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JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Hard
1 of 6
Application +4 | -1
A body of mass 0.4 kg0.4 \mathrm{~kg} starting at origin at t=0t=0 with a speed of 10 m/s10 \mathrm{~m} / \mathrm{s} in the positive xx-axis direction is subjected to a constant force F=8NF=8 N towards negative xx-axis. Calculate the position of the particle after 25 seconds
View answer and explanation
Correct option: A
−6000 m-6000 \mathrm{~m}
Option A (-6000 m) is correct because the position is calculated using kinematic equations with constant acceleration, considering the initial velocity and the constant force.
2 Hard
2 of 6
Application +4 | -1
Two guns A and B can fire bullets at speeds 1 km/s and 2 km/s, respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets on the ground fired by the two guns is
View answer and explanation
Correct option: B
0.052777778
Option B (01:16) is correct because the ratio of areas is proportional to the fourth power of the ratio of their velocities.
3 Hard
3 of 6
Application +4 | -1
The velocity of a body of mass 20 kg20\,kg decreases from 20 m/s20\,m/s to 5 m/s5\,m/s in a distance of 100   m100\,\,\,m Force on the body is
View answer and explanation
Correct option: C
−37.5 N- 37.5\,N
Option C (-37.5 N) is correct because it is the force calculated using the work-energy theorem or kinematic equations to find the acceleration and then applying Newton's second law.
4 Hard
4 of 6
Application +4 | -1
Two guns A and B can fire bullets at speeds 1 km/s and 2 km/s, respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets on the ground fired by the two guns is
View answer and explanation
Correct option: B
01:16
Option B (01:16) is correct because the ratio of areas is proportional to the fourth power of the ratio of their velocities.
5 Hard
5 of 6
Understanding +4 | -1
A metre scale is moving with uniform velocity. This implies
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Correct option: B
the force acting on the scale is zero and the torque acting about centre of mass of the scale is also zero
Option B is correct because uniform velocity implies zero net force and zero net torque acting on the meter scale.
6 Hard
6 of 6
Analyzing +4 | -1
A body of mass M is kept on a rough horizontal surface (friction coefficient μ\mu). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on the body is F, where
View answer and explanation
Correct option: C
Mg≤F≤Mg1+μ2Mg \le F \le Mg\sqrt {1 + {\mu ^2}}
Option C (Mg≤F≤Mg1+μ2Mg \le F \le Mg\sqrt {1 + {\mu ^2}}) is correct because the force by the surface ranges from the weight to the maximum force including friction.
Revision notes and key takeaways

Review LAWS OF MOTION in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 6 single-correct-answer MCQs on LAWS OF MOTION.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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