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JEE • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-363 of 363 questions

361 Medium

361 of 363

Understanding +4 | -1

\mathrm{\gamma }

is the ratio of specific heats and

R

is the universal gas constant, then the molar specific heat at constant volume

{C_v}

is given by

View answer and explanation

Correct option: C

\frac{R}{{\mathrm{\gamma } - 1}}

Option C (

\frac{R}{{\gamma - 1}}

) is correct because it is derived from Mayer's formula and the definition of the ratio of specific heats.

362 Medium

362 of 363

Understanding +4 | -1

A thermally insulated container is divided into two parts by a screen. In one part the pressure and temperature are

P

and

T

for an ideal gas filled. In the second part it is vacuum. If now a small hole is created in the screen, then the temperature of the gas will

View answer and explanation

Correct option: C

Remain same

Option C (Remain same) is correct because the free expansion of an ideal gas into a vacuum is an adiabatic process with no external work done, resulting in no temperature change.

363 Medium

363 of 363

Application +4 | -1

An ideal heat engine is working between source at

727^\circ C

and sink at

227^\circ C

. If heat absorbed by it from source is 1000 cal then heat rejected to the sink is

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Correct option: A

2100 J

Option A (2100 J) is correct because it is calculated using the efficiency formula for a heat engine and converting calories to joules.

Revision notes and key takeaways

Review THERMODYNAMICS in your textbook or class notes, then use this set to check your understanding.

Showing 361-363 of 363 questions

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