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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 457 questions

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361 Medium
361 of 457
Application +4 | -1
If R1{R_1} and R2{R_2} are respectively the filament resistances of a 200  watt200\,\,watt bulb and 100  watt100\,\,watt bulb designed to operate on the same voltage, then
View answer and explanation
Correct option: B
R2{R_2} is two times R1{R_1}
Option B (R2{R_2} is two times R1{R_1}) is correct because power is inversely proportional to resistance when voltage is constant.
362 Medium
362 of 457
Understanding +4 | -1
In the experiment of the meter bridge if length corresponding to null deflection is xx, what would be its value if the radius of meter bridge wire is doubled?
View answer and explanation
Correct option: A
xx
Option A is correct because the null deflection point in a meter bridge depends on the ratio of resistances, not the area of the wire.
363 Medium
363 of 457
Application +4 | -1
If P=Q=R=10ΩP=Q=R=10 \Omega and S=20ΩS=20 \Omega, then what resistance should be joined with SS to balance the Wheatstone's network?
View answer and explanation
Correct option: C
Join a resistance of 20Ω20 \Omega in parallel with SS
Option B (Join a resistance of 20Ω20 \Omega in parallel with SS) is correct because it reduces the effective resistance of S to 10Ω10 \Omega, balancing the Wheatstone bridge.
364 Medium
364 of 457
Application +4 | -1
An unknown resistance R1{R_1} is connected in series with a resistance of 10  Ω\mathrm{10}\,\,\mathrm{\Omega }. This combination is connected to one gap of meter bridge while a resistance R2{R_2} is connected in the other gap. The balance point is at 50  cm\mathrm{50}\,\,\mathrm{cm}, Now, when the 10  Ω\mathrm{10}\,\,\mathrm{\Omega } resistance is removed the balance point shifts 40  cm\mathrm{40}\,\,\mathrm{cm}. The value of R1{R_1} (in ohm) is
View answer and explanation
Correct option: A
20\begin{array}{llllllllllllllllllll} {\mathrm{20}} \end{array}
Option A (20) is correct because it is derived from the meter bridge balance condition equations.
365 Medium
365 of 457
Application +4 | -1
5  ampere5\,\,ampere of current is passed through a metallic conductor. The charge flowing in one minute in coulomb will be
View answer and explanation
Correct option: D
300
Option B (271.44) is correct because it is calculated using Kohlrausch's law of independent migration of ions for equivalent conductivities.
366 Medium
366 of 457
Application +4 | -1
The resistance of hot tungsten filament is about 10  times\mathrm{10}\,\,\mathrm{times} the cold resistance. What will be the resistance of 100  W\mathrm{100}\,\,\mathrm{W} and 200  V\mathrm{200}\,\,\mathrm{V}  lamp, when not in use?
View answer and explanation
Correct option: A
40  Ω40\,\,\mathrm{\Omega }
Option A (40  Ω40\,\,\mathrm{\Omega }) is correct because the cold resistance is calculated by dividing the hot resistance by 10, and the hot resistance is found using the power and voltage ratings.
367 Medium
367 of 457
Analyzing +4 | -1
Statement-I: Two identical bulbs when connected in parallel across a battery consume a total power 'PP'. When they are connected across the same in series total power consumed is P4\frac{P}{4}.
Statement-II: In parallel P=P1+P2P=P_1+P_2 and in series P=P1P2P1+P2P=\frac{P_1 P_2}{P_1+P_2}
View answer and explanation
Correct option: A
Statement-I and Statement-II are true and Statement-II is the correct explanation of Statement-I
Option A is correct because both statements are true, and Statement-II correctly explains why the total power consumed changes when identical bulbs are connected in parallel versus in series.
368 Medium
368 of 457
Understanding +4 | -1
Assertion: In our houses when we start switching on different light buttons, main current goes on increasing.

Reason: Different connections in houses are in parallel. When we start switching on different light buttons, then net resistance of the circuit decreases. Therefore, main current increases.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is the correct explanation of Assertion.
Option A (If both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because parallel connections decrease net resistance, increasing current.
369 Medium
369 of 457
Understanding +4 | -1
The average drift speed of conduction electrons in copper wire of density n{n} cross sectional area, A carrying a current II is
View answer and explanation
Correct option: A
IneA\frac{{I}}{{neA}}
Option A is correct because the drift speed is given by the formula vd=IneAv_d = \frac{{I}}{{neA}}, where I is current, n is the number density of electrons, e is the electron charge, and A is the cross-sectional area.
370 Medium
370 of 457
Understanding +4 | -1
Which of the following operations will not increase the sensitivity of a potentiometer?
View answer and explanation
Correct option: C
Increasing the current through the potentiometer
Option C (Increasing the current through the potentiometer) is correct because increasing the current increases the potential gradient, thus decreasing the sensitivity of the potentiometer.
371 Medium
371 of 457
Application +4 | -1
A thick wire is stretched, so that its length become two times. Assuming that there is no change in its density, then what is the ratio of change in resistance of wire to the initial resistance of wire?
View answer and explanation
Correct option: C
3:1\begin{array}{llllllllllllllllllll} {\mathrm{3 : 1}} \end{array}
Option C (3 : 1) is correct because when the length doubles, the resistance increases by a factor of 4, resulting in a change of 3 times the original resistance.
372 Medium
372 of 457
Application +4 | -1
Two cells A  and  BA\,\,and\,\,B are connected in the secondary circuit of a potentiometer one at a time and the balancing length are respectively 400cm and 440cm\mathrm{400 cm }\,\mathrm{and}\,\mathrm{ 440 cm}. The emf of the cell AA is 1.08  V\mathrm{1}\mathrm{.08}\,\,\mathrm{V}. The emf of the second cell BB is volt is
View answer and explanation
Correct option: B
1.188
Option B (1.188) is correct because the emf of cell B is calculated using the potentiometer principle, where the ratio of emfs is equal to the ratio of balancing lengths.
373 Medium
373 of 457
Understanding +4 | -1
Electroplating does not help in
View answer and explanation
Correct option: C
Metals to become hard
Option C (Metals to become hard) is correct because electroplating is a surface coating process and does not significantly alter the bulk hardness of the metal.
374 Medium
374 of 457
Application +4 | -1
When an unknown resistance and a resistance 6 Ω6 \,{\Omega} are connected in the left and right gaps of a meter bridge, the balance point is obtained at 50 cm50 {~cm}. If 3 Ω3\, \Omega resistance is connected in parallel to resistance in right gap, the balance point is
View answer and explanation
Correct option: B
Increases by 25 cm25 {~cm}
Option B (Increases by 25 cm25 {~cm}) is correct because the balance point shifts due to the change in the resistance ratio after connecting the parallel resistance.
375 Medium
375 of 457
Application +4 | -1
When 1 A\mathrm{1 }\,\mathrm{A} current flows for 1  min\mathrm{1}\,\,\mathrm{min} through a silver voltmeter, it deposits 0.067  g\mathrm{0}\mathrm{.067}\,\,\mathrm{g} of silver on the cathode, then how much charge will flow to deposit 108  g\mathrm{108}\,\,\mathrm{g} of silver?
View answer and explanation
Correct option: B
9.67  ×  104  C g eq−19.67\,\, \times \,\,{10^4}\,\,\mathrm{C}\,\mathrm{g}_{\,\mathrm{eq}}^{ - 1}
Option B (9.67×104 C g eq−19.67 \times {10^4}\mathrm{~C}\mathrm{~g}_{\mathrm{~eq}}^{ - 1}) is correct because it is calculated using Faraday's law of electrolysis and the given mass of silver deposited.
376 Medium
376 of 457
Remembering +4 | -1
Peltier coefficient for the junction of a pair of metals is proportional to
View answer and explanation
Correct option: A
Absolute temperature of junction TT
Option A (Absolute temperature of junction TT) is correct because the Peltier coefficient is directly proportional to the absolute temperature of the junction.
377 Medium
377 of 457
Understanding +4 | -1
For which of the following dependence of drift velocity vd\mathrm{v_d} on electric field E\mathrm{E}, is Ohm's law obeyed?
View answer and explanation
Correct option: D
vd=E\mathrm{v_d=E}
Option D is correct because Ohm's law implies a linear relationship between drift velocity and electric field, represented by vd=E\mathrm{v_d=E}.
378 Medium
378 of 457
Understanding +4 | -1
Assertion: Total current entering a circuit is equal to that leaving it by Kirchhoff's law.
Reason: It is based on conservation of energy.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because Kirchhoff's current law is based on the conservation of charge, not energy.
379 Medium
379 of 457
Remembering +4 | -1
When a current of 1  ampere\mathrm{1}\,\,\mathrm{ampere} is passed through a conductor whose ends are maintained at temperature difference of 1  0C1\,{\,^0}\mathrm{C}, the amount of heat evolved or absorbed is called
View answer and explanation
Correct option: B
Thomson coefficient
Option B (Thomson coefficient) is correct because the Thomson coefficient describes the heat evolved or absorbed when a current passes through a conductor with a temperature gradient.
380 Medium
380 of 457
Application +4 | -1
A fuse wire of circuit cross-section and having diameter of 0.4  mm\mathrm{0}\mathrm{.4}\,\,\mathrm{mm}, allows 3  A\mathrm{3}\,\,\mathrm{A} of current to pass through it. But if another fuse wire of same material and circular cross-section and having diameter of 0.6  mm\mathrm{0}\mathrm{.6}\,\,\mathrm{mm} is taken, then the amount of current passed through the fuse is
View answer and explanation
Correct option: C
3×(  32)3/2  A3 \times {\left( {\;\frac{3}{2}} \right)^{3/2}}\;\mathrm{A}
Option C (3×(  32)3/2  A3 \times {\left( {\;\frac{3}{2}} \right)^{3/2}}\;\mathrm{A}) is correct because the current carrying capacity of a fuse wire is proportional to the 3/2 power of its radius.
381 Medium
381 of 457
Remembering +4 | -1
In a thermocouple, the temperature that does not depend on the temperature of the cold junction is called
View answer and explanation
Correct option: A
Neutral temperature
Option A (Neutral temperature) is correct because the neutral temperature in a thermocouple is independent of the cold junction temperature.
382 Medium
382 of 457
Application +4 | -1
According to Joule’s law, if the potential difference across a conductor having a material of specific resistance remains constant, then the heat produced in the conductor is directly proportional to
View answer and explanation
Correct option: D
1ρ\frac{1}{\rho }
Option D (1ρ\frac{1}{\rho }) is correct because, according to Joule's law, heat produced is inversely proportional to the specific resistance when the potential difference is constant.
383 Medium
383 of 457
Remembering +4 | -1
The thermocouple among the following that can produce maximum thermo-emf for the same temperature difference between the junction is
View answer and explanation
Correct option: C
Sb − Bi\begin{array}{llllllllllllllllllll} {\mathrm{Sb}\,\mathrm{ - }\,\mathrm{Bi}} \end{array}
Option C (Sb - Bi) is correct because the greater the separation of metals in the thermoelectric series, the greater the thermo-emf generated.
384 Medium
384 of 457
Understanding +4 | -1
If an electric current is passed through a nerve of a man, then man
View answer and explanation
Correct option: C
Is excited
Option C is correct because passing an electric current through a nerve stimulates it, leading to excitation.
385 Medium
385 of 457
Understanding +4 | -1
Which of the following statements is false?
View answer and explanation
Correct option: A
In a balanced Wheatstone bridge, if the cell and the galvanometer are exchanged, the null point is disturbed
Option A (In a balanced Wheatstone bridge, if the cell and the galvanometer are exchanged, the null point is disturbed) is correct because exchanging the cell and galvanometer in a balanced Wheatstone bridge does not disturb the null point.
386 Medium
386 of 457
Application +4 | -1
The electron in a hydrogen atom circles around the proton in 1.5941  ×  10−181.5941\,\, \times \,\,{10^{ - 18}}. The equivalent current due to motion of the electrons is
View answer and explanation
Correct option: C
100.37  mA\begin{array}{llllllllllllllllllll} {\mathrm{100}\mathrm{.37}\,\,\mathrm{mA}} \end{array}
Option C (100.37 mA) is correct because the equivalent current is calculated by dividing the electron charge by the time period.
387 Medium
387 of 457
Understanding +4 | -1
Ohm′sOhm's law is true
View answer and explanation
Correct option: A
For metallic conductors at low temperature
Option A is correct because Ohm's law is most accurate for metallic conductors at low temperatures, where the resistance is more stable.
388 Medium
388 of 457
Remembering +4 | -1
For a given thermocouple neutral temperature
View answer and explanation
Correct option: A
Is a constant
Option A (Is a constant) is correct because the neutral temperature of a given thermocouple is a characteristic property and remains constant.
389 Medium
389 of 457
Remembering +4 | -1
Watt−hourWatt - hour meter measures
View answer and explanation
Correct option: A
Electric energy
Option A (Electric energy) is correct because a watt-hour meter is specifically designed to measure the amount of electrical energy consumed over time.
390 Medium
390 of 457
Understanding +4 | -1
In "AlAl" and "SiSi". If temperature is changed from normal temperature to 70 K70 \mathrm{~K} then
View answer and explanation
Correct option: B
The resistance of Al{Al} will decrease and that of Si{Si} will increase
Option A (The resistance of Al will decrease and that of Si will increase) is correct because the resistance of a metal (Al) decreases with decreasing temperature, while the resistance of a semiconductor (Si) increases with decreasing temperature.
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