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JEE • PHYSICS • THERMODYNAMICS
Thermodynamics practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 271-300 of 384 questions
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271
Medium
271 of 384
Application
+4 | -1
One gram of water (volume ) becomes 1671 of steam when boiled at a pressure of one atmosphere . Latent heat of vaporization at this pressure is . Compute the work done. ]
View answer and explanation
Correct option: A
169
The correct answer is 169 because the work done is calculated using the formula W = P(V2 - V1) with the given pressure and change in volume.
272
Hard
272 of 384
Understanding
+4 | -1
Identify the characteristics of an adiabatic process in a monoatomic gas.
(A) Internal energy is constant.
(B) Work done in the process is equal to the charge in internal energy.
(C) The product of temperature and volume is a constant.
(D) The product of pressure and volume is a constant.
(E) The work done to change the temperature from to is proportional to
Choose the correct answer from the options given below:
(A) Internal energy is constant.
(B) Work done in the process is equal to the charge in internal energy.
(C) The product of temperature and volume is a constant.
(D) The product of pressure and volume is a constant.
(E) The work done to change the temperature from to is proportional to
Choose the correct answer from the options given below:
View answer and explanation
Correct option: C
(B), (E) only
Option C is correct because in an adiabatic process, the work done is equal to the negative change in internal energy, and the work done is proportional to the change in temperature.
273
Medium
273 of 384
Understanding
+4 | -1
Choose the correct statement
View answer and explanation
Correct option: B
Heat is a path function, while internal energy is not
Option B is correct because heat is a path-dependent function, while internal energy is a state function and depends only on the initial and final states.
274
Medium
274 of 384
Understanding
+4 | -1
The slopes of isothermal and adiabatic curves are related as
View answer and explanation
Correct option: C
Adiabatic curve slope isothermal curve slope
Option C (Adiabatic curve slope isothermal curve slope) is correct because the adiabatic slope is times the isothermal slope.
275
Medium
275 of 384
Understanding
+4 | -1
Assertion: The efficiency of a heat engine can be unity.
Reason: Efficiency of heat engine is fundamental limitation given by first law of thermodynamics.
Reason: Efficiency of heat engine is fundamental limitation given by first law of thermodynamics.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because the efficiency of a heat engine cannot be unity, and the first law of thermodynamics does not impose a fundamental limitation on efficiency.
276
Medium
276 of 384
Analyzing
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Statement-I: Monoatomic, diatomic and polyatomic gases are adiabatically compressed such that compression ratio is . Then monoatomic gas will have maximum final volume out of these three gases.
Statement-II: Monoatomic gas has least degree of freedom.
Statement-II: Monoatomic gas has least degree of freedom.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because monoatomic gases have the least adiabatic index, leading to a maximum final volume after adiabatic compression, and they have the fewest degrees of freedom.
277
Medium
277 of 384
Application
+4 | -1
A carnot engine takes of heat from a reservoir at and gives it to a sink at . The work done by the engine is,
View answer and explanation
Correct option: B
Option B () is correct because it is calculated using the Carnot engine efficiency formula and the heat absorbed and rejected.
278
Medium
278 of 384
Remembering
+4 | -1
The relation between two specific heats of a gas is
View answer and explanation
Correct option: A
Option A () is correct because it represents the relationship between specific heat at constant pressure, specific heat at constant volume, the gas constant, and the mechanical equivalent of heat.
279
Medium
279 of 384
Understanding
+4 | -1
One mole of oxygen is expanded from a volume to at a constant temperature . The change in internal energy is:
View answer and explanation
Correct option: C
0 kJ
Option C (0 kJ) is correct because the internal energy of an ideal gas depends only on its temperature, and since the temperature is constant, the change in internal energy is zero.
280
Medium
280 of 384
Understanding
+4 | -1
An ideal gas A and a real gas B have their volumes increased from V to 2V under isothermal conditions. The increase in internal energy
View answer and explanation
Correct option: C
of B will be more than that of A
Option C is correct. The internal energy of a real gas (B) increases more than that of an ideal gas (A) under isothermal expansion because work is done against intermolecular forces in the real gas.
281
Medium
281 of 384
Analyzing
+4 | -1
(A): A room can not be cooled by opening the door of a refrigerator in a closed room
(R): Heat flows from lower temperature (refrigerator) to higher temperature (room).
(R): Heat flows from lower temperature (refrigerator) to higher temperature (room).
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because a refrigerator transfers heat from a cold reservoir to a hot reservoir, requiring work, and opening it in a closed room will eventually heat the room.
282
Medium
282 of 384
Remembering
+4 | -1
In thermodynamics, heat and work are:
View answer and explanation
Correct option: C
Path functions
Option C (Path functions) is correct because heat and work depend on the process or path taken, not just the initial and final states.
283
Medium
283 of 384
Understanding
+4 | -1
The specific heat of an ideal gas for an isothermal process is
View answer and explanation
Correct option: D
infinite
Option D (infinite) is correct because in an isothermal process, the temperature change is zero, leading to infinite specific heat.
284
Medium
284 of 384
Application
+4 | -1
An engine is supposed to operate between two reservoirs at temperature . The maximum possible efficiency of such an engine is
View answer and explanation
Correct option: A
The correct answer is 2 because it follows from the intensity equation in Young's double slit experiment.
285
Medium
285 of 384
Understanding
+4 | -1
The internal energy of an ideal gas increases during an isothermal process when the gas is
View answer and explanation
Correct option: A
Expanded by adding more molecules to it
Option A (Expanded by adding more molecules to it) is correct because the internal energy of an ideal gas depends on the number of molecules and temperature; at constant temperature, increasing the number of molecules increases internal energy.
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286
Medium
286 of 384
Remembering
+4 | -1
The molar specific heat at constant pressure for a monoatomic gas is
View answer and explanation
Correct option: B
Option B () is correct because for a monoatomic gas, the molar specific heat at constant pressure is given by .
287
Medium
287 of 384
Application
+4 | -1
moles of an ideal gas with constant volume heat capacity undergo an isobaric expansion by certain volume. The ratio of the work done in the process, to the heat supplied is
View answer and explanation
Correct option: D
Option D () is correct because it represents the ratio of work done to heat supplied during an isobaric process for an ideal gas.
288
Medium
288 of 384
Analyzing
+4 | -1
Assertion: A heat engine is the reverse of a refrigerator.
Reason: A refrigerator cannot work without some external work done on the system.
Reason: A refrigerator cannot work without some external work done on the system.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A is correct. Heat engines and refrigerators are reverse processes, and refrigerators require external work to function.
289
Medium
289 of 384
Understanding
+4 | -1
(A): An adiabatic process is an isoentropic process.
(R): Change in entropy is zero in case of adiabatic process.
(R): Change in entropy is zero in case of adiabatic process.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because an adiabatic process is defined as a process with no heat exchange, which implies no change in entropy, making it isoentropic.
290
Medium
290 of 384
Analyzing
+4 | -1
An ideal gas in a piston cylinder arrangement is to be taken from a temperature of to a temperature of . Which of the thermodynamic process given in options should be used so that the final state of is achieved using a minimum energy input from outside?
View answer and explanation
Correct option: C
Isochoric
Option C (Isochoric) is correct because in an isochoric process, no work is done, so all the energy input goes into increasing the internal energy, thus minimizing the energy needed to reach 600 K.
291
Medium
291 of 384
Understanding
+4 | -1
The change of entropy, when heat is absorbed by the gas is:
View answer and explanation
Correct option: A
Positive
Option A is correct because when a gas absorbs heat, its entropy increases as the molecules become more disordered.
292
Medium
292 of 384
Application
+4 | -1
In a Carnot engine, when its efficiency is its efficiency is , then what in
View answer and explanation
Correct option: A
0.577
Option A (0.577) is correct because it represents the ratio of the efficiencies calculated using the Carnot engine efficiency formula with the given temperatures converted to Kelvin.
293
Medium
293 of 384
Understanding
+4 | -1
The theory of refrigerator is based on
View answer and explanation
Correct option: D
None of the above
Option A (Joule –Thomson effect) is incorrect, Option B (Newton’s particle theory) is incorrect, Option C (Joule’s effect) is incorrect, therefore Option D (None of the above) is the correct answer because the refrigerator's operation is based on the second law of thermodynamics.
294
Medium
294 of 384
Application
+4 | -1
An engine takes in compressed steam at and rejects it at . Efficiency of the engine is
View answer and explanation
Correct option: C
0.2
Option C (20%) is correct because the efficiency is calculated by using the formula with temperatures in Kelvin.
295
Medium
295 of 384
Remembering
+4 | -1
In which of the processes, does the internal energy of the system remain constant?
View answer and explanation
Correct option: D
Isothermal
Option D (Isothermal) is correct because an isothermal process occurs at a constant temperature, meaning the internal energy remains constant.
296
Medium
296 of 384
Application
+4 | -1
The for and are and respectively. The standard enthalpy change (in ) for the reaction,
is
is
View answer and explanation
Correct option: B
41.2
Option B (25 mm) is correct because the separation is calculated by determining the positions of the proton and alpha particle when their velocities are perpendicular, considering their circular paths in the magnetic field.
297
Medium
297 of 384
Understanding
+4 | -1
In an isobaric process, , where is What is ?
View answer and explanation
Correct option: D
Work done
Option D is correct because in an isobaric process, the heat added is related to the change in internal energy and the work done, and K represents the work done.
298
Medium
298 of 384
Application
+4 | -1
An ideal gas at pressure and temperature occupies . It is adiabatically compressed to half its original volume. Calculate (a) the final temperature and (b) the work done by the gas in the process. Take .
View answer and explanation
Correct option: A
424 K; 21 J
Option A (424 K; 21 J) is correct because it accurately calculates the final temperature using the adiabatic process formula and the work done using the appropriate formula.
299
Medium
299 of 384
Understanding
+4 | -1
The work done, W during an isothermal process in which 1 mole of the gas expands from an initial volume to a final volume is given by (R=gas constant, T=temperature)
View answer and explanation
Correct option: C
Option C is correct. The work done during an isothermal process is given by the formula .
300
Medium
300 of 384
Understanding
+4 | -1
In an isothermal expansion
View answer and explanation
Correct option: C
Internal energy remains unchanged
Option C is correct because in an isothermal process, the temperature remains constant, and therefore the internal energy, which depends on temperature, also remains unchanged.
Revision notes and key takeaways
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Showing 271-300 of 384 questions
