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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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If the equation for the displacement of a particle moving on a circular path is given by (θ)=2t3+0.5\left( \theta \right) = 2{t^3} + 0.5, where θ\theta is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start is
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Correct option: C
24 rad/sec
Option C (24 rad/sec) is correct because the angular velocity is the derivative of the angular displacement with respect to time, evaluated at t=2s.

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