JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A solid sphere of radius

R

has its outer half removed, so that its radius becomes

(R / 2)

. Then its moment of inertia about the diameter is

View answer and explanation

Correct option: D

becomes

\frac{1}{32}

of initial volume

Option D (becomes

\frac{1}{32}

of initial volume) is correct because the moment of inertia depends on both mass and radius, and both are reduced when the outer half is removed.

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