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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A block of mass

M

is suspended from a light spring of force constant

k

. Another mass

m

moving upwards with velocity

v

hits the mass

M

and gets embedded in it. What will be the amplitude of oscillation of the combined mass?

View answer and explanation

Correct option: D

\frac{m v}{\sqrt{(M+m) k}}

Option D (

\frac{m v}{\sqrt{(M+m) k}}

) is correct because it represents the amplitude of oscillation of the combined mass, calculated using conservation of momentum and energy.

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{y_1}

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{y_2}

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