JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium

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Application +4 | -1

For two substance ratio of mass is

1: 2

and ratio of specific heat is 2 : 3 and its temperature is

10^{\circ} \mathrm{C}

and

40^{\circ} \mathrm{C}

respectively then find out the temperature of mixture.

View answer and explanation

Correct option: D

32.5^{\circ} \mathrm{C}

Option D (

32.5^{\circ} \mathrm{C}

) is correct because it is calculated using the principle of calorimetry, where heat lost equals heat gained.

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