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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 391-420 of 475 questions

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391 Medium
391 of 475
Understanding +4 | -1
Electroplating does not help in
View answer and explanation
Correct option: C
Metals to become hard
Option C (Metals to become hard) is correct because electroplating is a surface coating process and does not significantly alter the bulk hardness of the metal.
392 Medium
392 of 475
Application +4 | -1
When an unknown resistance and a resistance 6 Ω6 \,{\Omega} are connected in the left and right gaps of a meter bridge, the balance point is obtained at 50 cm50 {~cm}. If 3 Ω3\, \Omega resistance is connected in parallel to resistance in right gap, the balance point is
View answer and explanation
Correct option: B
Increases by 25 cm25 {~cm}
Option B (Increases by 25 cm25 {~cm}) is correct because the balance point shifts due to the change in the resistance ratio after connecting the parallel resistance.
393 Medium
393 of 475
Application +4 | -1
When 1 A\mathrm{1 }\,\mathrm{A} current flows for 1  min\mathrm{1}\,\,\mathrm{min} through a silver voltmeter, it deposits 0.067  g\mathrm{0}\mathrm{.067}\,\,\mathrm{g} of silver on the cathode, then how much charge will flow to deposit 108  g\mathrm{108}\,\,\mathrm{g} of silver?
View answer and explanation
Correct option: B
9.67  ×  104  C g eq−19.67\,\, \times \,\,{10^4}\,\,\mathrm{C}\,\mathrm{g}_{\,\mathrm{eq}}^{ - 1}
Option B (9.67×104 C g eq−19.67 \times {10^4}\mathrm{~C}\mathrm{~g}_{\mathrm{~eq}}^{ - 1}) is correct because it is calculated using Faraday's law of electrolysis and the given mass of silver deposited.
394 Medium
394 of 475
Remembering +4 | -1
Peltier coefficient for the junction of a pair of metals is proportional to
View answer and explanation
Correct option: A
Absolute temperature of junction TT
Option A (Absolute temperature of junction TT) is correct because the Peltier coefficient is directly proportional to the absolute temperature of the junction.
395 Medium
395 of 475
Understanding +4 | -1
For which of the following dependence of drift velocity vd\mathrm{v_d} on electric field E\mathrm{E}, is Ohm's law obeyed?
View answer and explanation
Correct option: D
vd=E\mathrm{v_d=E}
Option D is correct because Ohm's law implies a linear relationship between drift velocity and electric field, represented by vd=E\mathrm{v_d=E}.
396 Medium
396 of 475
Understanding +4 | -1
Assertion: Total current entering a circuit is equal to that leaving it by Kirchhoff's law.
Reason: It is based on conservation of energy.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because Kirchhoff's current law is based on the conservation of charge, not energy.
397 Medium
397 of 475
Remembering +4 | -1
When a current of 1  ampere\mathrm{1}\,\,\mathrm{ampere} is passed through a conductor whose ends are maintained at temperature difference of 1  0C1\,{\,^0}\mathrm{C}, the amount of heat evolved or absorbed is called
View answer and explanation
Correct option: B
Thomson coefficient
Option B (Thomson coefficient) is correct because the Thomson coefficient describes the heat evolved or absorbed when a current passes through a conductor with a temperature gradient.
398 Medium
398 of 475
Application +4 | -1
A fuse wire of circuit cross-section and having diameter of 0.4  mm\mathrm{0}\mathrm{.4}\,\,\mathrm{mm}, allows 3  A\mathrm{3}\,\,\mathrm{A} of current to pass through it. But if another fuse wire of same material and circular cross-section and having diameter of 0.6  mm\mathrm{0}\mathrm{.6}\,\,\mathrm{mm} is taken, then the amount of current passed through the fuse is
View answer and explanation
Correct option: C
3×(  32)3/2  A3 \times {\left( {\;\frac{3}{2}} \right)^{3/2}}\;\mathrm{A}
Option C (3×(  32)3/2  A3 \times {\left( {\;\frac{3}{2}} \right)^{3/2}}\;\mathrm{A}) is correct because the current carrying capacity of a fuse wire is proportional to the 3/2 power of its radius.
399 Medium
399 of 475
Remembering +4 | -1
In a thermocouple, the temperature that does not depend on the temperature of the cold junction is called
View answer and explanation
Correct option: A
Neutral temperature
Option A (Neutral temperature) is correct because the neutral temperature in a thermocouple is independent of the cold junction temperature.
400 Medium
400 of 475
Application +4 | -1
According to Joule’s law, if the potential difference across a conductor having a material of specific resistance remains constant, then the heat produced in the conductor is directly proportional to
View answer and explanation
Correct option: D
1ρ\frac{1}{\rho }
Option D (1ρ\frac{1}{\rho }) is correct because, according to Joule's law, heat produced is inversely proportional to the specific resistance when the potential difference is constant.
401 Medium
401 of 475
Remembering +4 | -1
The thermocouple among the following that can produce maximum thermo-emf for the same temperature difference between the junction is
View answer and explanation
Correct option: C
Sb − Bi\begin{array}{llllllllllllllllllll} {\mathrm{Sb}\,\mathrm{ - }\,\mathrm{Bi}} \end{array}
Option C (Sb - Bi) is correct because the greater the separation of metals in the thermoelectric series, the greater the thermo-emf generated.
402 Medium
402 of 475
Understanding +4 | -1
If an electric current is passed through a nerve of a man, then man
View answer and explanation
Correct option: C
Is excited
Option C is correct because passing an electric current through a nerve stimulates it, leading to excitation.
403 Medium
403 of 475
Understanding +4 | -1
Which of the following statements is false?
View answer and explanation
Correct option: A
In a balanced Wheatstone bridge, if the cell and the galvanometer are exchanged, the null point is disturbed
Option A (In a balanced Wheatstone bridge, if the cell and the galvanometer are exchanged, the null point is disturbed) is correct because exchanging the cell and galvanometer in a balanced Wheatstone bridge does not disturb the null point.
404 Medium
404 of 475
Application +4 | -1
The electron in a hydrogen atom circles around the proton in 1.5941  ×  10−181.5941\,\, \times \,\,{10^{ - 18}}. The equivalent current due to motion of the electrons is
View answer and explanation
Correct option: C
100.37  mA\begin{array}{llllllllllllllllllll} {\mathrm{100}\mathrm{.37}\,\,\mathrm{mA}} \end{array}
Option C (100.37 mA) is correct because the equivalent current is calculated by dividing the electron charge by the time period.
405 Medium
405 of 475
Understanding +4 | -1
Ohm′sOhm's law is true
View answer and explanation
Correct option: A
For metallic conductors at low temperature
Option A is correct because Ohm's law is most accurate for metallic conductors at low temperatures, where the resistance is more stable.
406 Medium
406 of 475
Remembering +4 | -1
For a given thermocouple neutral temperature
View answer and explanation
Correct option: A
Is a constant
Option A (Is a constant) is correct because the neutral temperature of a given thermocouple is a characteristic property and remains constant.
407 Medium
407 of 475
Remembering +4 | -1
Watt−hourWatt - hour meter measures
View answer and explanation
Correct option: A
Electric energy
Option A (Electric energy) is correct because a watt-hour meter is specifically designed to measure the amount of electrical energy consumed over time.
408 Medium
408 of 475
Understanding +4 | -1
In "AlAl" and "SiSi". If temperature is changed from normal temperature to 70 K70 \mathrm{~K} then
View answer and explanation
Correct option: B
The resistance of Al{Al} will decrease and that of Si{Si} will increase
Option A (The resistance of Al will decrease and that of Si will increase) is correct because the resistance of a metal (Al) decreases with decreasing temperature, while the resistance of a semiconductor (Si) increases with decreasing temperature.
409 Medium
409 of 475
Application +4 | -1
An immersion heater with electrical resistance 7  Ω7\,\,\mathrm{\Omega } is immersed in 0.1  kg\mathrm{0}\mathrm{.1}\,\,\mathrm{kg} of water at 20  0C20\,{\,^0}\mathrm{C} for 3  min\mathrm{3}\,\,\mathrm{min}. If the flow of current is 4  A\mathrm{4}\,\,\mathrm{A}, what is the final temperature of the water in ideal conditions? (Specificheat capacity of water=4.2  × 103  Jkg)−1K−1{\left( {\mathrm{Specific heat }\,\mathrm{capacity}\,\mathrm{ of }\,\mathrm{water} = 4.2\,\, \times \,{{10}^3}\,\,\mathrm{Jkg}} \right)^{ - 1}}{\mathrm{K}^{ - 1}}
View answer and explanation
Correct option: D
68  0C68\,{\,^0}\mathrm{C}
Option D (68 0C68\,^0\mathrm{C}) is correct because it is calculated by equating the heat generated by the immersion heater to the heat gained by the water.
410 Medium
410 of 475
Application +4 | -1
In a meter bridge, null point is 20 cm20 \mathrm{~cm}. When the known resistance R\mathrm{R} is shunted by 10Ω10 \Omega resistance, null point is found to be shifted by 10 cm10 \mathrm{~cm}. The value of unknown resistance X\mathrm{X} is.
View answer and explanation
Correct option: C
50Ω50 \Omega
Option C (50Ω50 \Omega) is correct because it uses the meter bridge principle and the shift in null point to determine the unknown resistance.
411 Medium
411 of 475
Remembering +4 | -1
When a current passes through the junction of two different metals, evolution or absorption of heat at the junction is known as
View answer and explanation
Correct option: C
Peltier effect
Option C (Peltier effect) is correct because the Peltier effect describes the phenomenon of heat absorption or evolution at the junction of two dissimilar metals when an electric current passes through it.
412 Medium
412 of 475
Application +4 | -1
One junction of thermocouple is at 0  0C0\,{\,^0}\mathrm{C} and the other is at T  0CT\,{\,^0}\mathrm{C}. The thermo emf (in volts) is given by E=20  ×  10−6  T−0.02  ×  10−6  T2E = 20\,\, \times \,\,{10^{ - 6}}\,\,T - 0.02\,\, \times \,\,{10^{ - 6}}\,\,{T^2} The maximum value of EE is
View answer and explanation
Correct option: A
5  mV\begin{array}{llllllllllllllllllll} {\mathrm{5}\,\,\mathrm{mV}} \end{array}
Option A (5 mV) is correct because the maximum thermo emf is found by differentiating the given equation and setting it to zero.
413 Medium
413 of 475
Application +4 | -1
A capacitor of capacity CC is charged to a potential difference VV and another capacitor of capacity 2C2 \mathrm{C} is charged to a potential difference 4 V4 \mathrm{~V}. The charging batteries are disconnected and the two capacitors are connected with reverse polarity (i.e. positive plate of first capacitor is connected to negative plate of second capacitor). The heat produced during the redistribution of charge between the capacitors will be
View answer and explanation
Correct option: D
25CV23\frac{25 C V^2}{3}
Option D (25CV23\frac{{25 C V^2}}{{3}}) is correct because it represents the heat produced during charge redistribution, calculated using the difference in initial and final energies.
414 Medium
414 of 475
Understanding +4 | -1
For comparing the e.m.f.'s of two cells with a potentiometer, a standard cell is used to develop a potential gradient along the wires. Which of the following possibilities would make the experiment unsuccessful
View answer and explanation
Correct option: D
The e.m.f. of the standard cell is smaller than the e.m.f.'s of the two cells
Option D (The e.m.f. of the standard cell is smaller than the e.m.f.'s of the two cells) is correct because the potentiometer requires the standard cell to have a higher EMF than the cells being compared to establish a potential gradient.
415 Medium
415 of 475
Application +4 | -1
If in a voltaic cell, 5  g\mathrm{5}\,\,\mathrm{g} of zinc is consumed, we will get how many ampere hour (given that ECE\mathrm{ECE} of zinc is 3.38  ×  10−7  kgC−13.38\,\, \times \,\,{10^{ - 7}}\,\,\mathrm{kg}{\mathrm{C}^{ - 1}})
View answer and explanation
Correct option: C
4.1
Option C (4.1) is correct because it is calculated by using the formula It=mzIt = \frac{m}{z} and converting the result to ampere-hours.
416 Medium
416 of 475
Application +4 | -1
Three unequal resistors in parallel are equivalent to a resistance 1  Ω1\,\,\mathrm{\Omega }. If two of them are in the ratio 1:2\mathrm{1:2} and if no resistance value is fractional, the largest of the three resistance in ohm is
View answer and explanation
Correct option: B
6
Option B (8) is correct because it is the original resistance calculated using Ohm's law and the given current changes.
417 Medium
417 of 475
Application +4 | -1
Under what condition will the strength of current in a wire of resistance RR be the same for connection is n series or in parallel of nn identical cells each of the internal resistance rr, when
View answer and explanation
Correct option: C
R=rR = r
Option C (R=rR = r) is correct because the current is the same in both series and parallel configurations only when the external resistance equals the internal resistance.
418 Medium
418 of 475
Understanding +4 | -1
A current passes through a wire of unequal cross-sectional area. The one that does not depend on cross- section among the following is
View answer and explanation
Correct option: A
Free electron density
Option A (Free electron density) is correct because free electron density depends on the material and is independent of the cross-sectional area of the wire.
419 Medium
419 of 475
Remembering +4 | -1
As the temperature rises the resistance offered by metals
View answer and explanation
Correct option: A
increases
Option A (Increases) is correct because the resistance offered by a metal generally increases with increasing temperature due to increased atomic vibrations.
420 Medium
420 of 475
Application +4 | -1
Two identical cells send the same current in 3  Ω3\,\,\Omegaresistance, whether connected in series or in parallel. The internal resistance on the cell should be
View answer and explanation
Correct option: B
3  Ω3\,\,\Omega
Option B (3 Ω3\,\Omega) is correct because the internal resistance equals the external resistance when the current is the same in series and parallel combinations.
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