it is the temperature of the source calculated using the Carnot cycle efficiency formula.
89 Medium
89 of 363
Understanding +4 | -1
Two cylinders of equal capacity are connected to each other via stop cock. AA contains an ideal gas at a standard temperature and pressure, BB is completely evacuated. The entire system is thermally insulated. The stop cock suddenly opens. Which one is correct option?
View answer and explanation
Correct option: D
Change in internal energy is zero
Option D (Change in internal energy is zero) is correct because in free expansion against vacuum, no work is done, and for an ideal gas, internal energy depends only on temperature.
90 Medium
90 of 363
Analyzing +4 | -1
Assertion(A): In isothermal process, whole of the heat energy supplied to the body is converted into internal energy.

Reason(R): According to the first law of thermodynamics,

ΔQ=ΔU+ΔW\Delta Q=\Delta U+\Delta W
View answer and explanation
Correct option: D
Assertion is incorrect but Reason is correct.
The correct answer is D because the assertion is incorrect (heat energy is converted into work, not internal energy in an isothermal process), but the reason (first law of thermodynamics) is correct.
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