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JEE PHYSICS MCQ: OSCILLATIONS

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The equation of linear simple harmonic motion is

x=8 \cos (12 \pi t)

where

x

is in

\mathrm{cm}

and

t

is in second. The initial phase angle is:

View answer and explanation

Correct option: C

\pi / 2 \mathrm{~rad}

Option C (

\pi / 2 \mathrm{~rad}

) is correct because the given equation can be rewritten in terms of sine with an initial phase of

\pi/2

.

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Assertion: A particle executing simple harmonic motion comes to rest at the extreme positions.

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x

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y

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a

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SHM

. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)