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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Medium

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301 Medium
301 of 451
Application +4 | -1
A solid sphere and a spherical shell roll down an incline from same height the ratio of times taken by them is
View answer and explanation
Correct option: A
21/25\sqrt {21/25}
Option A (21/25\sqrt {21/25}) is correct because the ratio of times is inversely proportional to the square root of the acceleration, which depends on the moment of inertia.
302 Medium
302 of 451
Application +4 | -1
Two blocks of masses 10 kg and 4 kg connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14  ms−114\mathrm{\;m}{\mathrm{s}^{ - 1}} to the heavier block in the direction of the lighter block. The velocity of the centre of mass is
View answer and explanation
Correct option: C
10  ms−110\mathrm{\;m}{\mathrm{s}^{ - 1}}
Option D (10  ms−110\mathrm{\;m}{\mathrm{s}^{ - 1}}) is correct because it is the velocity of the center of mass calculated using the formula for the center of mass velocity.
303 Medium
303 of 451
Application +4 | -1
Two circular iron discs are of the same thickness. The diameter of A is twice that of B. The moment of inertia of A as compared to that of B is
View answer and explanation
Correct option: D
16 times as large
Option D (16 times as large) is correct because the moment of inertia of a disc is proportional to the fourth power of its radius (or diameter).
304 Medium
304 of 451
Analyzing +4 | -1
Two discs having moment of inertia I1\mathrm{I}_1 and I2\mathrm{I}_2 are made from same material have same mass. Their thickness and radii are t1,t2\mathrm{t}_1, \mathrm{t}_2 and R1,R2\mathrm{R}_1, \mathrm{R}_2 respectively. The relation between moment of inertia of each disc about an axis passing through its centre and perpendicular to its plane and its thickness is
View answer and explanation
Correct option: B
I1t1=I2t2\mathrm{I}_1 \mathrm{t}_1=\mathrm{I}_2 \mathrm{t}_2
Option C (I₁t₁=I₂t₂) is correct because the moment of inertia is proportional to the mass and the square of the radius, and the mass is related to the density, radius, and thickness.
305 Medium
305 of 451
Application +4 | -1
A motor is rotating at a constant angular velocity of 600 rpm. The angular displacement per second is
View answer and explanation
Correct option: D
50π3  rad\frac{{50\mathrm{\pi }}}{3}\mathrm{\;rad}
Option D (50π3  rad\frac{{50\mathrm{\pi }}}{{3}}\mathrm{\;rad}) is correct because it represents the angular displacement per second calculated from the given angular velocity in rpm.
306 Medium
306 of 451
Remembering +4 | -1
The correct relation between moment of inertial II, radius of gyration KK and mass MM of the body is:
View answer and explanation
Correct option: D
K=IMK=\sqrt{\frac{I}{M}}
Option D (K=IMK=\sqrt{\frac{{I}}{{M}}}) is correct because it is the correct formula for the radius of gyration.
307 Medium
307 of 451
Application +4 | -1
Two particles of masses 5 kg and 3 kg moves with velocity 2 ms−12\,m{s^{ - 1}} and 4 ms−14\,m{s^{ - 1}} in the same direction. Find the velocity of centre of mass of the system of two particles is
View answer and explanation
Correct option: A
228 ms−1\frac{{22}}{8}\,m{s^{ - 1}}
Option A (22/8 m/s) is correct because it is the velocity of the center of mass calculated using the formula for the center of mass velocity.
308 Medium
308 of 451
Application +4 | -1
A wheel is rotating at 900rpm900 \mathrm{rpm} about its axis. When power is cut-off, it comes to rest in 1 min1 \mathrm{~min}. The angular retardation (in rads−2\mathrm{rad} \mathrm{s}^{-2} ) is
View answer and explanation
Correct option: A
π2\frac{\pi}{2}
Option A (π2\frac{\pi}{2}) is correct because the angular retardation is calculated by dividing the initial angular velocity by the time taken to come to rest.
309 Medium
309 of 451
Application +4 | -1
Moment of inertia of a solid sphere about its diameter is ' I\mathrm{I} '. It is then casted into 27 small sphere of same diameter. The moment of inertia of each new sphere is
View answer and explanation
Correct option: C
I243\frac{\mathrm{I}}{243}
Option C (I243\frac{\mathrm{I}}{243}) is correct because the moment of inertia is proportional to MR², and both mass and radius change when the sphere is recast.
310 Medium
310 of 451
Application +4 | -1
A wheel is rotating at 480 rpm480 \mathrm{~rpm}. Find the magnitude of angular acceleration required to stop the wheel in 8 seconds?
View answer and explanation
Correct option: A
2π rad.s−22 \pi\mathrm{~rad}.\mathrm{s}^{-2}
Option A (2π rad.s−22 \pi\mathrm{~rad}.\mathrm{s}^{-2}) is correct because it is the angular acceleration required to stop the wheel, calculated using the formula α=ΔωΔt\alpha = \frac{\Delta \omega}{\Delta t}.
311 Medium
311 of 451
Understanding +4 | -1
(A): When couple acting on a body moment of the couple does not depends on the point about which moments are measured.
(R): When a couple acts on a body it is in translational equilibrium.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because a couple results in zero net force but non-zero net torque, and the torque is independent of the point of measurement.
312 Medium
312 of 451
Understanding +4 | -1
A couple produces
View answer and explanation
Correct option: C
Purely rotational motion
Option C is correct because a couple consists of two equal and opposite forces that produce rotation without translation.
313 Medium
313 of 451
Analyzing +4 | -1
Assertion: When a body dropped from a height explodes in mid air, its centre of mass keeps moving in vertically downward direction.
Reason: Explosion occur under internal forces only. External force is zero.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because the explosion is due to internal forces, and the center of mass continues its downward motion unaffected by these internal forces.
314 Medium
314 of 451
Application +4 | -1
A diver having a moment of inertia of 6.0 kg−m26.0 \mathrm{~kg}-\mathrm{m}^2 about an axis through its centre of mass rotates at angular speed of 2 rad/s2 \mathrm{~rad} / \mathrm{s} about this axis. If he folds his hands and feet to decrease the moment of inertia to 5.0 kg−m2,5.0 \mathrm{~kg}-\mathrm{m}^2, what will be the new angular speed?
View answer and explanation
Correct option: A
2.4 rad/s2.4 \mathrm{~rad} / \mathrm{s}
Option A (2.4 rad/s2.4 \mathrm{~rad} / \mathrm{s}) is correct because the angular speed is calculated using the conservation of angular momentum.
315 Medium
315 of 451
Application +4 | -1
Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities ω1  and  ω2.{\omega _1}\mathrm{\; and\; }{\omega _2}. They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is
View answer and explanation
Correct option: C
14I(ω1−ω2)2\frac{1}{4}I{({\omega _1} - {\omega _2})^2}
Option C (14I(ω1−ω2)2\frac{1}{4}I{({\omega _1} - {\omega _2})^2}) is correct because it represents the loss of kinetic energy due to the change in angular velocity after the discs are joined.
316 Medium
316 of 451
Understanding +4 | -1
Moment of inertia (MI) of four bodies, having same mass and radius, are reported as I1=MI{I_1} = MI of thin circular ring about its diameter,
I2=MI{I_2} = MI of circular disk about an axis perpendicular to the disk and going through the centre,
I3=MI{I_3} = MI of solid cylinder about its axis and I4=MI{I_4} = MI of solid sphere about its diameter. Then,
View answer and explanation
Correct option: D
I1=I2=I3>I4{I_1} = {I_2} = {I_3} > {I_4}
Option A (MHMH) is correct because the maximum potential energy of a magnet in a magnetic field occurs when the magnet is aligned anti-parallel to the field.
317 Medium
317 of 451
Application +4 | -1
If an object starts from rest and covers angle of 60 rad60 \mathrm{~rad} in 10 s10 \mathrm{~s} in circular motion, then magnitude of its angular acceleration will be
View answer and explanation
Correct option: A
1.2 rad s−21.2 \mathrm{~rad} \mathrm{~s}^{-2}
Option A (1.2 rad s⁻²) is correct because it correctly applies the rotational motion equation to find the angular acceleration.
318 Medium
318 of 451
Application +4 | -1
A star of mass twice the solar mass and radius 106 km10^6 \mathrm{~km} rotates about its axis with an angular speed of 10−6 rad s−110^{-6} \mathrm{~rad} \mathrm{~s}^{-1}. What is the angular speed of the star when it collapses (due to inward gravitational force) to a radius of 104 km10^4 \mathrm{~km}? Solar mass 1.99×1030 kg1.99 \times 10^{30} \mathrm{~kg}.
View answer and explanation
Correct option: A
0.01 rad s−10.01 \mathrm{~rad} \mathrm{~s}^{-1}
Option A (0.01 rad s−10.01 \mathrm{~rad} \mathrm{~s}^{-1}) is correct because angular momentum is conserved during the collapse, and the angular speed is inversely proportional to the square of the radius.
319 Medium
319 of 451
Understanding +4 | -1
The angular momentum of a system of particles is not conserved
View answer and explanation
Correct option: B
When a net external torque is acting upon the system
Option B (When a net external torque is acting upon the system) is correct because angular momentum is conserved only when the net external torque is zero.
320 Medium
320 of 451
Application +4 | -1
A particle is moving on a circle of radius RR such that at every instant the tangential and radial accelerations are equal in magnitude. If the velocity of the particle be v0{v}_0 at t=0{t}=0, the time for the completion of half of first revolution will be
View answer and explanation
Correct option: B
Rv0(1−e−π)\frac{R}{v_0}\left(1-e^{-\pi}\right)
Option B (Rv0(1−e−π)\frac{R}{v_0}(1-e^{-\pi})) is correct because it represents the time for half a revolution when tangential and radial accelerations are equal.
321 Medium
321 of 451
Remembering +4 | -1
What is the moment of inertia of solid sphere of density ρ\rho and radius R about its diameter?
View answer and explanation
Correct option: C
176105R5ρ\frac{{176}}{{105}}{R^5}\mathrm{\rho }
Option C (176105R5ρ\frac{{176}}{{105}}{R^5}\mathrm{\rho }) is correct because it's derived from the formula for the moment of inertia of a solid sphere about its diameter, substituting mass with density and volume.
322 Medium
322 of 451
Understanding +4 | -1
Assertion: The condition of equilibrium for a rigid body is- Translational equilibrium : ∑F→=0\sum \overrightarrow{\mathrm{F}}=0, (i.e. sum of all external forces equal to zero.) Rotational equilibrium: ∑τ⃗=0\sum \vec{\tau}=0, (i.e. sum of all external forces equal to zero.)
Reason: A rigid body must be in equilibrium under the action of two equal and opposite forces.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because the assertion correctly states the conditions for equilibrium, but the reason provides an insufficient condition.
323 Medium
323 of 451
Understanding +4 | -1
Assertion: The centre of mass of a system of two particles of unequal masses is closer to the heavier particle.
Reason: The centre of mass of a system of two particles divides the distance between the particles in the inverse ratio of their masses.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A is correct because the assertion and reason are both true, and the reason correctly explains why the center of mass is closer to the heavier particle.
324 Medium
324 of 451
Understanding +4 | -1
The centre of mass of a body
View answer and explanation
Correct option: B
May lie within, outside on the surface of the body
Option B (May lie within, outside on the surface of the body) is correct because the center of mass depends on the mass distribution and can be located anywhere relative to the body's physical extent.
325 Medium
325 of 451
Understanding +4 | -1
Two racing cars of masses m1 and m2{m_1}\,and\,{m_2} are moving in circles of radii r1 and r2{r_1}\,and\,{r_2} respectively. Their speeds are such that each makes a complete circle in the same duration of time t.The ratio of the angular speed of the first to the second car is
View answer and explanation
Correct option: C
1:11:1
Option C (1:1) is correct because angular speed is inversely proportional to the time period, and since the time period is the same, the angular speeds are equal.
326 Medium
326 of 451
Analyzing +4 | -1
(A): The hard boiled egg and raw egg can be distinguished on the basis of spinning of both.
(R): The moment of inertia of hard boiled egg is more as compare to raw egg.
View answer and explanation
Correct option: C
(A) is true but (R) is false
Option C is correct because the assertion is true, but the reason is false. Hard and raw eggs can be distinguished by spinning, but the moment of inertia of a hard-boiled egg is less than that of a raw egg.
327 Medium
327 of 451
Understanding +4 | -1
If the torque of the rotational motion by zero,
then the constant quantity will be
View answer and explanation
Correct option: A
angular momentum
Option A (angular momentum) is correct because when the net torque is zero, the angular momentum remains constant due to the relationship τ=dL/dt\tau = dL/dt.
328 Medium
328 of 451
Application +4 | -1
A solid sphere, hollow sphere, solid cylinder, hollow cylinder and ring each of mass MM and radius RR are simultaneously released at rest from top of incline and allowed to roll down the incline. The angular acceleration is maximum for
View answer and explanation
Correct option: A
Solid sphere
Option A (Solid sphere) is correct because it has the smallest moment of inertia, leading to the highest angular acceleration.
329 Medium
329 of 451
Remembering +4 | -1
What is the angular velocity of earth
View answer and explanation
Correct option: A
2π86400  rad/sec\frac{{2\pi }}{{86400}}\;rad/sec
Option A (2π86400  rad/sec\frac{{2\pi }}{{86400}}\;rad/sec) is correct because the Earth completes one rotation (2π2\pi radians) in 24 hours, which is 86400 seconds.
330 Medium
330 of 451
Remembering +4 | -1
The moment of inertia (I)(I) of a sphere of radius RR and mass MM is given by
View answer and explanation
Correct option: D
I=(2/5)MR2I=(2 / 5) M R^2
Option D (I=(2/5)MR2I=(2 / 5) M R^2) is correct because it is the standard formula for the moment of inertia of a solid sphere about its diameter.
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