JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium

1 of 1

Application +4 | -1

During the adiabatic expansion of 2 moles of a gas, change in internal energy was found to be equal to 100 J. Work done in the process will be equal to

View answer and explanation

Correct option: A

100 J

Option A (100 J) is correct because, in an adiabatic process, the work done is equal to the negative of the change in internal energy.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →

The work done in which of the following process is zero? Water is used to cool the radiators of engines in cars because A gas expand

0.25\,\,{m^3}

at constant pressure

{10^3}N/{m^2},

the work done is A thermodynamic process in which temperature

T

of the system remains constant though other variable

P

and

V

may change, is called What is the slope for an isothermal process? For adiabatic processes

\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)