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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A particle is moving with SHM in a straight line. When the distance of the particle from the equilibrium position has values

x_1

and

x_2

, the corresponding values of velocities are

u_1

and

u_2

. the time period of oscillation

T=

View answer and explanation

Correct option: A

2 \pi\left[\frac{x_2^2-x_1^2}{u_1^2-u_2^2}\right]^{1 / 2}

Option A (

2 \pi\left[\frac{x_2^2-x_1^2}{u_1^2-u_2^2}\right]^{1 / 2}

) is correct because it is derived from the relationship between velocity, displacement, and angular frequency in SHM.

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. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)