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JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Medium

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Showing 181-210 of 384 questions

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181 Medium
181 of 384
Understanding +4 | -1
If the net external force on a body is ...X..., its acceleration is zero. Acceleration can be ...Y... only, if there is a net external force on the body. Here, X and Y refer to
View answer and explanation
Correct option: B
zero, non-zero
Option B (zero, non-zero) is correct because if the net external force is zero, the acceleration is zero, and acceleration can only be non-zero if there is a net external force.
182 Medium
182 of 384
Application +4 | -1
Starting from rest, the time taken by a body sliding down on a rough inclined plane at 450{45^0} with the horizontal is twice the time taken to travel on a smooth plane of same inclination and same distance. Then the coefficient of kinetic friction is
View answer and explanation
Correct option: D
0.750.75
Option D (0.750.75) is correct because the coefficient of friction is calculated using the relationship between time taken on rough and smooth inclined planes.
183 Medium
183 of 384
Understanding +4 | -1
What is the working principle of a jet engine?
View answer and explanation
Correct option: A
Conservation of linear momentum
Option A (Conservation of linear momentum) is correct because jet engines propel themselves forward by expelling exhaust gases backward, conserving linear momentum.
184 Medium
184 of 384
Analyzing +4 | -1
Statement-I: The work done in bringing a body down from the top to the base along a frictionless incline plane is the same as the work done in bringing it down the vertical side
Statement-II: The gravitational force on the body along the inclined plane is the same as that along the vertical side.
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option B is correct. The work done is the same because gravitational force is conservative, but the gravitational force component along the inclined plane is less than the vertical force.
185 Medium
185 of 384
Remembering +4 | -1
Impulse of a force is equal to the change in-
View answer and explanation
Correct option: C
Momentum
Option C (Momentum) is correct because the impulse of a force is defined as the change in momentum.
186 Medium
186 of 384
Analyzing +4 | -1
A 60 kg man stands on a spring scale in the lift. At some instant he finds, scale reading has changed from 60 kg to 50 kg for a while and then comes back to the original mark. What should we conclude
View answer and explanation
Correct option: C
The lift while in constant motion upwards, is stopped suddenly
Option D is correct. The scale reading decreasing indicates a downward acceleration or upward deceleration, which occurs when an upward-moving lift suddenly stops.
187 Medium
187 of 384
Application +4 | -1
An open carriage in a goods train is moving with a uniform velocity of 10   ms−1\;\mathrm{m}{\mathrm{s}^{ - 1}}. If the rain adds water with zero velocity at the rate of 5 kgs−1\mathrm{kg}{\mathrm{s}^{ - 1}}, then the additional force applied by the engine to maintain the same velocity of the train is
View answer and explanation
Correct option: C
50 N
Option C (50 N) is correct because the additional force is calculated by multiplying the rate of mass addition by the velocity of the train.
188 Medium
188 of 384
Application +4 | -1
A particle of mass 10g is moving with a velocity 2i^+j^+3k^2\hat i + \hat j + 3\hat k (cm/s) Magnitude of its linear momentum is
View answer and explanation
Correct option: A
1400g cm/s\sqrt {1400} g\,cm/s
Option A (1400g cm/s\sqrt {1400} g\,cm/s) is correct because the magnitude of linear momentum is calculated by multiplying the mass by the velocity vector and finding the magnitude.
189 Medium
189 of 384
Analyzing +4 | -1
Statement-I: The velocity of a body at the bottom of an incline plane of given height is more when it slides down the plane, compared to, when it rolling down the same plane.
Statement-II: In rolling down a body acquires both, kinetic energy of translation and rotation.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option C (Statement-I is false and statement-II is true) is correct because the velocity is greater when sliding, and in rolling, energy is divided into translational and rotational.
190 Medium
190 of 384
Understanding +4 | -1
Statement-1: For a body resting on level ground normal reaction and weight form Newton's 3rd3^{\text {rd}} law action-reaction pair.
Statement-2: Action-reaction pair of Newton's 3rd3^{\text {rd}} law are equal and opposite.
View answer and explanation
Correct option: D
Statement- 1 is false, Statement-2 is true
Option D (Statement- 1 is false, Statement-2 is true) is correct because the normal reaction and weight are not action-reaction pairs, but action-reaction pairs are always equal and opposite.
191 Medium
191 of 384
Application +4 | -1
If a force of 200 N acts on a body, the momentum acquired is 150  kg  ms−1.150\,\,{\text{kg}}\,\,{\text{m}}{{\text{s}}^{ - 1}}. The period for which the force acts on the body (in sec) is
View answer and explanation
Correct option: C
0.75
Option C (0.75) is correct because it is calculated directly from the relationship between force, momentum, and time: F=dPdtF = \frac{{dP}}{{dt}}.
192 Medium
192 of 384
Understanding +4 | -1
A gun when firing bullet recoils, this can be explained by
View answer and explanation
Correct option: B
Conservation of linear momentum
Option B is correct. The recoil of a gun is a direct application of the conservation of linear momentum, where the total momentum before firing equals the total momentum after firing.
193 Medium
193 of 384
Application +4 | -1
In a TV picture tube electrons are ejected from the cathode with negligible speed and reach a velocity of 5×106 m/s5 \times 10^6 \mathrm{~m} / \mathrm{s} in travelling one centimeter. Assuming straight line motion, find the constant force exerted on the electron. The mass of the electron is 9.1×10−31 kg9.1 \times 10^{-31} \mathrm{~kg}.
View answer and explanation
Correct option: A
1.1×10−15 N1.1 \times 10^{-15} \mathrm{~N}
Option A (1.1×10−15 N1.1 \times 10^{-15} \mathrm{~N}) is correct because it is calculated using kinematic equations to find acceleration and then Newton's second law to find the force.
194 Medium
194 of 384
Understanding +4 | -1
Assertion: If there is an isolated system of particle exists, then its total momentum is conserved.
Reason: The law of conservation of momentum follows from the second and third law of motion.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
The correct answer is B (If both assertion and reason are true but reason is not the correct explanation of assertion) because both the conservation of momentum and Newton's laws are true, but conservation of momentum follows from Newton's 1st and 3rd laws.
195 Medium
195 of 384
Analyzing +4 | -1
A block is given certain upward velocity along the incline of elevation α\alpha. The time of ascent to upper point was found to be half the time of descent to initial point. The co-efficient of friction between block and incline is:
View answer and explanation
Correct option: C
0.6tan⁡α0.6 \tan \alpha
Option C is correct because the coefficient of friction between the block and incline is found to be 0.6tan⁡α0.6 \tan \alpha by analyzing the upward and downward motion with friction.
196 Medium
196 of 384
Application +4 | -1
Bullets of 0.03 kg0.03 \mathrm{~kg} mass each hit a plate at the rate of 200 bullets per second, with a velocity of 50 m/s50 \mathrm{~m} / \mathrm{s} and reflect back with a velocity of 30 ms−130 \mathrm{~ms}^{-1}. The average force acting on the plate in Newton is
View answer and explanation
Correct option: D
480
Option D (480) is correct because the average force is calculated using the change in momentum per second.
197 Medium
197 of 384
Application +4 | -1
An object at rest in space suddenly explodes into three parts of same mass. The momentum of the two parts are 2pi^ and pj^2p\hat i\,and\,p\hat j. The momentum of the third part
View answer and explanation
Correct option: B
Will have a magnitude p5p\sqrt 5
Option B (Will have a magnitude p5p\sqrt 5) is correct because the momentum of the third part must be equal and opposite to the combined momentum of the first two parts to conserve momentum.
198 Medium
198 of 384
Application +4 | -1
A block is placed at distance of 2 m from the rear on the floor of a truck (g=10 ms−2).\left( {g = 10\,m{s^{ - 2}}} \right). When the truck moves with an acceleration of 8 ms−2,8\,m{s^{ - 2}}, the block takes 2 sec to fall off from the rear of the truck. The coefficient of sliding friction between truck and the block is
View answer and explanation
Correct option: D
0.7
Option D (0.7) is correct because the coefficient of friction is calculated using the given time, distance, and acceleration of the truck.
199 Medium
199 of 384
Application +4 | -1
A truck starts from rest and has acceleration of 4 m s−24 \mathrm{~m} \mathrm{~s}^{-2}. A box is inside truck which is at 6 m6 \mathrm{~m} from open end of truck. The coefficient of friction between box and truck is 0.1.0.1. How much time box will take to slip out of truck?
View answer and explanation
Correct option: A
2 s2 \mathrm{~s}
Option A (2 s2 \mathrm{~s}) is correct because the box slips when the pseudo force exceeds the friction force, and the time is calculated using kinematics.
200 Medium
200 of 384
Application +4 | -1
If the maximum possible exhaust velocity of a rocket be 2 kms−12 \mathrm{~kms}^{-1}, calculate the ratio m0/mm_0 / m for it if it is to acquire the escape velocity of 11.2 kms−111.2 \mathrm{~kms}^{-1} after starting from rest.
View answer and explanation
Correct option: A
270.4270.4
Option A (270.4) is correct because it is the ratio of initial to final mass calculated using the Tsiolkovsky rocket equation and the given exhaust and escape velocities.
201 Medium
201 of 384
Application +4 | -1
The minimum velocity (in  ms−1)\left( {\mathrm{in\;m}{\mathrm{s}^{ - 1}}} \right) with which a car driver must traverse a flat curve of radius of 150 m and coefficient of friction 0.6 to avoid skidding is
View answer and explanation
Correct option: B
30
Option B (30) is correct because the minimum velocity to avoid skidding is calculated using the coefficient of friction and the radius of the curve, resulting in 30 m/s.
202 Medium
202 of 384
Understanding +4 | -1
A body is acted upon by balanced forces,
View answer and explanation
Correct option: A
If it is in rest only
Option D (If it is not accelerating) is correct because balanced forces imply zero net force, which means zero acceleration according to Newton's first law.
203 Medium
203 of 384
Analyzing +4 | -1
Observer O1{O_1} is in a lift going upwards and O2{O_2} is on the ground. Both apply Newton’s law, and measure normal reaction on the body
View answer and explanation
Correct option: C
Both measure different value
Option C (Both measure different value) is correct because the observer in the lift experiences a pseudo force due to the lift's acceleration, leading to a different normal reaction compared to the observer on the ground.
204 Medium
204 of 384
Understanding +4 | -1
Aeroplanes are streamlined to reduce
View answer and explanation
Correct option: A
fluid friction
Option A (fluid friction) is correct because streamlining reduces the drag force caused by air resistance, which is a form of fluid friction.
205 Medium
205 of 384
Analyzing +4 | -1
Assertion: When a person walks on a rough surface, the frictional force exerted by the surface on the person is opposite to the direction of the tendency of motion of his legs.
Reason: If a body moves with constant velocity, it implies that it is moving along a straight line and there is no acceleration.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
206 Medium
206 of 384
Remembering +4 | -1
A force produces an acceleration of 1 m/s in a body of mass 1 kg. This form is defined as?
View answer and explanation
Correct option: A
Newton
Option A (Newton) is correct because a Newton is defined as the force required to accelerate a 1 kg mass at 1 m/s².
207 Medium
207 of 384
Application +4 | -1
A body of mass mm moves along XX-axis such that its position co-ordinate at any instant tt is x=at4−bt3+ctx=at^4-bt^3+ct, where a,ba, b and cc are constants. What is the force acting on the particle at any instant tt?
View answer and explanation
Correct option: A
m(12at2−6bt)m\left(12 a t^2-6 b t\right)
Option A (m(12at2−6bt)m(12 a t^2-6 b t)) is correct because it accurately calculates the force by finding the second derivative of the position function and multiplying by the mass.
208 Medium
208 of 384
Application +4 | -1
A car of mass 800 kg moves on a circular track of radius 40 m. If the coefficient of friction is 0.5, then maximum velocity with which the car can move is
View answer and explanation
Correct option: B
14 m/s
Option B (14 m/s) is correct because it represents the maximum velocity calculated using the coefficient of friction, radius, and acceleration due to gravity.
209 Medium
209 of 384
Application +4 | -1
A woman of 50 kg50 \mathrm{~kg} mass is standing in an elevator.
Suddenly, the cable of the elevator breaks and the elevator begins to fall freely. The force exerted by the floor of the elevator on the woman is
View answer and explanation
Correct option: A
0 kgf0 \mathrm{~kg} \mathrm{f}
The correct answer is A (0 kg f) because in free fall, the woman and the elevator are accelerating at the same rate, resulting in no normal force.
210 Medium
210 of 384
Understanding +4 | -1
A block is placed on a rough horizontal floor and a horizontal force FF is applied on it. The force of friction ff by the floor on the block is measured for different values of FF and a graph is plotted between them. Then the graph will be a
View answer and explanation
Correct option: D
Straight line of slope 45∘45^{\circ} for small FF and a straight line with slope 0∘0^{\circ} for larger FF.
Option D (Straight line of slope 45∘45^{\circ} for small FF and a straight line with slope 0∘0^{\circ} for larger FF) is correct because static friction equals the applied force until it reaches its maximum value, then kinetic friction remains constant.
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