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JEE • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 331-360 of 384 questions

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331 Medium
331 of 384
Understanding +4 | -1
The heat capacity per mole of water is (R is universal gas constant)
View answer and explanation
Correct option: A
9R9R
Option A (9R9R) is correct because, according to the equipartition theorem, each atom in a water molecule contributes 3R to the molar heat capacity, and a water molecule has 3 atoms.
332 Medium
332 of 384
Understanding +4 | -1
Pi,ViP_i, V_i and Pf,VfP_f, V_f are initial and final pressures and volumes of a gas in a thermodynamic process respectively. If PVn=P V^n= constant, then the amount of work done is
View answer and explanation
Correct option: A
Minimum for n=γn=\gamma
Option C (Minimum for n=0n=0) is correct because the work done is minimum for isobaric process where n=0.
333 Medium
333 of 384
Remembering +4 | -1
which of the following is the unit of specific heat
View answer and explanation
Correct option: B
J/kg  0CJ/kg{\;^0}C
Option B (J/kg  0CJ/kg{\;^0}C) is correct because specific heat is defined as the amount of heat required to raise the temperature of 1 kg of a substance by 1 degree Celsius.
334 Medium
334 of 384
Understanding +4 | -1
A system goes from AA and BB via two processes II and IIII as shown in figure. If ΔU1\Delta {U_1} and ΔU2\Delta {U_2} are the changes in internal energies in the process II and IIII respectively, then
View answer and explanation
Correct option: A
ΔU1=ΔU2\Delta {U_1} = \Delta {U_2}
Option A (ΔU1=ΔU2\Delta {U_1} = \Delta {U_2}) is correct because the change in internal energy is a state function and depends only on the initial and final states, not the path taken.
335 Medium
335 of 384
Remembering +4 | -1
The process in which no heat enters or leaves the system is termed as
View answer and explanation
Correct option: D
Adiabatic
Option D (Adiabatic) is correct because an adiabatic process is defined as one in which no heat is exchanged between the system and its surroundings.
336 Medium
336 of 384
Understanding +4 | -1
Which of the following statements is correct for a thermodynamic gaseous system?
View answer and explanation
Correct option: C
Temperature of system may decrease inspite of heat is being absorbed by the system
The correct answer is C (Temperature of system may decrease inspite of heat is being absorbed by the system) because if the system does work while absorbing heat, its internal energy and thus temperature can decrease.
337 Medium
337 of 384
Application +4 | -1
A Camot engine with efficiency 50% takes heat
from a source at 600 K. In order to increase the
efficiency to 70%, keeping the temperature of sink
same, the new temperature of the source will be:
View answer and explanation
Correct option: D
1000 K
Option D (1000 K) is correct because it is calculated by first finding the temperature of the sink using the initial efficiency and source temperature, and then using the new efficiency and the same sink temperature to find the new source temperature.
338 Medium
338 of 384
Understanding +4 | -1
The internal energy of the gas increases in
View answer and explanation
Correct option: B
Adiabatic compression
Option B (Adiabatic compression) is correct because in adiabatic compression, work is done on the gas, increasing its internal energy.
339 Medium
339 of 384
Understanding +4 | -1
Assertion (A) : First law of thermodynamics can be applied for ideal gases only.

Reason (R) : First law is simply, law of conservation of energy.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D (If Assertion is false but the Reason is true) is correct because the first law of thermodynamics applies to all systems, not just ideal gases, and it is indeed a statement of energy conservation.
340 Medium
340 of 384
Understanding +4 | -1
When you make ice cubes, the entropy of water
View answer and explanation
Correct option: C
decreases
Option C (decreases) is correct because when water freezes into ice, it becomes more ordered, thus decreasing entropy.
341 Medium
341 of 384
Understanding +4 | -1
In isothermal expansion, the pressure is determined by
View answer and explanation
Correct option: B
Compressibility only
Option B is correct because in an isothermal expansion, the pressure is inversely proportional to the volume, and compressibility is the measure of the change in volume with pressure.
342 Easy
342 of 384
Understanding +4 | -1
For an isothermal expansion of a perfect gas, the value of ΔPP\frac{{\Delta P}}{P} is equal
View answer and explanation
Correct option: B
−ΔVV- \frac{{\Delta V}}{V}
Option B is correct because for an isothermal process, the relationship between pressure and volume changes can be derived from the ideal gas law.
343 Medium
343 of 384
Application +4 | -1
1 mm31\,m{m^3} of a gas is compressed at '11' atmospheric pressure and temperature 270C to 6270C{27^0}C\,to\,{627^0}C. What is the final pressure under adiabatic condition (γfor the gas=1.5)\left( {\gamma for\,the\,gas = 1.5} \right)
View answer and explanation
Correct option: A
27×105N/M227 \times {10^5}N/{M^2}
Option A (27×105N/M227 \times {10^5}N/{M^2}) is correct because it follows from the adiabatic condition equation relating pressure and temperature.
344 Medium
344 of 384
Application +4 | -1
A Carnot engine takes heat from a reservoir at 627∘C{627^ \circ }C and rejects heat to a sink at 27∘C{27^ \circ }C. Its efficiency will be
View answer and explanation
Correct option: C
45718
Option C (02-Mar) is correct because the efficiency of a Carnot engine is calculated using the temperatures of the hot and cold reservoirs.
345 Medium
345 of 384
Understanding +4 | -1
A perfect gas contained in a cylinder is kept in vacuum. If the cylinder suddenly bursts, then the temperature of the gas
View answer and explanation
Correct option: A
remains constant
Option A is correct because the free expansion into a vacuum is an adiabatic process with no work done, resulting in no temperature change.
346 Medium
346 of 384
Application +4 | -1
During an adiabatic process, the pressure pp of a fixed mass of an ideal gas changes by Δp\Delta p and its volume VV changes ΔV\Delta V. If γ=Cp/Cv\mathrm{\gamma } = {C_p}/{C_v} , then ΔV/V\Delta V/V is given by
View answer and explanation
Correct option: C
−Δpγp- \frac{{\Delta p}}{{\mathrm{\gamma }p}}
Option C (−Δpγp- \frac{{\Delta p}}{{\mathrm{\gamma }p}}) is correct because it is derived from the adiabatic process equation relating pressure and volume changes.
347 Easy
347 of 384
Understanding +4 | -1
Assertion: First law of thermodynamics is a restatement of the principle of conservation.
Reason: Energy is fundamental quantity.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
The correct answer is C (If assertion is true, but reason is false) because the first law of thermodynamics is indeed a restatement of the principle of conservation of energy, but energy being a fundamental quantity is not the correct reason.
348 Medium
348 of 384
Understanding +4 | -1
The ratio of specific heats (CpCv)\left( {\frac{{{C_p}}}{{{C_v}}}} \right) in terms of degree of freedom (f) is given by:
View answer and explanation
Correct option: B
(1+2f)\left( {1 + \frac{2}{f}} \right)
Option B ((1+2f)( {1 + \frac{{2}}{f}} )) is correct because it represents the correct relationship between the ratio of specific heats and the degrees of freedom.
349 Hard
349 of 384
Application +4 | -1
A diatomic gas (γ=1.4)(\gamma=1.4) does 100 J100 \mathrm{~J} of work in an isobaric expansion. The heat given to the gas is:
View answer and explanation
Correct option: A
350 J350 \mathrm{~J}
Option A (350 J350 \mathrm{~J}) is correct because for an isobaric process, the heat given to the gas is calculated using Q=ΔU+WQ = \Delta U + W, where ΔU=f2nRΔT\Delta U = \frac{f}{2} nR \Delta T and W=nRΔTW = nR \Delta T. For a diatomic gas, f=5f = 5.
350 Medium
350 of 384
Application +4 | -1
When an ideal gas at pressure P,
temperature T and volume V is
isothermally compressed to V/n, its
pressure becomes P1{P_1}. If the same
amount of same gas is compressed
adiabatically to V/n, its pressure
becomes P2{P_2}. The ratio P1/P2{P_1}/{P_2} is :
View answer and explanation
Correct option: C
1nγ−1\frac{1}{{{n^{\gamma - 1}}}}
Option C (1nγ−1\frac{1}{{{n^{\gamma - 1}}}}) is correct because it is derived from the ratio of pressures calculated under isothermal and adiabatic conditions.
351 Medium
351 of 384
Understanding +4 | -1
A given system undergoes a change in which the work done by the system equals the decrease in its internal energy. The system must have undergone an
View answer and explanation
Correct option: B
Adiabatic change
Option B is correct because in an adiabatic process, there is no heat exchange with the surroundings, meaning the work done equals the negative change in internal energy.
352 Medium
352 of 384
Analyzing +4 | -1
Assertion: For an isolated system, mechanical energy is not conserved.
Reason: For an isolated system internal energy is constant.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct. For an isolated system, mechanical energy can be conserved if only conservative forces are acting, and internal energy is not always constant due to processes like friction.
353 Medium
353 of 384
Understanding +4 | -1
The state of a thermodynamic system is represented by
View answer and explanation
Correct option: C
Pressure, volume and temperature
Option C (Pressure, volume and temperature) is correct because these three variables are sufficient to define the state of a thermodynamic system in equilibrium.
354 Medium
354 of 384
Understanding +4 | -1
Assertion: In an adiabatic process change in the internal energy of the gas is equal to work done on or by the gas in the process.

Reason: Temperature of a gas remains constant in adiabatic process.
View answer and explanation
Correct option: C
If assertion is true but reason is false.
Option C is correct because the assertion is true about adiabatic processes, but the reason is false as temperature changes in an adiabatic process.
355 Medium
355 of 384
Application +4 | -1
Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take, molar mass of helium M1=4 gM_1=4 \mathrm{~g} and that of hydrogen M2=2 gM_2=2 \mathrm{~g}. The equivalent value of γ\gamma.
View answer and explanation
Correct option: C
1.561.56
Option C (1.56) is correct because it is calculated using the formula for the equivalent value of γ\gamma for a mixture of gases, considering the number of moles and degrees of freedom of each gas.
356 Easy
356 of 384
Understanding +4 | -1
A gas has nn degrees of freedom. The ratio of specific heat of gas at constant volume to the specific heat of gas at constant pressure will be
View answer and explanation
Correct option: A
nn+2\frac{n}{n+2}
Option A (nn+2\frac{n}{n+2}) is correct because it represents the ratio of specific heat at constant volume to specific heat at constant pressure for a gas with n degrees of freedom.
357 Medium
357 of 384
Application +4 | -1
Assuming radius of earth is ' RR ', specific heat is ' ss ' and angular velocity is ' ω\omega ' if earth rotation is suddenly stop then find out the increasing the temperature of earth surface.
View answer and explanation
Correct option: A
ΔT=ω2R25Js\Delta T=\frac{\omega^2 R^2}{5 J s}
Option A (ΔT=ω2R25Js\Delta T=\frac{\omega^2 R^2}{5 J s}) is correct because the increase in temperature is calculated by equating the rotational kinetic energy to the heat energy gained.
358 Medium
358 of 384
Understanding +4 | -1
Entropy of a system is related with
View answer and explanation
Correct option: A
Disorder of molecular motion of the system
Option A (Disorder of molecular motion of the system) is correct because entropy is a measure of the randomness or disorder of a system at the molecular level.
359 Medium
359 of 384
Understanding +4 | -1
We consider a thermodynamic system. If ΔU\Delta U represents the increase in its internal energy and WW the work done by the system, which of the following statements is true?
View answer and explanation
Correct option: A
ΔU=−W\Delta U = - W in an adiabatic process
Option A (ΔU=−W\Delta U = - W in an adiabatic process) is correct because in an adiabatic process, there is no heat exchange, so the change in internal energy is equal to the negative of the work done by the system.
360 Medium
360 of 384
Application +4 | -1
A sphere and a cube of same material and same total surface area are placed in the same evacuated space turn by turn after they are heated to the same temperature. Find the ratio of their initial rates of cooling in the enclosure
View answer and explanation
Correct option: A
π6:1\sqrt{\frac{\pi}{6}}: 1
Option A (π6:1\sqrt{\frac{\pi}{6}}: 1) is correct because it represents the ratio of initial cooling rates based on surface area to mass ratio.
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