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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 475 questions

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271 Medium
271 of 475
Application +4 | -1
Two wires have resistances R  and  2RR\,\,\mathrm{and}\,\,2R. When both are joining in series and in parallel, then ratio of heats generated in these situations on applying the same voltage, is
View answer and explanation
Correct option: C
2:9\begin{array}{llllllllllllllllllll} {\mathrm{2 : 9}} \end{array}
Option C (2:9\mathrm{2 : 9}) is correct because it is the ratio of heat generated in series to parallel combinations when the voltage is the same.
272 Easy
272 of 475
Analyzing +4 | -1
Statement-1: If a wire is stretched to increase its length nn times then its resistance also become nn time.
Statement-2: Resistance of the wire is directly proportional to its length.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because Statement-1 is false (resistance becomes n2 times), and Statement-2 is true (resistance is directly proportional to length).
273 Medium
273 of 475
Analyzing +4 | -1
Assertion: As a direct current passes through a thick metallic conductor, it produces magnetic field only outside the rod.
Reason: Current passes only along the surface of the conductor and not through the interior.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false. Direct current flows throughout the conductor, not just on the surface, and it produces a magnetic field both inside and outside the rod.
274 Medium
274 of 475
Remembering +4 | -1
Ohm's law is applicable to :
View answer and explanation
Correct option: D
conductor
Option D (conductor) is correct because Ohm's law (V=IR) applies to conductors where the current is directly proportional to the voltage, given a constant resistance.
275 Medium
275 of 475
Understanding +4 | -1
The kirchhoff's first law (∑i=0)\left( {\sum i = 0} \right) and second law (∑  iR=0)\left( {\sum {\mkern 1mu} {\mkern 1mu} iR = 0} \right) where the symbols have their usual meanings, are respectively based on
View answer and explanation
Correct option: D
Conservation of charge, conservation of energy
Option D is correct because Kirchhoff's first law (junction rule) is based on the conservation of charge, and Kirchhoff's second law (loop rule) is based on the conservation of energy.
276 Medium
276 of 475
Remembering +4 | -1
The relation between Faraday’s constant FF, electron charge ee and avogadro number NN is
View answer and explanation
Correct option: B
F=NeF = Ne
Option B (F=NeF = Ne) is correct because Faraday's constant is defined as the product of Avogadro's number and the elementary charge.
277 Medium
277 of 475
Understanding +4 | -1
The charge given to any conductor resides on its outer surface because
View answer and explanation
Correct option: A
The free charge tends to be in its minimum potential energy state
Option A (The free charge tends to be in its minimum potential energy state) is correct because charges redistribute themselves on a conductor to minimize their potential energy, which occurs when they are on the outer surface.
278 Medium
278 of 475
Understanding +4 | -1
An electric heater kept in vacuum is heated continuously by passing electric current. Its temperature
View answer and explanation
Correct option: D
Will become constant after sometime because of loss of heat due to radiation
The correct answer is D (Will become constant after sometime because of loss of heat due to radiation) because the heater will reach thermal equilibrium with its surroundings through radiation.
279 Medium
279 of 475
Understanding +4 | -1
What determines the emf between the two metals placed in an electrolyte?
View answer and explanation
Correct option: A
Relative position of metals in the electro chemical series
Option A is correct because the electrochemical series dictates the potential difference based on the metals' relative reactivity.
280 Medium
280 of 475
Application +4 | -1
A,  B, CA,\,\,B,\,C and DD are four resistances of 2  Ω,  2  Ω,  2  Ω  and  3  Ω2\,\,\mathrm{\Omega },\,\,2\,\,\mathrm{\Omega },\,\,2\,\,\mathrm{\Omega }\,\,\mathrm{and}\,\,3\,\,\mathrm{\Omega } respectively. They are used to form a Wheatstone bridge. The resistance DD is short circuted with a resistances R\mathrm{R} in order to get the bridge balanced. The value of RR will be
View answer and explanation
Correct option: B
6  Ω6\,\,\mathrm{\Omega }
Option B (6 Ω) is correct because it satisfies the Wheatstone bridge balance condition after short-circuiting resistance D with R.
281 Medium
281 of 475
Understanding +4 | -1
For a metallic wire, the ratio of voltage to corresponding current is
View answer and explanation
Correct option: D
increases with rise in temperature
Option D (increases with rise in temperature) is correct because the resistance of a metallic wire increases with temperature.
282 Easy
282 of 475
Application +4 | -1
The emf of a battery A is balanced by a length of 80 cm on a potentiometer wire. The emf of a standard cell 1 V is balanced by 50 cm. The emf of A is
View answer and explanation
Correct option: D
1.6 V
Option D (1.6 V) is correct because the emf is directly proportional to the balancing length in a potentiometer.
283 Medium
283 of 475
Remembering +4 | -1
The resistivity of a wire depends on its
View answer and explanation
Correct option: D
Material
Option D (Material) is correct because resistivity is an intrinsic property of the material.
284 Medium
284 of 475
Application +4 | -1
If R1  and  R2{R_1}\,\,\mathrm{and}\,\,{R_2} be the resistances of the filaments of 200  W\mathrm{200}\,\,\mathrm{W} and 100  W\mathrm{100}\,\,\mathrm{W} electric bulbs operation at 220  V\mathrm{220}\,\,\mathrm{V}, then (R1R2)\left( {\frac{{{R_1}}}{{{R_2}}}} \right) is
View answer and explanation
Correct option: C
0.5\mathrm{0}\mathrm{.5}
Option C (0.5) is correct because the ratio of resistances is inversely proportional to the ratio of power, given the voltage is constant.
285 Medium
285 of 475
Application +4 | -1
If 2  A\mathrm{2}\,\,\mathrm{A} of current is passed through C u S O4\mathrm{C}\,\mathrm{u}\,\mathrm{S}\,{\mathrm{O}_4} solution for 32  s\mathrm{32}\,\,\mathrm{s}, then the number of copper ions deposited at the cathode will be
View answer and explanation
Correct option: B
2  ×  10202\,\, \times \,\,{10^{20}}
Option B (2×10202 \times 10^{20}) is correct because the number of copper ions is calculated using the formula q = it = n * 2e, where n is the number of ions.
286 Medium
286 of 475
Application +4 | -1
A conducting wire of cross-sectional area 1 cm21 \mathrm{~cm}^2 has 3×1023 m−33 \times 10^{23} \mathrm{~m}^{-3} charge carriers. If wire carries a current of 24 mA24 \mathrm{~mA}, the drift speed of the carrier is
View answer and explanation
Correct option: B
5×10−3 m/s5 \times 10^{-3} \mathrm{~m} / \mathrm{s}
Option B (5×10−3 m/s5 \times 10^{-3} \mathrm{~m} / \mathrm{s}) is correct because the drift speed is calculated using the formula vd=i/(neA)v_d = i / (n e A).
287 Medium
287 of 475
Understanding +4 | -1
On increasing the temperature of a conductor, its resistance increases because the
View answer and explanation
Correct option: D
Relaxation time decreases
Option D (Relaxation time decreases) is correct because as temperature increases, the collision frequency of electrons increases, reducing the relaxation time.
288 Medium
288 of 475
Analyzing +4 | -1
Twelve cells, each having emf E volt are connected in series and are kept in a closed box. Some of these cells are wrongly connected with positive and negative terminals reversed. This 12 cell battery is connected in series with an ammeter, an external resistance R\mathrm{R} ohm and a two-cell battery (two cells of the same type used earlier, connected perfectly in series). The current in the circuit when the 12-cell battery and 2-cell battery aid each other is 3 A3 \mathrm{~A} and is 2 A2 \mathrm{~A} when they oppose each other. Then the number of cell is 12-cell battery that are connected wrongly is:
View answer and explanation
Correct option: D
1
Option D is correct. By setting up equations for the current in both aiding and opposing configurations and solving them simultaneously, we find that one cell is connected wrongly.
289 Medium
289 of 475
Understanding +4 | -1
A small drop of water falls from rest through a large height hh in air, the final velocity is proportional to:-
View answer and explanation
Correct option: D
h∘h^\circ
h∘h^\circ is correct because after falling through a large height, the drop attains terminal velocity, which is independent of height.
290 Hard
290 of 475
Application +4 | -1
A dry cell of emf 1.5  V\mathrm{1}\mathrm{.5 }\,\,\mathrm{V} and internal resistance 0.10  Ω\mathrm{0}\mathrm{.10}\,\,\mathrm{\Omega } is connected across a resistor in series with a very low resistance ammeter. When the circuit is switched on, the ammeter reading settles to a steady rate of 2 A\mathrm{2}\,\mathrm{A}. Find (i)\left( \mathrm{i} \right) chemical energy consumption of the cell (ii)\left( \mathrm{ii} \right) energy dissipation inside the cell (iii)\left( \mathrm{iii} \right) energy dissipation inside the resistor (iv)\left( \mathrm{iv} \right)power output of source is
View answer and explanation
Correct option: A
(i)3W(ii)0.4W(iii)2.6W  (iv)2.6W\begin{array}{llllllllllllllllllll} {\left( \mathrm{i} \right)\mathrm{ 3 W }\left( {\mathrm{ii}} \right)\mathrm{ 0}\mathrm{.4 W }\left( {\mathrm{iii}} \right)\mathrm{ 2}\mathrm{.6 W\;}\left( {\mathrm{iv}} \right)\mathrm{ 2}\mathrm{.6 W}} \end{array}
Option A is correct. It correctly calculates the chemical energy consumption, energy dissipation inside the cell and resistor, and power output of the source.
291 Medium
291 of 475
Application +4 | -1
A piece of silver has a resistance of 1 Ω1 ~\Omega. What will be the resistance of a constantan wire of one-third length and one-half diameter, if the specific resistance of constantan is 30 times that of silver?
View answer and explanation
Correct option: B
40 Ω40 ~\Omega
Option B (40 Ω\Omega) is correct because it correctly uses the relationship between resistance, resistivity, length, and area to find the resistance of the constantan wire.
292 Medium
292 of 475
Understanding +4 | -1
A steady current flows in a metal wire of non-uniform cross-section. Which quantity remains constant along the length of the wire?
View answer and explanation
Correct option: D
Mobility of the free electrons
The correct answer is D (Mobility of the free electrons) because mobility depends on material properties and temperature, which are constant along the wire.
293 Medium
293 of 475
Application +4 | -1
A uniform wire of resistance RR is uniformly compressed along its length, until its radius becomes nn times the original radius. Now resistance of the wire becomes
View answer and explanation
Correct option: A
Rn4\frac{R}{{{n^4}}}
Option A (Rn4\frac{R}{{{n^4}}}) is correct because the resistance changes inversely with the fourth power of the radius when the wire is compressed.
294 Medium
294 of 475
Application +4 | -1
The number of dry cells, each of e.m.f. 1.5  volt1.5\,\,volt and internal resistance 0.5  ohm0.5\,\,ohm that must be joined in series with a resistance of 20  ohm20\,\,ohm so as to send a current of 0.6  ampere0.6\,\,ampere through the circuit is
View answer and explanation
Correct option: C
10
Option C (10) is correct because it is the number of cells required to achieve the specified current through the given resistance, calculated using Ohm's law for series circuits.
295 Medium
295 of 475
Application +4 | -1
A copper wire is stretched to make it 0.5% longer. The percentage change in its electrical resistance, if its volume remains unchanged is
View answer and explanation
Correct option: B
0.01
Option B (1.00%) is correct because the percentage change in resistance is approximately twice the percentage change in length.
296 Hard
296 of 475
Application +4 | -1
A resistor develops 500 J of thermal energy in 20 S, when a current of 1.5A is passed through it. If the current is increased from 1.5A to 3A, what will be the energy developed in 20S?
View answer and explanation
Correct option: D
2000 J
Option D (2000 J) is correct because the energy developed is proportional to the square of the current.
297 Medium
297 of 475
Remembering +4 | -1
Kirchhoff's first law (∑i=0)\left(\sum {i}=0\right) expresses the conservation of
View answer and explanation
Correct option: B
Charge
Option B (Charge) is correct because Kirchhoff's first law, also known as the junction rule, is based on the conservation of electric charge.
298 Medium
298 of 475
Understanding +4 | -1
Thermoelectric constant of a thermocouple are α\alpha and β.\beta .. Thermoelectric power at inversion temperature is
View answer and explanation
Correct option: B
−α- \alpha
Option B (−α- \alpha) is correct because at the inversion temperature, the thermoelectric power is given by the derivative of the thermoelectric EMF with respect to temperature, evaluated at the inversion temperature, which results in −α- \alpha.
299 Medium
299 of 475
Analyzing +4 | -1
Two bulbs rates (25 W−200 V)(25 {~W}-200 {~V}) and (100 W−(100 {~W}- 220 V220 {~V} ) are connected in series to a 440 V440 {~V} line. Which one is likely to fuse?
View answer and explanation
Correct option: C
25 W25 {~W} bulb
Option C (25 W25 {~W} bulb) is correct because the 25 W25 {~W} bulb has a higher resistance and will experience a larger voltage drop, making it more likely to fuse.
300 Medium
300 of 475
Application +4 | -1
Which one of the following is the resistance that must be placed parallel with 12Ω12 \Omega resistance to obtain a combined resistance of 4Ω4 \Omega ?
View answer and explanation
Correct option: C
6Ω6 \Omega
Option C (6Ω6 \Omega) is correct because it is the resistance value that, when placed in parallel with 12Ω12 \Omega, results in a combined resistance of 4Ω4 \Omega.
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