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JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 384 questions

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151 Medium
151 of 384
Application +4 | -1
To the free end of spring hanging from a rigid support, a block of mass m is hung and slowly allowed to come to its equilibrium position. Then stretching in the spring is d. if the same block is attached to the same spring and allowed to fall suddenly, the amount of stretching is (force constant ,k)
View answer and explanation
Correct option: B
2d
Option B (2d) is correct because when the block is suddenly released, it oscillates, and the maximum extension is twice the static extension.
152 Medium
152 of 384
Understanding +4 | -1
A student unable to answer a question on Newton’s law of motion attempts to pull himself up by tugging on his hair. He will not succeed
View answer and explanation
Correct option: D
As the force applied is internal to the system
Option D (As the force applied is internal to the system) is correct because an internal force cannot change the momentum of the system.
153 Medium
153 of 384
Understanding +4 | -1
One feels heavier in a lift when the lift
View answer and explanation
Correct option: B
Just begins to go up
Option B (Just begins to go up) is correct because when the lift accelerates upwards, there is an additional pseudo force acting downwards, making one feel heavier.
154 Medium
154 of 384
Application +4 | -1
When a bus of mass 1000 kg1000 \mathrm{~kg} is moving with a velocity of 20 ms−120 \mathrm{~ms}^{-1} on a rough horizontal road, surface its engine is switched off then, how far does the bus move before it comes to rest (velocity =0=0 ) if the coefficient of kinetic friction between the road surface and tyres of the bus is 0.75 ?
View answer and explanation
Correct option: A
26.67 m26.67 \mathrm{~m}
Option A (26.67 m26.67 \mathrm{~m}) is correct because the stopping distance is calculated using the formula S=v22μkgS=\frac{\mathrm{v}^2}{2 \mu_{\mathrm{k}} \mathrm{g}}.
155 Medium
155 of 384
Application +4 | -1
A box of mass m kg is placed on the rear side of an open truck accelerating at t  ms−2t\;\mathrm{m}{\mathrm{s}^{ - 2}}. The coefficient of friction between the box and the surface below it is 0.4. The net acceleration of the box with respect to the truck is zero. The value of m is [Given g=10  ms−2\mathrm{g} = 10\mathrm{\;m}{\mathrm{s}^{ - 2}})
View answer and explanation
Correct option: D
It could be any value
Option D (It could be any value) is correct because the condition for the box not to slide is independent of the mass of the box.
156 Medium
156 of 384
Application +4 | -1
A golf ball of mass 50 gm50 \,{gm} placed on a tee, is truck by a golf-club. The speed of the golf ball as it leaves the tee is 100 m/s100 {~m} / {s}, the time of contact on the ball is 0.02 s0.02 {~s}. If the force decreases to zero linearly with time, then the force at the beginning of the contact is
View answer and explanation
Correct option: C
250 N250 {~N}
Option B (−75%-75 \%) is correct because the de-Broglie wavelength is inversely proportional to the square root of the kinetic energy.
157 Medium
157 of 384
Understanding +4 | -1
A lift is moving upwards with a uniform velocity v in which a block of mass m is lying. The frictional force offered by the block, when coefficient of the frictional is μ\mu, will be
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because if the block is at rest relative to the lift moving with uniform velocity, there is no relative motion and hence no frictional force.
158 Medium
158 of 384
Analyzing +4 | -1
Assertion : A cyclist always bends inwards while negotiating a curve.
Reason : By bending, cyclist lowers his centre of gravity.
View answer and explanation
Correct option: C
Assertion is correct, reason is incorrect.
Option C is correct because while the cyclist does bend inwards, the primary reason is to obtain the necessary centripetal force, not to lower the center of gravity.
159 Medium
159 of 384
Understanding +4 | -1
When a particle moves in a circle with a uniform speed
View answer and explanation
Correct option: D
Its velocity and acceleration both change
Option D (Its velocity and acceleration both change) is correct because while the speed is constant, the direction of velocity and acceleration are continuously changing in circular motion.
160 Medium
160 of 384
Analyzing +4 | -1
Assertion: Animate object can accelerate in the absence of external force.

Reason: Newton's second law is not applicable on animate object.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option C is correct. Animate objects can accelerate without external forces due to internal mechanisms, but Newton's second law still applies to them when considering the net external force.
161 Medium
161 of 384
Application +4 | -1
A motorcyclist wants to drive on the vertical surface of wooden 'well' of radius 5 m5 \mathrm{~m}, with a minimum speed of 55 ms−15 \sqrt{5} \mathrm{~ms}^{-1}. The minimum value of coefficient of friction between the tyres and the wall of the well must be (Take, g=10 ms−2g=10 \mathrm{~ms}^{-2})
View answer and explanation
Correct option: D
0.400.40
Option D (0.400.40) is correct because it calculates the minimum coefficient of friction required to prevent the motorcyclist from slipping down the wall.
162 Medium
162 of 384
Application +4 | -1
A car moves at a speed of 20 ms−120 \mathrm{~ms}^{-1} on a banked track and describes an arc of a circle of radius 403 m40 \sqrt{3} \mathrm{~m}. The angle of banking is (g=10 ms−2)\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)
View answer and explanation
Correct option: D
30∘30^{\circ}
Option D (30∘30^{\circ}) is correct because the angle of banking is calculated using the formula tan⁡θ=v2rg\tan \theta = \frac{{v^2}}{{rg}}.
163 Medium
163 of 384
Application +4 | -1
A lift of mass 1000 kg1000 \mathrm{~kg} which is moving with acceleration of 1 m/s21 \mathrm{~m} / \mathrm{s}^2 in upward direction, then the tension developed in string which is connected to lift is
View answer and explanation
Correct option: B
10800 N10800 \mathrm{~N}
Option B (10800 N10800 \mathrm{~N}) is correct because it is the tension calculated using the formula T=m(g+a)T = m(g + a) for an upward accelerating lift.
164 Medium
164 of 384
Application +4 | -1
A block is lying on the horizontal frictionless surface. One end of a uniform rope is fixed to the block which is pulled in the horizontal direction by applying a force FF at the other end. If the mass of the rope is half the mass of the block, the tension in the middle of the rope will be
View answer and explanation
Correct option: D
5F/65 F / 6
Option D (5F/65 F / 6) is correct because the tension in the middle of the rope is calculated based on the mass of the block, mass of the rope, and the applied force.
165 Medium
165 of 384
Understanding +4 | -1
Assertion: A man in a closed cabin falling freely experience weightlessness.
Reason: Inertial and gravitational mass have equivalence.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because a freely falling man in a closed cabin experiences weightlessness due to the equivalence of inertial and gravitational mass, as predicted by the equivalence principle.
166 Medium
166 of 384
Analyzing +4 | -1
A parachutist is in free fall before opening her parachute. The net force on her has a magnitude FF and is directed downwards. This net force is somewhat less than, her weight ww because of air resistance. Then, she opens her parachute. At the instant after her parachute fully inflates, the net force on her would be
View answer and explanation
Correct option: D
directed upwards but could be more or less than FF
Option D (directed upwards but could be more or less than FF) is correct because after the parachute opens, the air resistance force increases significantly, potentially exceeding the weight, causing upward net force.
167 Medium
167 of 384
Understanding +4 | -1
Which of the following statement is NOT true for kinetic friction?
View answer and explanation
Correct option: C
Its value depends on the type of motion.
Option C is correct because kinetic friction depends on the normal reaction and is slightly less than limiting friction, but it's independent of the type of motion.
168 Medium
168 of 384
Analyzing +4 | -1
Statement-1: A man starts walking towards west. Friction force on him acts towards east.
Statement-2 : Friction opposes relative motion.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because the friction force acts in the direction of motion when a person walks, and friction opposes relative motion.
169 Medium
169 of 384
Understanding +4 | -1
A shell initially at rest explodes into two pieces of equal mass, then the two pieces will
View answer and explanation
Correct option: C
move with the same velocity in opposite directions
Option C (move with the same velocity in opposite directions) is correct because, due to the conservation of linear momentum, the two pieces must have equal and opposite momenta after the explosion.
170 Medium
170 of 384
Application +4 | -1
A body of weight 64 N is pushed with just enough force to start it moving across a horizontal floor and the same force continues to act afterwards. If the coefficients of static and dynamic friction are 0.6 and 0.4 respectively, the acceleration of the body will be (Acceleration due to gravity =g)
View answer and explanation
Correct option: D
0.2 g
Option A (2.3,4.6,6.92.3, 4.6, 6.9) is correct because these values represent the time constants required for the current to reach 90%, 99%, and 99.9% of its steady-state value in an LR circuit.
171 Medium
171 of 384
Understanding +4 | -1
Statement-I: The apparent weight of a body in an elevator moving with some downward acceleration is less than the actual weight of body.
Statement-II: The part of the weight is spent in producing downward acceleration, when body is in elevator.
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option A (Statement-I is true and statement-II is true) is correct because the apparent weight is less than the actual weight when there's downward acceleration, and this is because the net force is reduced.
172 Medium
172 of 384
Understanding +4 | -1
Statement-I: When the lift moves with uniform velocity the man in the lift will feel weightlessness.
Statement-II: In downward accelerated motion of lift, apparent weight of a body increases.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option A (Is changing with time) is correct because displacement current is proportional to the rate of change of electric flux, which occurs when the charge on the capacitor is changing.
173 Medium
173 of 384
Understanding +4 | -1
Shock absorbers are used in vehicles to reduce the magnitude of
View answer and explanation
Correct option: A
impulsive force
Option A (impulsive force) is correct because shock absorbers increase the time over which the force acts, thus reducing the magnitude of the impulsive force.
174 Medium
174 of 384
Analyzing +4 | -1
Assertion : Impulse of force and momentum are same physical quantities.
Reason : Both quantities have same unit.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct.
Option D is correct because impulse and momentum are different physical quantities, although they share the same units.
175 Medium
175 of 384
Understanding +4 | -1
It is easier to draw up a wooden block along an inclined plane than to haul it vertically, principally because
View answer and explanation
Correct option: C
Only a part of the weight has to be overcome
Option C is correct because when pulling along an inclined plane, only a component of the weight (mg sin θ) needs to be overcome, which is less than the full weight (mg) when hauling vertically.
176 Medium
176 of 384
Application +4 | -1
The position vector of a particle related to time tt is given by r⃗=(5t2i^+3tj^+4k^)\vec{r}=\left(5 t^2 \hat{i}+3 t \hat{j}+4 \hat{k}\right). The direction of net force experienced by the particle is
View answer and explanation
Correct option: A
Along positive xx-axis
Option A (Along positive xx-axis) is correct because the net force is proportional to the acceleration, and the acceleration vector is along the positive x-axis.
177 Medium
177 of 384
Application +4 | -1
A block can slide on a smooth inclined plane of inclination θ\mathrm{\theta } kept on the floor of a lift. When the lift is descending with a retardation a, the acceleration of the block relative to the incline is
View answer and explanation
Correct option: A
(g+a)sin⁡θ\left( {g + a} \right)\sin \theta
Option A ((g+a)sin⁡θ\left( {g + a} \right)\sin \theta) is correct because the effective acceleration due to the lift's retardation adds to the gravitational acceleration.
178 Medium
178 of 384
Application +4 | -1
A body takes time t to reach the bottom of an inclined plane of angle θ\theta with the horizontal. If the plane is made rough, time taken now is 2t. The coefficient of the friction of the rough surface is
View answer and explanation
Correct option: A
34tan⁡θ\frac{3}{4}\tan \theta
Option A (34tan⁡θ\frac{{3}}{{4}}\tan \theta) is correct because it is derived from comparing the accelerations with and without friction using the given time relationship.
179 Medium
179 of 384
Understanding +4 | -1
A ball moves in a frictionless inclined table without slipping. The work done by the table surface on the ball is
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because if the table is frictionless, there is no frictional force acting on the ball, and therefore no work done by the table surface.
180 Medium
180 of 384
Application +4 | -1
A body of mass 0.1 kg0.1 {~kg} attains a velocity of 10{1 0} ms−1{ms}^{-1} in 0.1 s0.1 {~s}. The force acting on the body is
View answer and explanation
Correct option: A
10 N10 {~N}
The correct answer is A (10 N) because it is the force calculated using Newton's second law of motion.
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