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JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Medium

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121 Medium
121 of 384
Application +4 | -1
The breaking strength of the cable used to pull a body is 40 N40 \mathrm{~N}. A body of mass 8 kg8 \mathrm{~kg} is resting on a table of coefficient of friction μ=0.2\mu=0.2 The maximum acceleration which can be peoduced by the cable connected to the body is (Take, g=10 ms−2g=10 \mathrm{~ms}^{-2})
View answer and explanation
Correct option: B
3 ms−23 \mathrm{~ms}^{-2}
Option B (3 ms−23 \mathrm{~ms}^{-2}) is correct because it accurately calculates the maximum acceleration using the breaking strength and friction.
122 Medium
122 of 384
Application +4 | -1
A stick of 1 m is moving with velocity of 2.7×108  ms−12.7 \times {10^8}\;m{s^{ - 1}}. What is the apparent length of the stick (c=3×108  ms−1)\left( {c = 3 \times {{10}^8}\;m{s^{ - 1}}} \right)
View answer and explanation
Correct option: C
0.44 m
Option C (0.44 m) is correct because it correctly applies the length contraction formula from special relativity.
123 Medium
123 of 384
Application +4 | -1
A cyclist is speeding at 20 m/s20 \mathrm{~m} / \mathrm{s} on a level road taking a level circular turn of radius 200 m200 \mathrm{~m} without reducing speed. What is minimum coefficient of static friction required between tyres and road so that cyclist take turn without slipping?
View answer and explanation
Correct option: B
0.20.2
Option B (0.2) is correct because the minimum coefficient of static friction is calculated using the formula μ=v2rg\mu = \frac{{v^2}}{{rg}}, where v is the speed, r is the radius, and g is the acceleration due to gravity.
124 Medium
124 of 384
Analyzing +4 | -1
A trolley filled with sand moves on a smooth horizontal surface with a velocity V0{V}_{{0}}. A small hole is made at the base of it from which sand is leaking out vertically down at constant rate. As the sand leaks out
a) The velocity of the trolley remains constant
b) The velocity of the trolley increases
c) The velocity of trolley decreases
d) The momentum of trolley + leaked out sand is conserved
View answer and explanation
Correct option: D
b &\& d are correct
Options B and D are correct. The velocity of the trolley increases because the mass decreases while momentum is conserved. The momentum of the trolley + leaked out sand is conserved because there is no external horizontal force.
125 Medium
125 of 384
Understanding +4 | -1
(A): A sphere cannot roll on a smooth inclined surface.
(R): For a smooth inclined surface force of friction is equal to zero.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
The correct answer is A (Both (A) and (R) are true and (R) is the correct explanation of (A)) because a sphere needs friction to roll, and a smooth surface has zero friction.
126 Medium
126 of 384
Understanding +4 | -1
A bullet hits and gets embedded in a solid block resting on a frictionless surface .In this process which one of the following is correct?
View answer and explanation
Correct option: A
Only momentum is conserved
Option A is correct because in an inelastic collision like this, momentum is conserved, but kinetic energy is not.
127 Medium
127 of 384
Understanding +4 | -1
Assertion: Static friction is a force which can be self-adjusted up to its limit μsN\mu_{{s}} {N} where μs\mu_{{s}} is the co-efficient of static friction.
Reason: The equation fs=μsNf_s=\mu_s N is applicable only when the maximum value of static friction comes into play.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B is correct because both the assertion and the reason are true, but the reason does not correctly explain the assertion.
128 Medium
128 of 384
Understanding +4 | -1
Which of the following statements is/are correct about action and reaction forces?
I. Action and reaction are simultancous forces
II. There is no cause-effect relation between action and reaction.
III. Action and reaction always on two different body
View answer and explanation
Correct option: D
I, II and III
Option D (I, II and III) is correct because all three statements accurately describe the nature of action and reaction forces.
129 Medium
129 of 384
Understanding +4 | -1
A rectangular wooden box 10 cm×20 cm×40 cm10 \mathrm{~cm} \times 20 \mathrm{~cm} \times 40 \mathrm{~cm} in size is kept on a horizontal surface with its face of largest area on the surface. A minimum force of 10 N10 \mathrm{~N} applied parallel to the surface sets the box in sliding motion along the surface. If the box is now kept with its face of smaller area in contact with the surface, the minimum force applied parallel to the surface, to set the box in motion, is
View answer and explanation
Correct option: D
equal to 10 N10 \mathrm{~N}
Option D (equal to 10 N) is correct because the force required to initiate sliding motion depends on the coefficient of static friction and the normal force, but not the area of contact.
130 Medium
130 of 384
Remembering +4 | -1
The coefficient of static friction between two surfaces depends upon
View answer and explanation
Correct option: A
the normal reaction
Option D (none of these) is correct because the coefficient of static friction depends on the nature of the two surfaces in contact and their roughness, not directly on the normal reaction, shape, or area of contact.
131 Medium
131 of 384
Application +4 | -1
A block has been placed on an inclined plane with the slope
angle θ,\theta, block slides down the plane at constant speed. The
coefficient of kinetic friction is equal to
View answer and explanation
Correct option: D
tan⁡θ\tan \theta
Option D (tan⁡θ\tan \theta) is correct because at constant speed, the friction force equals the component of weight along the incline, leading to μ=tan⁡θ\mu = \tan \theta.
132 Medium
132 of 384
Understanding +4 | -1
A sphere cannot roll without applying external force on
View answer and explanation
Correct option: B
a smooth horizontal surface
Option B (a smooth horizontal surface) is correct because a sphere requires friction to roll; without it, it can only slide.
133 Medium
133 of 384
Analyzing +4 | -1
Three concurrent co-planar forces 1 N,2 N and 3 N acting along different directions on a body
View answer and explanation
Correct option: C
Cannot keep the body in equilibrium
Option C is correct because for three concurrent coplanar forces to be in equilibrium, the vector sum of the forces must be zero, which is not possible with 1 N, 2 N, and 3 N unless they are aligned or have specific angular relationships.
134 Medium
134 of 384
Remembering +4 | -1
The two factors on which the momentum of a body depends are_____ and _____
View answer and explanation
Correct option: D
Mass, velocity
Option D (Mass, velocity) is correct because momentum is defined as the product of mass and velocity.
135 Medium
135 of 384
Application +4 | -1
1 kg body explodes into three fragments. The ratio of their masses is 1:1:31:1:3. The fragments of same mass move perpendicular to each other with speeds   30ms−1\;30\mathrm{m}{\mathrm{s}^{ - 1}}, while the heavier part remains in the initial direction. The speed of heavier part is
View answer and explanation
Correct option: B
102  ms−110\sqrt 2 \mathrm{\;m}{\mathrm{s}^{ - 1}}
Option B (102  ms−110\sqrt 2 \mathrm{\;m}{\mathrm{s}^{ - 1}}) is correct because the momentum of the heavier part is equal to the resultant of the momenta of the two lighter parts.
136 Medium
136 of 384
Understanding +4 | -1
Tension in the cable supporting an elevator, is equal to the weight of the elevator. From this, we can conclude that the elevator is going up or down with a
View answer and explanation
Correct option: A
Uniform velocity
Option A (Uniform velocity) is correct because when the tension equals the weight, the net force is zero, implying either rest or constant velocity.
137 Medium
137 of 384
Understanding +4 | -1
When the speed of a moving body is doubled
View answer and explanation
Correct option: B
Its momentum is doubled
Option B is correct because momentum is the product of mass and velocity (p=mv). If the speed is doubled, the momentum is also doubled.
138 Medium
138 of 384
Understanding +4 | -1
Statement-I: Shock absorbers reduce the magnitude of change in momentum.
Statement-II: Shock absorbers increase the time of action of impulsive force.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option C is correct because shock absorbers do not reduce the magnitude of change in momentum (Statement-I is false), but they do increase the time of action of the impulsive force (Statement-II is true).
139 Medium
139 of 384
Application +4 | -1
A block of mass m=11.7 kgm=11.7 \mathrm{~kg} is to be pushed a distance of s=4.65 ms=4.65 \mathrm{~m} along an incline and raised to a distance of h=2.86 mh=2.86 \mathrm{~m}. Assuming frictionless surface, calculate the work done in applying a force parallel to the incline to push the block up at a constant speed. (Take, g=9.8 ms−2g=9.8 \mathrm{~ms}^{-2} )
View answer and explanation
Correct option: A
328 J328 \mathrm{~J}
Option A (328 J) is correct because the work done is equal to the change in potential energy, which is mghmgh.
140 Medium
140 of 384
Understanding +4 | -1
A person is standing in an elevator. In which situation, he experiences weight loss?
View answer and explanation
Correct option: B
When the elevator moves downward with constant acceleration
Option B is correct because nuclear fusion, the joining of nuclei, releases tremendous energy, which is the source of light energy emitted by stars.
141 Medium
141 of 384
Analyzing +4 | -1
An air tight cage in which a bird is sitting is suspended from a spring balance. If the bird starts flying, then the reading of the balance will
View answer and explanation
Correct option: C
Decreases
The correct answer is Decreases because when the bird starts flying, it exerts a downward force on the air, which in turn exerts an upward force on the cage, effectively reducing the weight supported by the spring balance.
142 Medium
142 of 384
Application +4 | -1
A car is moving on a circular level road of radius of curvature 300 m. If the coefficient of friction is 0.3 and acceleration due to gravity 10  ms−210\;\mathrm{m}{\mathrm{s}^{ - 2}}, the maximum speed the car can have is (in km h−1{\mathrm{h}^{ - 1}})
View answer and explanation
Correct option: C
108
Option C (108) is correct because the maximum speed is calculated using the formula involving the coefficient of friction, radius, and gravity, then converted to km/h.
143 Medium
143 of 384
Analyzing +4 | -1
Assertion: Frictional forces are conservating forces.
Reason: Potential energy can be associated with frictional forces.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct
Assertion is incorrect, reason is correct because frictional forces are non-conservative, and potential energy cannot be uniquely associated with them.
144 Medium
144 of 384
Understanding +4 | -1
Which of the following statement/s is/are correct?

Statement I: Work done by kinetic friction in a closed path is not zero.

Statement II: Kinetic frictional force is a nonconservative force.
View answer and explanation
Correct option: A
Both I and II
Option A (Both I and II) is correct because work done by kinetic friction in a closed path is non-zero, and kinetic frictional force is a non-conservative force.
145 Medium
145 of 384
Understanding +4 | -1
The force of friction and tension in a string are derived from
View answer and explanation
Correct option: D
Electromagnetic forces
Option D (Electromagnetic forces) is correct because friction and tension arise from the electromagnetic interactions between atoms and molecules.
146 Medium
146 of 384
Application +4 | -1
Sand drops fall vertically at the rate of 2 kg/sec2 \mathrm{~kg} / \mathrm{sec} on to a conveyor belt moving horizontally with the velocity of 0.2 m/sec0.2 \mathrm{~m} / \mathrm{sec}. Then the extra force needed to keep the belt moving is
View answer and explanation
Correct option: A
0.4 Newton
The correct answer is A (0.4 Newton). The extra force needed is calculated using the formula F = v(dm/dt), where v is the velocity of the belt and dm/dt is the rate at which sand is dropped.
147 Medium
147 of 384
Understanding +4 | -1
Assertion: Static friction is self adjusting but kinetic friction is a constant force for a certain range of speed.
Reason: A body slides down an inclined plane if the angle of friction is more than the angle of the inclined plane with the horizontal.
View answer and explanation
Correct option: C
If Assertion if True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because static friction is self-adjusting, kinetic friction is constant, but the condition for sliding down a plane involves comparing the angle of repose with the inclination angle, not the angle of friction.
148 Medium
148 of 384
Application +4 | -1
Two blocks of equal mass mm are connected by an
unstretched spring and the system is kept at rest on a
frictionless horizontal surface. A constant force FF is
applied on one of the blocks pulling it away from the
other as shown in figure.
(a) Find the position of
the centre of mass at time t.t.
(b) If the extension of the spring is x0x_0
at time t,t, find the displacement of the two
blocks at this instant.
View answer and explanation
Correct option: A
(a) Ft24m;\frac{F t^2}{4 m}; (b) x1=12(Ft22m−x0),x2=12(Ft22m+x0)x_1=\frac{1}{2}\left(\frac{F t^2}{2 m}-x_0\right), x_2=\frac{1}{2}\left(\frac{F t^2}{2 m}+x_0\right)
Option A ((a) Ft24m;\frac{F t^2}{4 m}; (b) x1=12(Ft22m−x0),x2=12(Ft22m+x0)x_1=\frac{1}{2}\left(\frac{F t^2}{2 m}-x_0\right), x_2=\frac{1}{2}\left(\frac{F t^2}{2 m}+x_0\right)) is correct because it accurately calculates the center of mass position and the displacement of each block considering the spring extension.
149 Medium
149 of 384
Application +4 | -1
A body of 5 kg is moving with a velocity of 20m/s. If a force of 100N is applied on it for 10s in the same direction as its velocity, what will now be the velocity of the body
View answer and explanation
Correct option: B
220 m/s
Option B (220 m/s) is correct because the final velocity is calculated using the equation v=u+atv = u + at, where a=F/ma = F/m.
150 Medium
150 of 384
Understanding +4 | -1
Which one of the following is not a force
View answer and explanation
Correct option: A
Impulse
Option A (Impulse) is correct because impulse is the change in momentum, not a force itself, while tension, thrust, and air resistance are all forces.
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