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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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The moment of inertia of a body about a given axis is 2.4 kg−m22.4\,kg - {m^2}. To produce a rotational kinetic energy of 750 J, an angular acceleration of 5 rad/s2{s^2} must be applied about the axis for
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Correct option: B
5 sec
Option B (5 sec) is correct because it is calculated using the rotational kinetic energy formula and angular acceleration formula.

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