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JEE • PHYSICS • OSCILLATIONS

Oscillations practice · Mixed difficulty

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91 Medium
91 of 483
Understanding +4 | -1
A body is executing simple harmonic motion with
frequency 50 Hz, the frequency of its potential
energy is:
View answer and explanation
Correct option: A
100 Hz
Option A (100 Hz) is correct because the frequency of potential energy in SHM is twice the frequency of the SHM itself.
92 Medium
92 of 483
Application +4 | -1
The total energy of a particle executing S.H.M is 80 J. what is the potential energy when the particle is at a distance of 3/4 of amplitude from the mean position
View answer and explanation
Correct option: D
45 J
Option D (45 J) is correct because the potential energy is calculated as a fraction of the total energy based on the displacement from the mean position.
93 Medium
93 of 483
Understanding +4 | -1
A simple pendulum is taken from the equator to the pole. Its period
View answer and explanation
Correct option: A
Decreases
Option A (Decreases) is correct because the time period of a simple pendulum is inversely proportional to the square root of the acceleration due to gravity, which increases from the equator to the pole.
94 Medium
94 of 483
Application +4 | -1
The time period of a body suspended by a spring be TT. What will be the new period, if the spring is cut into two equal parts and when (i) the body is suspended from one part (ii) the body is suspended from both the parts connected in parallel.
View answer and explanation
Correct option: A
T/2;T/2T / \sqrt{2}; T / 2
Option A (T/2;T/2T / \sqrt{2}; T / 2) is correct because cutting the spring changes the spring constant, affecting the time period of the oscillation.
95 Medium
95 of 483
Application +4 | -1
If a spring has time period TT, and is cut into nn equal parts, then the time period of each part will be-
View answer and explanation
Correct option: B
T/nT / \sqrt{n}
Option B (T/nT / \sqrt{n}) is correct because the time period is inversely proportional to the square root of the spring constant, and cutting the spring into n parts increases the spring constant of each part by a factor of n.
96 Medium
96 of 483
Application +4 | -1
A simple pendulum has time period T1{T_1}.The point of suspension is now moved upward according to the relation y=kt2,(k=1ms−2)y = k{t^2},\left( {k = 1\mathrm{m}{\mathrm{s}^{ - 2}}} \right) where y is the vertical displacement. The time period now becomes T2{T_2} The ratio of T12T22\frac{{T_1^2}}{{T_2^2}} is (g=10ms−2)\left( {\mathrm{g} = 10\mathrm{m}{\mathrm{s}^{ - 2}}} \right)
View answer and explanation
Correct option: A
6⁄5
Option A (6⁄5) is correct because the effective acceleration due to gravity changes when the suspension point moves upwards, affecting the time period.
97 Medium
97 of 483
Application +4 | -1
A person of mass 80 Kg80 \mathrm{~Kg} sits on a spring and the spring compresses by 2 m2 \mathrm{~m}. If the person himself is projected at 20 ms−120 \mathrm{~ms}^{-1} velocity by the spring then the spring constant of the spring in Nm−1\mathrm{Nm}^{-1} is
View answer and explanation
Correct option: D
8000
Option D (8000) is correct because the spring constant is calculated using the conservation of energy principle, equating the spring's potential energy to the kinetic energy of the person.
98 Medium
98 of 483
Application +4 | -1
A particle is oscillating according to the equation V(t)=4sin⁡0.4πtV(t)=4 \sin 0.4 \pi t metres. In how much time after the motion begins will that particle reach the extreme position form the mean position?
View answer and explanation
Correct option: A
1.25 s1.25 \mathrm{~s}
Option A (1.25 s1.25 \mathrm{~s}) is correct because it is the time taken to reach the extreme position, calculated as T/4.
99 Medium
99 of 483
Analyzing +4 | -1
A sealed spherical ball half filled with a volatile liquid is used as the bob of a pendulum executing simple harmonic motion with period T1T_1. The bob is heated slightly so that the liquid evaporates completely and the period is now found to be T2T_2. Which one of the following is true?
View answer and explanation
Correct option: C
T2<T1T_2 < T_1
Option C (T2<T1T_2 < T_1) is correct because when the liquid evaporates, the center of mass shifts closer to the pivot point, effectively shortening the pendulum's length and thus decreasing the period.
100 Medium
100 of 483
Understanding +4 | -1
In simple harmonic motion, loss of kinetic energy is proportional to
View answer and explanation
Correct option: D
x2x^2
Option D (x2x^2) is correct because the potential energy, and thus the loss of kinetic energy, in SHM is proportional to the square of the displacement.
101 Medium
101 of 483
Application +4 | -1
A particle which is attached to a spring oscillates horizontally with simple harmonic motion with a frequency of 1/π Hz1 / \pi \mathrm{~Hz} and total energy of 10 J10 \mathrm{~J}. If the maximum speed of the particle is 0.4 ms−10.4 \mathrm{~ms}^{-1}, what is the force constant of the spring? What will be the maximum potential energy of the spring during the motion?
View answer and explanation
Correct option: A
500 Nm−1,10 J500 \mathrm{~Nm}^{-1}, 10 \mathrm{~J}
Option A (500 Nm−1,10 J500 \text{ Nm}^{-1}, 10 \text{ J}) is correct because the force constant and maximum potential energy are calculated correctly using the given frequency, total energy, and maximum speed.
102 Medium
102 of 483
Understanding +4 | -1
Which one of the following is an example of the
force of gravity of the earth acting on a
vibrating pendulum bob?
View answer and explanation
Correct option: C
Restoring force
Option C (Restoring force) is correct because the force of gravity acting on a vibrating pendulum bob pulls it towards the equilibrium position, thus acting as a restoring force.
103 Medium
103 of 483
Understanding +4 | -1
The motion which is not simple harmonic is
View answer and explanation
Correct option: C
Motion of a planet around the sun
Option C (Motion of a planet around the sun) is correct because planetary motion is elliptical and does not follow the restoring force principle of simple harmonic motion.
104 Medium
104 of 483
Understanding +4 | -1
S-I: In a simple harmonic oscillation the average potential energy in one time period is equal to the average kinetic energy in this period.
S-II: The average kinetic energy for one oscillation is equal to half of total mechanical energy.
View answer and explanation
Correct option: A
S-I &\& S-II are true
Option A (S-I & S-II are true) is correct because in SHM, the average potential and kinetic energies over one time period are equal, and each is half the total mechanical energy.
105 Medium
105 of 483
Application +4 | -1
A body oscillates with a simple harmonic motion having amplitude 0.05 m0.05 \mathrm{~m}. At a certain instant, its displacement is 0.01 m0.01 \mathrm{~m} and acceleration is 1.0 m/s21.0 \mathrm{~m} / \mathrm{s}^2. The period of oscillation is
View answer and explanation
Correct option: D
π5 s\frac{\pi}{5} \mathrm{~s}
Option D (π5 s\frac{\pi}{5} \mathrm{~s}) is correct because the period is calculated from the angular frequency, which is derived from the given displacement and acceleration.
106 Easy
106 of 483
Understanding +4 | -1
In a seconds pendulum, the mass of the bob is 30 g30 \mathrm{~g}. If it is replaced by 90 g90 \mathrm{~g} mass, then its time period will be
View answer and explanation
Correct option: B
2 s2 \mathrm{~s}
Option B (2 s) is correct because the time period of a simple pendulum depends only on its length and the acceleration due to gravity, not on the mass of the bob.
107 Medium
107 of 483
Application +4 | -1
Two simple harmonic motions are represented by y1=4sin⁡(4πt+π2){y_1} = 4\sin \left( {4\pi t + \frac{\pi }{2}} \right) and   y2=3cos⁡(4πt)\;{y_2} = 3\cos \left( {4\pi t} \right) The resultant amplitude is
View answer and explanation
Correct option: A
7
Option A (7) is correct because the two SHM equations are in phase, so the amplitudes add directly.
108 Medium
108 of 483
Analyzing +4 | -1
The displacement of a particle along the xx axis is given by x=asin⁡2ωtx = a{\sin ^2}\omega t The motion of the particle corresponds to
View answer and explanation
Correct option: D
Non simple harmonic motion
Option D (Non simple harmonic motion) is correct because the given displacement equation does not represent simple harmonic motion.
109 Medium
109 of 483
Application +4 | -1
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time (in seconds) is
View answer and explanation
Correct option: B
8π3\frac{{8\pi }}{3}
Option B (8π3\frac{{8\pi }}{{3}}) is correct because the periodic time is calculated using the relationship between velocity, acceleration, amplitude, and angular frequency in SHM.
110 Medium
110 of 483
Application +4 | -1
A particle moving on xx-axis has potential energy U=2−20x+5x2U=2-20 x+5 x^2 joule along xx-axis. The particle is released at x=−3x=-3. The maximum value of xx will be (xx is in metre)
View answer and explanation
Correct option: C
7 m7 \mathrm{~m}
Option C (7 m7 \mathrm{~m}) is correct because the maximum value of x is found by determining the equilibrium position and using the amplitude of the oscillation.
111 Medium
111 of 483
Application +4 | -1
If the maximum acceleration of a SHMSHM is α\alpha and the maximum velocity is β\beta, then the amplitude of vibration is
View answer and explanation
Correct option: C
β2α\frac{{{\beta ^2}}}{\alpha }
Option C (β2α\frac{{{\beta ^2}}}{\alpha }) is correct because it is derived from the relationship between maximum acceleration, maximum velocity, angular frequency, and amplitude in SHM.
112 Medium
112 of 483
Understanding +4 | -1
In a linear Simple Harmonic Motion (SHM)

(A) Restoring force is directly proportional to the
displacement.

(B) The acceleration and displacement are
opposite in direction.

(C) The velocity is maximum at mean position.

(D) The acceleration is minimum at extreme points.
Choose the correct answer from the options given
below:
View answer and explanation
Correct option: C
(A), (B) and (C) only
Option C ((A), (B) and (C) only) is correct because it accurately describes the properties of Simple Harmonic Motion (SHM).
113 Medium
113 of 483
Understanding +4 | -1
Assertion: Pendulum clocks go slow in summer and fast in winter.
Reason: The length of the pendulum used in clock increases in summer.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the length of a pendulum increases in summer due to thermal expansion, which increases the time period and makes the clock go slow.
114 Medium
114 of 483
Analyzing +4 | -1
The displacement of a particle along the x{x}-axis is given by The motion of the particle corresponds to
View answer and explanation
Correct option: C
Non simple harmonic motion
Option C (Non simple harmonic motion) is correct because the given displacement equation, x=asin⁡2ωtx = a \sin^2 \omega t, does not satisfy the condition for simple harmonic motion, which requires acceleration to be proportional to the negative of displacement.
115 Medium
115 of 483
Understanding +4 | -1
There is a large difference between the frequencies of external periodic force and natural frequency of a body. The body will:
View answer and explanation
Correct option: D
Vibrate with small amplitude and with frequency of force
Option D (Vibrate with small amplitude and with frequency of force) is correct because when the external force frequency is very different from the natural frequency, the amplitude is small, and the body vibrates at the driving frequency.
116 Medium
116 of 483
Understanding +4 | -1
The principle involved in the performance of a
spinning-chair circus acrobat is
View answer and explanation
Correct option: A
conservation of angular momentum
Option A (conservation of angular momentum) is correct because the acrobat changes their moment of inertia, leading to a change in angular velocity to conserve angular momentum.
117 Medium
117 of 483
Understanding +4 | -1
S-I: In a simple harmonic oscillation the average potential energy in one time period is equal to the average kinetic energy in this period.
S-II: The average kinetic energy for one oscillation is equal to half of total mechanical energy.
View answer and explanation
Correct option: A
S-I &\& S-II are true
Option A is correct because in SHM, the average potential energy and average kinetic energy over one time period are equal, and each is half the total mechanical energy.
118 Medium
118 of 483
Analyzing +4 | -1
A particle, with restoring force proportional to displacement and resisting force proportional to velocity is subjected to a force. F=F0sin⁡ωtF = {F_0}\sin \omega t If the amplitude of the particle is maximum for &omega;=ω1{\omega _1} and the energy of the particle is maximum for &omega;=ω2{\omega _2} then
View answer and explanation
Correct option: C
ω1≠ω0  and  ω2=ω0{\omega _1} \ne {\omega _0}\,\,\mathrm{and}\,\,{\omega _2} = {\omega _0}
Option C (ω1≠ω0  and  ω2=ω0{\omega _1} \ne {\omega _0}\,\,\mathrm{and}\,\,{\omega _2} = {\omega _0}) is correct because amplitude resonance occurs at a frequency slightly less than the natural frequency, while energy (or velocity) resonance occurs at the natural frequency.
119 Medium
119 of 483
Application +4 | -1
A particle is attached to a vertical spring and is pulled down a distance 4 cm4 \mathrm{~cm} below its equilibrium and is released from rest. The initial upward acceleration is 0.5 ms−20.5 \mathrm{~ms}^{-2}. The angular frequency of oscillation is
View answer and explanation
Correct option: A
3.53 rad/s3.53 \mathrm{~rad} / \mathrm{s}
Option A (3.53 rad/s) is correct because the angular frequency is calculated from the initial upward acceleration and displacement.
120 Easy
120 of 483
Understanding +4 | -1
Assertion(A): In SHM, v−xv-x graph is an ellipse, where vv is velocity and xx is displacement from mean position.

Reason(R): Equation between vv and xx is v2ω2+x21=A2\frac{v^2}{\omega^2}+\frac{x^2}{1}=A^2.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A (If both Assertion and Reason are correct and Reason is the correct explanation of Assertion) is correct because the equation relating velocity and displacement in SHM represents an ellipse, and the given equation is the correct form.
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