A dry cell of emf ${\rm{1}}{\rm{.5 }}\,\,{\rm{V}}$ and internal resistance ${\rm{0}}{\rm{.10}}\,\,{\rm{\Omega }}$ is connected across a resistor in series with a very low resistance ammeter. When the circuit is switched on, the ammeter reading settles to a steady rate of ${\rm{2}}\,{\rm{A}}$. Find $\left( {\rm{i}} \right)$ chemical energy consumption of the cell $\left( {\rm{ii}} \right)$ energy dissipation inside the cell $\left( {\rm{iii}} \right)$ energy dissipation inside the resistor $\left( {\rm{iv}} \right)$power output of source is

$\begin{array}{*{20}{l}} {\left( {\rm{i}} \right){\rm{ 3 W }}\left( {{\rm{ii}}} \right){\rm{ 0}}{\rm{.4 W }}\left( {{\rm{iii}}} \right){\rm{ 2}}{\rm{.6 W\;}}\left( {{\rm{iv}}} \right){\rm{ 2}}{\rm{.6 W}}} \end{array}$

$\begin{array}{*{20}{l}} {\left( {\rm{i}} \right){\rm{ 0}}{\rm{.4 W }}\left( {{\rm{ii}}} \right){\rm{ 3 W }}\left( {{\rm{iii}}} \right){\rm{ 2}}{\rm{.6 W\;}}\left( {{\rm{iv}}} \right){\rm{ 2}}{\rm{.6 W}}} \end{array}$

$\begin{array}{*{20}{l}} {\left( {\rm{i}} \right){\rm{ 2}}{\rm{.6 W }}\left( {{\rm{ii}}} \right){\rm{ 0}}{\rm{.4 W }}\left( {{\rm{iii}}} \right){\rm{ 9 W\;}}\left( {{\rm{iv}}} \right){\rm{ 1 W}}} \end{array}$

Back to CURRENT ELECTRICITY

Your Progress

0 / 4 Answered

Correct

Incorrect

Accuracy

JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Hard

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →

1 Hard

1 of 4

Application +4 | -1

It takes 12 minutes to boil 1 litre of water in an electric kettle. Due to some defect it becomes necessary to remove

20 \%

turns of heating coil of the kettle. After repair, how much time will it take to boil 1 litre of water?

View answer and explanation

Correct option: A

9.6

minute

Option A (

9.6

minute) is correct because it calculates the new boiling time after reducing the heating coil turns, considering the change in resistance and heat produced.

2 Hard

2 of 4

Application +4 | -1

A dry cell of emf

\mathrm{1}\mathrm{.5 }\,\,\mathrm{V}

and internal resistance

\mathrm{0}\mathrm{.10}\,\,\mathrm{\Omega }

is connected across a resistor in series with a very low resistance ammeter. When the circuit is switched on, the ammeter reading settles to a steady rate of

\mathrm{2}\,\mathrm{A}

. Find

\left( \mathrm{i} \right)

chemical energy consumption of the cell

\left( \mathrm{ii} \right)

energy dissipation inside the cell

\left( \mathrm{iii} \right)

energy dissipation inside the resistor

\left( \mathrm{iv} \right)

power output of source is

View answer and explanation

Correct option: A

\begin{array}{llllllllllllllllllll} {\left( \mathrm{i} \right)\mathrm{ 3 W }\left( {\mathrm{ii}} \right)\mathrm{ 0}\mathrm{.4 W }\left( {\mathrm{iii}} \right)\mathrm{ 2}\mathrm{.6 W\;}\left( {\mathrm{iv}} \right)\mathrm{ 2}\mathrm{.6 W}} \end{array}

Option A is correct. It correctly calculates the chemical energy consumption, energy dissipation inside the cell and resistor, and power output of the source.

3 Hard

3 of 4

Application +4 | -1

A resistor develops 500 J of thermal energy in 20 S, when a current of 1.5A is passed through it. If the current is increased from 1.5A to 3A, what will be the energy developed in 20S?

View answer and explanation

Correct option: D

2000 J

Option D (2000 J) is correct because the energy developed is proportional to the square of the current.

4 Hard

4 of 4

Analyzing +4 | -1

Statement-1: If the radius of copper wire carrying a current is doubled, then the drift velocity of the electrons will become one fourth.
Statement-2: Drift velocity will change according to the relation,

I=n e A v_{{d}}

View answer and explanation

Correct option: A

Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1

Statement-1 is true and Statement-2 is true, and Statement-2 is the correct explanation for Statement-1 because drift velocity is inversely proportional to the area, hence proportional to the square of the radius.

Revision notes and key takeaways

Review CURRENT ELECTRICITY in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 4 single-correct-answer MCQs on CURRENT ELECTRICITY.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

Continue Your Practice

📚 Switch Set (HARD)

Chapter Sets

ALL 475 MCQs EASY 14 MCQs HARD 4 MCQs MEDIUM 457 MCQs

0 /4

0✓ 0✗

0% Accuracy