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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 391-420 of 457 questions

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391 Medium
391 of 457
Application +4 | -1
An immersion heater with electrical resistance 7  Ω7\,\,\mathrm{\Omega } is immersed in 0.1  kg\mathrm{0}\mathrm{.1}\,\,\mathrm{kg} of water at 20  0C20\,{\,^0}\mathrm{C} for 3  min\mathrm{3}\,\,\mathrm{min}. If the flow of current is 4  A\mathrm{4}\,\,\mathrm{A}, what is the final temperature of the water in ideal conditions? (Specificheat capacity of water=4.2  × 103  Jkg)−1K−1{\left( {\mathrm{Specific heat }\,\mathrm{capacity}\,\mathrm{ of }\,\mathrm{water} = 4.2\,\, \times \,{{10}^3}\,\,\mathrm{Jkg}} \right)^{ - 1}}{\mathrm{K}^{ - 1}}
View answer and explanation
Correct option: D
68  0C68\,{\,^0}\mathrm{C}
Option D (68 0C68\,^0\mathrm{C}) is correct because it is calculated by equating the heat generated by the immersion heater to the heat gained by the water.
392 Medium
392 of 457
Application +4 | -1
In a meter bridge, null point is 20 cm20 \mathrm{~cm}. When the known resistance R\mathrm{R} is shunted by 10Ω10 \Omega resistance, null point is found to be shifted by 10 cm10 \mathrm{~cm}. The value of unknown resistance X\mathrm{X} is.
View answer and explanation
Correct option: C
50Ω50 \Omega
Option C (50Ω50 \Omega) is correct because it uses the meter bridge principle and the shift in null point to determine the unknown resistance.
393 Medium
393 of 457
Remembering +4 | -1
When a current passes through the junction of two different metals, evolution or absorption of heat at the junction is known as
View answer and explanation
Correct option: C
Peltier effect
Option C (Peltier effect) is correct because the Peltier effect describes the phenomenon of heat absorption or evolution at the junction of two dissimilar metals when an electric current passes through it.
394 Medium
394 of 457
Application +4 | -1
One junction of thermocouple is at 0  0C0\,{\,^0}\mathrm{C} and the other is at T  0CT\,{\,^0}\mathrm{C}. The thermo emf (in volts) is given by E=20  ×  10−6  T−0.02  ×  10−6  T2E = 20\,\, \times \,\,{10^{ - 6}}\,\,T - 0.02\,\, \times \,\,{10^{ - 6}}\,\,{T^2} The maximum value of EE is
View answer and explanation
Correct option: A
5  mV\begin{array}{llllllllllllllllllll} {\mathrm{5}\,\,\mathrm{mV}} \end{array}
Option A (5 mV) is correct because the maximum thermo emf is found by differentiating the given equation and setting it to zero.
395 Medium
395 of 457
Application +4 | -1
A capacitor of capacity CC is charged to a potential difference VV and another capacitor of capacity 2C2 \mathrm{C} is charged to a potential difference 4 V4 \mathrm{~V}. The charging batteries are disconnected and the two capacitors are connected with reverse polarity (i.e. positive plate of first capacitor is connected to negative plate of second capacitor). The heat produced during the redistribution of charge between the capacitors will be
View answer and explanation
Correct option: D
25CV23\frac{25 C V^2}{3}
Option D (25CV23\frac{{25 C V^2}}{{3}}) is correct because it represents the heat produced during charge redistribution, calculated using the difference in initial and final energies.
396 Medium
396 of 457
Understanding +4 | -1
For comparing the e.m.f.'s of two cells with a potentiometer, a standard cell is used to develop a potential gradient along the wires. Which of the following possibilities would make the experiment unsuccessful
View answer and explanation
Correct option: D
The e.m.f. of the standard cell is smaller than the e.m.f.'s of the two cells
Option D (The e.m.f. of the standard cell is smaller than the e.m.f.'s of the two cells) is correct because the potentiometer requires the standard cell to have a higher EMF than the cells being compared to establish a potential gradient.
397 Medium
397 of 457
Application +4 | -1
If in a voltaic cell, 5  g\mathrm{5}\,\,\mathrm{g} of zinc is consumed, we will get how many ampere hour (given that ECE\mathrm{ECE} of zinc is 3.38  ×  10−7  kgC−13.38\,\, \times \,\,{10^{ - 7}}\,\,\mathrm{kg}{\mathrm{C}^{ - 1}})
View answer and explanation
Correct option: C
4.1
Option C (4.1) is correct because it is calculated by using the formula It=mzIt = \frac{m}{z} and converting the result to ampere-hours.
398 Medium
398 of 457
Application +4 | -1
Three unequal resistors in parallel are equivalent to a resistance 1  Ω1\,\,\mathrm{\Omega }. If two of them are in the ratio 1:2\mathrm{1:2} and if no resistance value is fractional, the largest of the three resistance in ohm is
View answer and explanation
Correct option: B
6
Option B (8) is correct because it is the original resistance calculated using Ohm's law and the given current changes.
399 Medium
399 of 457
Application +4 | -1
Under what condition will the strength of current in a wire of resistance RR be the same for connection is n series or in parallel of nn identical cells each of the internal resistance rr, when
View answer and explanation
Correct option: C
R=rR = r
Option C (R=rR = r) is correct because the current is the same in both series and parallel configurations only when the external resistance equals the internal resistance.
400 Medium
400 of 457
Understanding +4 | -1
A current passes through a wire of unequal cross-sectional area. The one that does not depend on cross- section among the following is
View answer and explanation
Correct option: A
Free electron density
Option A (Free electron density) is correct because free electron density depends on the material and is independent of the cross-sectional area of the wire.
401 Medium
401 of 457
Remembering +4 | -1
As the temperature rises the resistance offered by metals
View answer and explanation
Correct option: A
increases
Option A (Increases) is correct because the resistance offered by a metal generally increases with increasing temperature due to increased atomic vibrations.
402 Medium
402 of 457
Application +4 | -1
Two identical cells send the same current in 3  Ω3\,\,\Omegaresistance, whether connected in series or in parallel. The internal resistance on the cell should be
View answer and explanation
Correct option: B
3  Ω3\,\,\Omega
Option B (3 Ω3\,\Omega) is correct because the internal resistance equals the external resistance when the current is the same in series and parallel combinations.
403 Medium
403 of 457
Application +4 | -1
What is the volume of hydrogen liberated at NTP\mathrm{NTP} by the amount of charge which liberates 0.3175 g\mathrm{0}\mathrm{.3175}\,\mathrm{ g} of copper?
View answer and explanation
Correct option: B
112 cc\begin{array}{llllllllllllllllllll} {\mathrm{112 }\,\mathrm{cc}} \end{array}
Option B (112 cc) is correct because it is the volume of hydrogen liberated at NTP, calculated using Faraday's laws of electrolysis and the equivalent weights of hydrogen and copper.
404 Medium
404 of 457
Remembering +4 | -1
The commercial unit of electrical energy is kilowatt-hour (kWh), which is equal to
View answer and explanation
Correct option: A
3.6×106 J3.6 \times 10^6 {~J}
Option A (3.6×106 J3.6 \times 10^6 {~J}) is correct because 1 kilowatt-hour is equal to 3.6 million joules.
405 Medium
405 of 457
Understanding +4 | -1
Which one of the following devices is nonohmic?
View answer and explanation
Correct option: C
Semi conductor diode
Option C (Semi conductor diode) is correct because a semiconductor diode's current-voltage relationship is non-linear, thus it doesn't obey Ohm's law.
406 Medium
406 of 457
Application +4 | -1
Two identical heaters of 220  V,1000W\mathrm{220}\,\,\mathrm{V , 1000 W} are placed in parallel with each other across 220  V\mathrm{220}\,\,\mathrm{V} line, then the combined power is
View answer and explanation
Correct option: B
2000  W\begin{array}{llllllllllllllllllll} {\mathrm{2000}\,\,\mathrm{W}} \end{array}
Option B (2000 W) is correct because the total power in a parallel circuit is the sum of individual powers.
407 Medium
407 of 457
Understanding +4 | -1
In comparing e.m.f. of two cells with the help of a potentiometer,if the balance point is to be shifted to a longer length of the wire, then this can be done by
View answer and explanation
Correct option: D
Decreasing the current from the main circuit
Option D (Decreasing the current from the main circuit) is correct because decreasing the main circuit current reduces the potential gradient, requiring a longer length for the same potential difference.
408 Medium
408 of 457
Application +4 | -1
If one cell is connected wrongly in a series combination of four cells each of e.m.f 1.5 V1.5 {~V} and internal resistance of 0.5Ω0.5 \Omega, then the equivalent internal resistance of the combination is
View answer and explanation
Correct option: D
2Ω2 \Omega
Option D (2Ω2 \Omega) is correct because when one cell is wrongly connected, its emf opposes the others, but the internal resistances always add in series.
409 Medium
409 of 457
Understanding +4 | -1
Which of the following are true, when the cells are connected in series?
View answer and explanation
Correct option: D
The emf increases
Option D (The emf increases) is correct because when cells are connected in series, their emfs add up, resulting in an increased total emf.
410 Medium
410 of 457
Analyzing +4 | -1
Assertion: When a straight wire is bent to form L-shape, its resistance increases.
Reason: Electrons take longer time to travel along bent-wire as compared to travel along a straight wire.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D (If both Assertion & Reason are False) is correct because bending a wire doesn't necessarily increase resistance, and electron travel time isn't the primary factor.
411 Medium
411 of 457
Understanding +4 | -1
Kirchhoff's junction rule is a reflection of :
View answer and explanation
Correct option: C
Conservation of charges
Option C (Conservation of charges) is correct because Kirchhoff's junction rule is based on the principle of charge conservation.
412 Medium
412 of 457
Understanding +4 | -1
In parallel combination of nn cells, we obtain
View answer and explanation
Correct option: B
more current
Option B (more current) is correct because parallel cells reduce internal resistance, increasing current output.
413 Medium
413 of 457
Understanding +4 | -1
Statement-I: In a balanced Wheatstone bridge if cell and galvanometer arms are interchanged, reading of the galvanometer remains unchanged.
Statement-II: For a balanced Wheatstone bridge, current detected by galvanometer is zero.
View answer and explanation
Correct option: A
Statement-I is True, Statement-II is True
Option A (Statement-I is True, Statement-II is True) is correct because interchanging the cell and galvanometer in a balanced Wheatstone bridge does not affect the balance condition, and the galvanometer reads zero current in a balanced bridge.
414 Medium
414 of 457
Application +4 | -1
In meter bridge arrangement, resistances xx and yy are used in 2 gaps of bridge. Null point is at distance of 25 cm25 \mathrm{~cm} from one of the end wire (y>x)(y>x). If resistance of 2x2 x is used instead of xx then calculate distance of null point from same end of wire.
View answer and explanation
Correct option: A
40 cm40 \mathrm{~cm}
Option A (40 cm40 \mathrm{~cm}) is correct because it is calculated by using the meter bridge principle and solving the equations for the two cases.
415 Medium
415 of 457
Understanding +4 | -1
The electrical conductivity of a metal is
View answer and explanation
Correct option: A
directly proportional to the mean free path
Option A (directly proportional to the mean free path) is correct because the electrical conductivity of a metal is directly proportional to the mean free path of the electrons.
416 Medium
416 of 457
Understanding +4 | -1
A student has 10  resistors\mathrm{10}\,\,\mathrm{resistors} of resistance ′r′'r'. The minimum resistance made by him from given resistors is
View answer and explanation
Correct option: B
r10\frac{r}{{10}}
Option B (r10\frac{r}{{10}}) is correct because the minimum resistance is achieved by connecting all resistors in parallel.
417 Medium
417 of 457
Application +4 | -1
Four wires made of same material have different lengths and radii. The wire having more resistance in the following case is
View answer and explanation
Correct option: C
l=100cm,r=12mml = 100cm,r = \frac{1}{2}mm
Option C (l=100cm,r=12mml = 100cm,r = \frac{1}{2}mm) is correct because resistance is directly proportional to length and inversely proportional to the square of the radius.
418 Medium
418 of 457
Understanding +4 | -1
Assertion: Conductivity of a metals is much higher than that of an electrolyte at room temperature.
Reason: Free electron density in metals is much larger than the density of ions in electrolytes and also free electrons have greater mobility than ions.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because metals have higher conductivity due to greater free electron density and mobility compared to electrolytes.
419 Medium
419 of 457
Remembering +4 | -1
To deposit one gm equivalent of an element at an electrode, the quantity of electricity needed is
View answer and explanation
Correct option: D
96500  coulombs96500\,\,coulombs
Option D (96500  coulombs96500\,\,coulombs) is correct because Faraday's constant (approximately 96500 coulombs) is the charge required to deposit one gram equivalent of an element.
420 Medium
420 of 457
Understanding +4 | -1
For mobile charge carries of mass mm, the mobility is :
View answer and explanation
Correct option: C
Inversely proportional to m{m}
Option C (Inversely proportional to m{m}) is correct because mobility is defined as drift velocity per unit electric field, and drift velocity is inversely proportional to mass.
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