Question

The pressure of an ideal gas varies with volume as $P = \alpha V,$ where $\alpha$ is a constant. One mole of the gas is allowed to undergo expansion such that its volume becomes $'m'$ times its initial volume. The work done by the gas in the process is

Accepted Answer

$\frac{{\alpha {V^2}}}{2}\left( {{m^2} - 1} \right)$

Answer

$\frac{{\alpha V}}{2}\left( {{m^2} - 1} \right)$

Answer

$\frac{{{\alpha ^2}{V^2}}}{2}\left( {{m^2} - 1} \right)$

Answer

$\frac{\alpha }{2}\left( {{m^2} - 1} \right)$

JEE PHYSICS MCQ: THERMODYNAMICS

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