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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1
The resistance of the tungsten wire in the light bulb, which is 120 V/75 W120 {~V} / 75 {~W} and powered by a 120 V120 {~V} direct current supply, is
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Correct option: D
192Ω192 \Omega
Option D (192Ω192 \Omega) is correct because it correctly calculates the resistance using the power and voltage ratings of the bulb.

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