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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 475 questions

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301 Medium
301 of 475
Application +4 | -1
A capacitor of capacitance CC is charged by a battery of emf EE and internal resistance rr. A resistance 2r2 r is also connected in series with the capacitor. The amount of heat liberated inside the battery by the time capacitor is 50%50 \% charged is
View answer and explanation
Correct option: D
E2C24\frac{E^2 C}{24}
Option D (E2C24\frac{E^2 C}{24}) is correct because during charging, half the energy is lost, and the loss is distributed between the battery and the resistor.
302 Medium
302 of 475
Understanding +4 | -1
Ohm's law fails in which of the following cases

I. Potential VV depends on II non-linearly.

II. The relation between V{V} and I depends on the sign of V{V} for the same absolute value of V{V}.

III. VV depends on II linearly.
View answer and explanation
Correct option: D
I and II
Option D (I and II) is correct because Ohm's law fails when the relationship between voltage and current is non-linear or depends on the polarity of the voltage.
303 Medium
303 of 475
Analyzing +4 | -1
Assertion: As temperature of a metallic current carrying the wire is increased, its resistance increases.
Reason: Decrease in temperature results in a decrease of electric field strength, along the conductor so that the current reduces.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because the assertion is true (resistance increases with temperature for metals), but the reason is false (decrease in temperature does not directly cause a decrease in electric field strength).
304 Medium
304 of 475
Application +4 | -1
Value of I=∫01(2x+1)2dxI=\int\limits_{0}^1(2 x+1)^2 d x is
View answer and explanation
Correct option: D
133\frac{13}{3}
Option D (133\frac{13}{3}) is correct because it is the result of correctly evaluating the definite integral of the given function.
305 Medium
305 of 475
Understanding +4 | -1
The heat developed in a system is proportional to the current though it
View answer and explanation
Correct option: D
can be any the three heats mentioned above
Option D (can be any the three heats mentioned above) is correct because the heat developed can be Joule, Thomson, or Peltier heat, depending on the specific conditions.
306 Medium
306 of 475
Analyzing +4 | -1
40  W,220  V40 \,{~W}, 220 \,{~V} and 110  W,220  V110 \,{~W}, 220\, {~V} bulbs are connected in series with 440 volt440\, volt supply, then
View answer and explanation
Correct option: B
40  W40\, {~W} bulb will fuse
Option B is correct because the 40W bulb has higher resistance and thus lower current rating, causing it to fuse first when connected in series.
307 Medium
307 of 475
Remembering +4 | -1
The internal resistance of a cell is the resistance of :
View answer and explanation
Correct option: A
electrolyte used in cell
Option A (electrolyte used in cell) is correct because the internal resistance of a cell arises from the resistance offered by the electrolyte to the flow of ions.
308 Hard
308 of 475
Analyzing +4 | -1
Statement-1: If the radius of copper wire carrying a current is doubled, then the drift velocity of the electrons will become one fourth.
Statement-2: Drift velocity will change according to the relation, I=neAvdI=n e A v_{{d}}.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Statement-1 is true and Statement-2 is true, and Statement-2 is the correct explanation for Statement-1 because drift velocity is inversely proportional to the area, hence proportional to the square of the radius.
309 Medium
309 of 475
Application +4 | -1
For a certain thermocouple the emf is E=aT+  bT2\begin{array}{llllllllllllllllllll} {E = aT + \,\,b{T^2}} \end{array}, where t(in  0C)t\left( {\mathrm{in}\,{\,^0}\mathrm{C}} \right) is the temperature of hot junction, the cold junction is at 0  0C0\,{\,^0}\mathrm{C}. The value of contants a  and  ba\,\,\mathrm{and}\,\,b are 10  ×  10−610\,\, \times \,\,{10^{ - 6}} and 0.02  ×  10−60.02\,\, \times \,\,{10^{ - 6}} respectively, then the temperature of inversion (in  0C)\left( {\mathrm{in}\,{\,^0}\mathrm{C}} \right) will be
View answer and explanation
Correct option: C
500\begin{array}{llllllllllllllllllll} {\mathrm{500}} \end{array}
Option C (500) is correct because the temperature of inversion is found by setting the emf to zero and solving for the temperature.
310 Medium
310 of 475
Understanding +4 | -1
Choose the wrong statement regarding the experiment to identify a diode, an LED, a resistor and a capacitor
View answer and explanation
Correct option: C
when pointer moves in one way when voltage is applied and not when reversed, the item is a resistor
Option C (when pointer moves in one way when voltage is applied and not when reversed, the item is a resistor) is the wrong statement because a resistor allows current flow in both directions.
311 Medium
311 of 475
Application +4 | -1
In a thermo-couple, one junction which is at 0 ∘C0\,^\circ C and the othe at t  ∘Ct{\mkern 1mu} {\mkern 1mu} ^\circ C the emf is given by E=at2−bt2E = a{t^2} - b{t^2}. The neutral temperature is given by
View answer and explanation
Correct option: B
2  a/3 b2\,\,a/3\,b
Option B (2  a/3 b2\,\,a/3\,b) is correct because the neutral temperature is found by setting the derivative of the emf with respect to temperature equal to zero.
312 Medium
312 of 475
Understanding +4 | -1
Statement-1: The equivalent resistance in series combination is larger than even the largest individual resistance.
Statement-2: The equivalent resistance of the parallel combination is smaller than even the smallest resistance.
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option B (Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1) is correct because both statements are true, but they are independent facts about series and parallel resistances.
313 Medium
313 of 475
Application +4 | -1
A bulb of 220V\mathrm{220 V} and 300W\mathrm{300 W} is connected across 110V\mathrm{110 V} circuit, the percentage reduction in power is
View answer and explanation
Correct option: D
75  %\begin{array}{llllllllllllllllllll} {\mathrm{75}\,\,\mathrm{\% }} \end{array}
Option D (75 %) is correct because the power is proportional to the square of the voltage, so reducing the voltage by half reduces the power to one-fourth.
314 Medium
314 of 475
Application +4 | -1
Number of electrons flowing per second is a conductor carrying a current of 9 A9 {~A} is_____
View answer and explanation
Correct option: B
5.6×10195.6 \times 10^{19}
Option B (5.6×10195.6 \times 10^{19}) is correct because it is calculated using the formula I=ne/tI = ne/t where n is the number of electrons.
315 Medium
315 of 475
Remembering +4 | -1
In which one of the following substances the resistance decreases with increase of temperature?
View answer and explanation
Correct option: A
Carbon
Option A (Carbon) is correct because carbon is a semiconductor, and semiconductors typically exhibit a decrease in resistance with increasing temperature.
316 Medium
316 of 475
Understanding +4 | -1
Statement-I: Net power supplied by a non-ideal battery is Ei−i2r\mathrm{Ei}-\mathrm{i}^2 \mathrm{r}
Statement-II: Power consumed by internal resistance of a battery is i2r\mathrm{i}^2 \mathrm{r}.
View answer and explanation
Correct option: A
Statement-I and Statement-II are true and Statement-II is the correct explanation of Statement-I
Option A (Statement-I and Statement-II are true and Statement-II is the correct explanation of Statement-I) is correct because the net power supplied by the battery is the total power generated minus the power lost due to internal resistance.
317 Medium
317 of 475
Remembering +4 | -1
Which of the following material is the best conductor of electricity?
View answer and explanation
Correct option: D
Copper
Option D (Copper) is correct because copper has the highest electrical conductivity among the given materials.
318 Medium
318 of 475
Analyzing +4 | -1
When two resistances R1  and  R2{R_1}\,\,\mathrm{and}\,\,{R_2} are connected in series, they consume 12  W\mathrm{12}\,\,\mathrm{W} powers. When they are connected in parallel, they consume 50  W\mathrm{50}\,\,\mathrm{W} powers. What the ratio of the powers of R1  and  R2{R_1}\,\,\mathrm{and}\,\,{R_2} ?
View answer and explanation
Correct option: C
3/2\begin{array}{llllllllllllllllllll} {\mathrm{3/2}} \end{array}
Option C (3/2) is correct because the ratio of powers of the two resistors is calculated by using the series and parallel power consumption equations.
319 Medium
319 of 475
Application +4 | -1
Two identical heater filaments are connected first in parallel and then in series. At the same applied voltage, the ratio of heat produced in same time for parallel to series will be:
View answer and explanation
Correct option: B
4:14: 1
Option B (4:14: 1) is correct because the power in parallel is four times the power in series when the voltage is the same.
320 Medium
320 of 475
Understanding +4 | -1
As the temperature increases, the electrical resistance:
View answer and explanation
Correct option: D
increases for conductors but decreases for semiconductors
The correct answer is D (increases for conductors but decreases for semiconductors) because the resistance of conductors increases with temperature due to increased atomic vibrations, while the resistance of semiconductors decreases due to increased availability of charge carriers.
321 Medium
321 of 475
Application +4 | -1
In a potentiometer experiment, the balancing length with a cell is 560 cm560\,cm. When an external resistance of 10 Ω10\,\Omega is connected in parallel to the cell the balancing length changes by 60 cm60\,cm. The internal resistance of the cell in ohm is
View answer and explanation
Correct option: C
1.2
Option C (1.2) is correct because it is calculated using the formula for internal resistance in a potentiometer experiment.
322 Medium
322 of 475
Application +4 | -1
In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2  m2\,\,m when the cell is shunted by a 5  Ω5\,\,\mathrm{\Omega } resistance; and is at a length of 3  m3\,\,m when the cell is shunted by a 10  Ω10\,\,\mathrm{\Omega } resistance. The internal resistance of the cell is, then
View answer and explanation
Correct option: B
10  Ω10\,\,\mathrm{\Omega }
Option B (10Ω10 \Omega) is correct because the internal resistance is calculated using the potentiometer principle and the given shunt resistances and balancing lengths.
323 Medium
323 of 475
Analyzing +4 | -1
Assertion (A)In a meter bridge experiment, null point for an unknown resistance is put inside an enclosure maintained at a higher temperature. The null point can be obtained at the same p{p} as before by decreasing the value of the standard resistance.

Reason (R) Resistance of metal increases with increase in temperature.
View answer and explanation
Correct option: D
If both Assertion and Reason are false.
The correct answer is D because both the assertion and the reason are false. Increasing the temperature of the unknown resistance will change the null point, and the resistance of a metal increases with temperature.
324 Medium
324 of 475
Application +4 | -1
Two resistances are connected in two gaps of a meter bridge. The balance point is 20  cm\mathrm{20}\,\,\mathrm{cm} from the zero end. A resistance of 15  Ω15\,\,\mathrm{\Omega } is connected is series with the smaller of the two. The null point shifts to 40  cm\mathrm{40}\,\,\mathrm{cm}. The value of the smaller resistance in ohm\mathrm{ohm} is
View answer and explanation
Correct option: C
9
Option C (9) is correct because it is obtained by solving the equations derived from the meter bridge principle.
325 Medium
325 of 475
Analyzing +4 | -1
When two resistances R1{R_1} and R2{R_2} are connected in series and parallel with 120  V120\,\,V line power consumed will be 25  W25\,\,W and 100  W100\,\,W respectively. Then the ratio of power consumed by R1{R_1} to that consumed by R2{R_2} will be
View answer and explanation
Correct option: A
1:1\begin{array}{llllllllllllllllllll} {\mathrm{1 :1}} \end{array}
Option A (1:1) is correct because the ratio of the resistances R1 and R2 is found to be 1:1 based on the given power consumption in series and parallel combinations.
326 Medium
326 of 475
Understanding +4 | -1
Which of the following relation is wrong?
View answer and explanation
Correct option: D
1  coulomb×  1volt  =  1watt\begin{array}{llllllllllllllllllll} {\mathrm{1}\,\,\mathrm{coulomb \times }\,\,\mathrm{1 volt}\,\,\mathrm{ = }\,\,\mathrm{1 watt}} \end{array}
Option D (1\coulomb×,1volt,=,1watt\begin{array}{llllllllllllllllllll} {\mathrm{1}\coulomb \times \\,\mathrm{1 volt}\\,\mathrm{ = }\\,\mathrm{1 watt}} \end{array}) is wrong because 1 coulomb x 1 volt = 1 joule, not 1 watt.
327 Medium
327 of 475
Understanding +4 | -1
Lengths of two wires are 50 cm,100 cm50 {~cm}, 100 {~cm} respectively and their diameters are 1 mm,21 {~mm}, 2 mm{mm} then ratio between their specific resistances is
View answer and explanation
Correct option: B
1:11: 1
Option B is correct because specific resistance (resistivity) is a material property and depends only on the material, not on the length or diameter of the wire.
328 Medium
328 of 475
Application +4 | -1
In a potentiometer experiment the balancing length, with a cell is 560 cm560\,cm. When an external resistance of 10 Ω10\,\Omega is connected in parallel to the cell, the balancing length changes by 60 cm60\,cm. Find the internal resistance of the cell.
View answer and explanation
Correct option: B
1.2 Ω1.2\,\Omega
Option B (1.2 Ω1.2\,\Omega) is correct because it is calculated using the potentiometer formula for internal resistance.
329 Easy
329 of 475
Understanding +4 | -1
Statement-1: Current flows in a conductor only when there is an electric field within the conductor.
Statement-2: The drift velocity of electrons in the presence of electric field decreases.
View answer and explanation
Correct option: C
Statement-1 is true, Statement-2 is false
Option C (Statement-1 is true, Statement-2 is false) is correct because current flow requires an electric field, and the drift velocity of electrons increases with the electric field.
330 Medium
330 of 475
Understanding +4 | -1
A potential difference is applied across the ends of a metallic wire. If the potential difference is doubled, the drift velocity will
View answer and explanation
Correct option: A
Be doubled
Option A (Be doubled) is correct because drift velocity is directly proportional to the potential difference applied across the wire.
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