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JEE • PHYSICS • ATOMS

Atoms practice · Mixed difficulty

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Showing 181-210 of 257 questions

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181 Medium
181 of 257
Understanding +4 | -1
Consider an electron in the nth{n^{\mathrm{th}}} orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength λ\lambda of that electron as
View answer and explanation
Correct option: D
nλn\lambda
Option D (nλn\lambda) is correct because the circumference of the nth orbit is an integer multiple of the de Broglie wavelength, as per Bohr's quantization condition.
182 Medium
182 of 257
Application +4 | -1
The maximum wave length of bracket series of hydrogen atom will be [in A0{A^0} ]
View answer and explanation
Correct option: C
40477
Option C (40,477) is correct because it is the maximum wavelength calculated using the Rydberg formula for the Brackett series.
183 Medium
183 of 257
Analyzing +4 | -1
Statement I: The ionisation potential of hydrogen is found to be 13.6 eV13.6 \mathrm{~eV}, the ionisation potential of doubly ionised lithium is 122.4 eV122.4 \mathrm{~eV}.
Statement II: Energy in the nnth state of hydrogen atom is En=−13.6n2E_n=-\frac{13.6}{n^2}.
View answer and explanation
Correct option: B
Statement I is true; Statement II is true; Statement II is not the correct explanation for Statement I
Option B is correct. Statement I is true based on Bohr's theory, and Statement II correctly states the energy levels of hydrogen, but Statement II is not the direct explanation for the specific values in Statement I.
184 Medium
184 of 257
Remembering +4 | -1
To explain his theory, Bohr used
View answer and explanation
Correct option: B
Conservation of angular momentum
Option B (Conservation of angular momentum) is correct because Bohr's model quantized the angular momentum of the electron in the hydrogen atom.
185 Medium
185 of 257
Application +4 | -1
Suppose an electron is attracted towards the origin by a forcekr\frac{k}{r} where ′k′\mathrm{'k'} is a constant and ′r′\mathrm{'r'} is the distance of the electron from the origin. By applying Bohr model to this system, the radius of the nth{\mathrm{n}^{\mathrm{th}}} orbital of the electron is found to be ′rn′\mathrm{'}{\mathrm{r}_\mathrm{n}}^\prime and the kinetic energy of the electron to be ′Tn′\mathrm{'}{\mathrm{T}_\mathrm{n}}^\prime. Then which of the following is true
View answer and explanation
Correct option: A
Tn{\mathrm{T}_\mathrm{n}} independent of n,rn∝n\mathrm{n},{\mathrm{r}_\mathrm{n}} \propto \mathrm{n}
Option A (Tn{\mathrm{T}_\mathrm{n}} independent of n,rn∝n\mathrm{n},{\mathrm{r}_\mathrm{n}} \propto \mathrm{n}) is correct because the kinetic energy is independent of n and the radius is proportional to n under the given force condition.
186 Medium
186 of 257
Analyzing +4 | -1
Which of the following parameters is same for electron in all hydrogen like atoms and ions in their ground states?
View answer and explanation
Correct option: D
(Speed) (Radius)
Option D is correct. The product of speed and radius (v*r) is proportional to n, and thus remains constant for all hydrogen-like atoms in their ground state (n=1).
187 Medium
187 of 257
Remembering +4 | -1
The significant result deduced from the
Rutherford's scattering experiment is that
View answer and explanation
Correct option: A
whole of the positive charge is concentrated at
the centre of atom
Option A (whole of the positive charge is concentrated at the centre of atom) is correct because Rutherford's experiment demonstrated the existence of a small, dense, positively charged nucleus.
188 Medium
188 of 257
Analyzing +4 | -1
An X-ray tube with a copper target is found to be emitting lines other than those due to copper. The KαK_\alpha line of copper is known to have a wavelength 1.5405A∘1.5405 \mathop {\text{A}}\limits^ \circ and the other two KαK_\alpha lines observed have wavelengths 0.7090A∘0.7090 \mathop {\text{A}}\limits^ \circ and 1.6578A∘1.6578 \mathop {\text{A}}\limits^ \circ. Identify the impurities.
View answer and explanation
Correct option: C
Both (1) and (2)
Option C is correct because the impurities identified using Moseley's law are Molybdenum and Nickel, based on the given wavelengths of the emitted X-ray lines.
189 Medium
189 of 257
Analyzing +4 | -1
Assertion (A): Between any two given energy levels, the number of absorption transitions is always less than or equal to the number of emission transitions.

Reason (R): Absorption transitions start from the lowest energy level only and may end at any higher energy level. But emission trasitions may start from any higher energy level and end at an energy level below it.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because the number of absorption transitions is limited by the availability of electrons in the lowest energy level, while emission transitions can occur from multiple higher energy levels.
190 Medium
190 of 257
Application +4 | -1
The wavelength of radiation emitted is λ0{\lambda _0} when an electron jumps from the third to second orbit of hydrogen atom. For the electron jump from fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be
View answer and explanation
Correct option: B
(2027)λ0\left( {\frac{{20}}{{27}}} \right){\lambda _0}
Option B ((2027)λ0\left( {\frac{{20}}{{27}}} \right){\lambda _0}) is correct because it's the wavelength of radiation emitted when an electron jumps from the fourth to the second orbit, calculated using the Rydberg formula.
191 Medium
191 of 257
Understanding +4 | -1
Assertion: Bohr's atomic model can be applied for every atom.

Reason: The energy state of election in atom is continuous.
View answer and explanation
Correct option: D
If the assertion and reason both are false
Option D is correct because Bohr's model is only applicable to single-electron species, and the energy states of electrons in atoms are quantized, not continuous.
192 Medium
192 of 257
Understanding +4 | -1
The energy required to remove one of the electrons from a neutral helium atom is 24.6 eV. The energy required to remove both the electrons from a neutral helium atom is
View answer and explanation
Correct option: D
79 eV
Option D (79 eV) is correct because the total energy required is the sum of the energy to remove the first electron (24.6 eV) and the ionization energy of He+ (54.4 eV).
193 Medium
193 of 257
Application +4 | -1
Consider a hydrogen like atom in Bohr's model. It is given that difference between (n+1)th(n+1)^{\text {th}} Bohr's radius and nthn^{\text {th}} Bohr's radius is equal to (n−1)th(n-1)^{\text {th}} Bohr's radius, then the energy of nthn^{\text {th}} state (in eV\mathrm{eV}) is [Z={Z}= atomic number]
View answer and explanation
Correct option: A
−0.85 Z2-0.85 ~Z^2
Option A (-0.85 Z²) is correct because it is the energy of the nth state calculated after finding the value of n using the given condition on Bohr's radii.
194 Medium
194 of 257
Understanding +4 | -1
In the above figure DD and EE respectively represent
View answer and explanation
Correct option: A
Absorption line of Balmer series and the ionization energy of hydrogen
The correct answer is Absorption line of Balmer series and the ionization energy of hydrogen because D represents the absorption of energy to excite an electron from n=2, and E represents the energy required to remove an electron from the ground state.
195 Medium
195 of 257
Application +4 | -1
If scattering particles are 56\mathrm{56} for 90∘{90^\circ } angle, then at an angle 60∘{60^\circ } it will be
View answer and explanation
Correct option: A
224
Option A (224) is correct because the number of scattered particles is inversely proportional to the fourth power of the sine of half the scattering angle.
196 Medium
196 of 257
Understanding +4 | -1
The angular momentum of an electron in the first orbit of Li++{Li}^{++}ion is
View answer and explanation
Correct option: C
h2π\frac{h}{2 \pi}
Option C (h2π\frac{h}{2 \pi}) is correct because the angular momentum of an electron in the first orbit is given by nh2π\frac{nh}{2\pi} with n=1.
197 Medium
197 of 257
Understanding +4 | -1
Assertion (A): In a metal all the free electrons have same energy.

Reason (R): Electrons do not obey Pauli's exclusive principle.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D (Both (A) and (R) are false) is correct because free electrons in a metal do not have the same energy, and electrons do obey Pauli's exclusion principle.
198 Medium
198 of 257
Understanding +4 | -1
The electron in a hydrogen atom makes a transition from an excited state to the ground state. Which of the following statements is true
View answer and explanation
Correct option: A
Its kinetic energy increases and its potential and total energies decrease
Option A (Its kinetic energy increases and its potential and total energies decrease) is correct because as the electron transitions to a lower energy level, its kinetic energy increases while potential and total energies decrease.
199 Medium
199 of 257
Remembering +4 | -1
The voltage applied across an X-ray tube is nearly equal to
View answer and explanation
Correct option: D
10, 000 V
Option D (10,000 V) is correct because the voltage applied across an X-ray tube is typically in the kilovolt range to produce X-rays with sufficient energy.
200 Medium
200 of 257
Understanding +4 | -1
In Bohr’s atomic model of hydrogen, let K, P and E are the kinetic energy, potential energy and total energy of the electron respectively. Choose the correct option when the electron undergoes transitions to a higher level:
View answer and explanation
Correct option: B
K decreases, P and E increase
Option B (K decreases, P and E increase) is correct because as the electron transitions to a higher energy level, its kinetic energy decreases while its potential and total energy increase (become less negative).
201 Medium
201 of 257
Application +4 | -1
An electron in the hydrogen atom jumps excited state nn to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75  eV.2.75\;eV. If the stopping potential of the photoelectron is 10  eV,10\;eV, then the value of nn is
View answer and explanation
Correct option: D
4
Option D (4) is correct because the energy difference between the excited state n and the ground state corresponds to the energy of the emitted photon, which can be calculated from the work function and stopping potential.
202 Medium
202 of 257
Remembering +4 | -1
Davisson and Germer experiment proved
View answer and explanation
Correct option: A
Wave nature of light
Option A (Wave nature of light) is correct because the Davisson-Germer experiment demonstrated the wave-like properties of electrons, confirming de Broglie's hypothesis and thus the wave nature of matter, not light.
203 Medium
203 of 257
Analyzing +4 | -1
Consider Bohr's atomic theory of single electron system, where the transition of electron from fourth excited state to second excited state of Lithium emits radiation which knocks out the electron from fourth excited state of an atom of an element. The atomic number of the element is
View answer and explanation
Correct option: A
4
Option A (4) is correct because the energy emitted during the transition in Lithium is equal to the energy required to knock out the electron from the fourth excited state of the element.
204 Medium
204 of 257
Remembering +4 | -1
In the lowest energy level of hydrogen atom, the electron has the angular momentum
View answer and explanation
Correct option: C
h/2πh/2\pi
Option C (h/2πh/2\pi) is correct because, according to Bohr's model, the angular momentum of an electron in the lowest energy level (n=1) of a hydrogen atom is given by L=nh/2πL = nh/2\pi, where n=1.
205 Medium
205 of 257
Analyzing +4 | -1
Which of the following statements about the Bohr model of the hydrogen atom is false
View answer and explanation
Correct option: D
Potential energy of electron in n=2n = 2 orbit is less than that in n=1n = 1 orbit
Option D is correct because the potential energy of an electron becomes less negative (increases) as n increases in the Bohr model.
206 Medium
206 of 257
Understanding +4 | -1
X-rays and γ\gamma-rays of the same energies may be distinguished by
View answer and explanation
Correct option: D
Method of production
Option D (Method of production) is correct because X-rays are produced by accelerating electrons, while gamma rays are produced by nuclear transitions.
207 Hard
207 of 257
Remembering +4 | -1
The ionization energy for second He electron is:
View answer and explanation
Correct option: C
54.4 eV
Option C (54.4 eV) is correct because the ionization energy for the second electron of Helium (He+) is calculated using the formula 13.6 * Z2, where Z is the atomic number (2).
208 Medium
208 of 257
Analyzing +4 | -1
In the hydrogen atom, an electron makes a transition from n=2\mathrm{n}=2 to n=1\mathrm{n}=1. The magnetic field produced by the circulating electron at the nucleus
View answer and explanation
Correct option: D
increases 32 times
Option D (increases 32 times) is correct because the magnetic field produced by the circulating electron at the nucleus is inversely proportional to n5n^5, so when n changes from 2 to 1, the magnetic field increases by a factor of 25=322^5 = 32.
209 Medium
209 of 257
Understanding +4 | -1
In radio therapy, XX-rays are used to
View answer and explanation
Correct option: B
Treat cancer by controlled exposure
Option B (Treat cancer by controlled exposure) is correct because X-rays are used in radiotherapy to kill cancer cells through targeted radiation.
210 Medium
210 of 257
Application +4 | -1
The angular momentum of an electron in hydrogen atom is 5h2π\frac{5 h}{2 \pi}. Here hh is the Plank's constant. The potential energy of this electron is
View answer and explanation
Correct option: C
−1.088 eV-1.088 \,{eV}
Option C (-1.088 eV) is correct because the potential energy is calculated using the formula U=−27.2n2U = \frac{{-27.2}}{{n^2}} eV, where n=5.
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