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JEE • PHYSICS • ATOMS
Atoms practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 211-240 of 257 questions
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211
Medium
211 of 257
Remembering
+4 | -1
In Bohr’s model of hydrogen atom, which of the following represents the variation of nth orbit radius with n?
View answer and explanation
Correct option: D
Option D () is correct because, according to Bohr's model, the radius of the nth orbit is proportional to the square of the principal quantum number n.
212
Medium
212 of 257
Understanding
+4 | -1
The Bohr model of atoms
View answer and explanation
Correct option: B
assumes that the angular momentum of electrons is quantised
Option B (assumes that the angular momentum of electrons is quantised) is correct because Bohr's model postulates that the angular momentum of electrons in atoms is quantized.
213
Medium
213 of 257
Understanding
+4 | -1
Whenever a hydrogen atom emits a photon in the Balmer series
View answer and explanation
Correct option: C
It must emit another photon in the Lyman series
Option C (It must emit another photon in the Lyman series) is correct because after emitting a Balmer series photon, the electron must transition to the ground state, which involves emitting a Lyman series photon.
214
Medium
214 of 257
Analyzing
+4 | -1
An ionised -molecule consist of an electron and two protons. One proton are separated by a small distance of the order of angstrom. In the ground state
View answer and explanation
Correct option: A
The electron would not move in circular orbits
Option A (The electron would not move in circular orbits) is correct because the presence of two protons separated by a small distance will result in a non-uniform electric field, preventing the electron from moving in a perfect circular orbit.
215
Medium
215 of 257
Understanding
+4 | -1
An electron in the orbit of hydrogen atom is bounded by . Energy requires to ionize it is
View answer and explanation
Correct option: A
Option A (13.6 eV) is correct because the ionization energy is equal to the binding energy for an electron in the n=1 orbit.
216
Medium
216 of 257
Remembering
+4 | -1
The wavelength of X-rays is of the order of
View answer and explanation
Correct option: C
Option C () is correct because the wavelength of X-rays falls within the Angstrom range.
217
Medium
217 of 257
Understanding
+4 | -1
For the structural analysis of crystals, -rays are used because
View answer and explanation
Correct option: A
-rays have wavelength of the order of interatomic spacing
Option A (-rays have wavelength of the order of interatomic spacing) is correct because X-rays with wavelengths comparable to interatomic distances are diffracted by the crystal lattice, allowing for structural analysis.
218
Medium
218 of 257
Remembering
+4 | -1
The structure of solid crystals is investigated by using
View answer and explanation
Correct option: B
-rays
Option B (-rays) is correct because X-rays have wavelengths suitable for investigating the structure of solid crystals through diffraction.
219
Medium
219 of 257
Application
+4 | -1
If the wavelength of the first line of the Balmer series in the hydrogen spectrum is then the wavelength of the first line of the Lyman series is
View answer and explanation
Correct option: B
Option B () is correct because it is calculated by finding the Rydberg constant from the Balmer series and then using it to find the wavelength of the Lyman series.
220
Medium
220 of 257
Remembering
+4 | -1
According to Moseley’s law of -rays the frequency of particular characteristic -ray and the atomic number of the element depend on each other as
View answer and explanation
Correct option: D
Option D () is correct because Moseley's law states that the square root of the frequency of characteristic X-rays is proportional to the atomic number of the element.
221
Medium
221 of 257
Application
+4 | -1
The electron beam in a colour TV is accelerated through and then strikes the screen. What is the wavelength of the most energetic X-ray photon?
View answer and explanation
Correct option: A
The correct answer is 38.8 pm. The wavelength of the most energetic X-ray photon is calculated using the energy gained by the electron beam.
222
Medium
222 of 257
Application
+4 | -1
Calculate the shortest wavelength of Lyman series. Given Rydberg's constant, .
View answer and explanation
Correct option: A
Option A () is correct because it is calculated using the Rydberg formula for the shortest wavelength in the Lyman series (n = infinity).
223
Medium
223 of 257
Understanding
+4 | -1
As an electron makes a transition from an excited state to the ground state of hydrogen like atom/ion
View answer and explanation
Correct option: A
Its kinetic energy increases but potential energy and total energy decrease
Option A (Its kinetic energy increases but potential energy and total energy decrease) is correct because as the electron transitions to a lower energy level, its kinetic energy increases, while potential and total energy decrease.
224
Medium
224 of 257
Understanding
+4 | -1
The graph between priciple quantum number and radius of orbit is :
View answer and explanation
Correct option: C
Parabolic curve
Option C is correct because the radius of an orbit is proportional to the square of the principal quantum number, resulting in a parabolic relationship.
225
Medium
225 of 257
Application
+4 | -1
The time period of revolution of electron in its ground state orbit in a hydrogen atom is The frequency of revolution of the electron in its first excited state (in Hz) is
View answer and explanation
Correct option: D
Option D () is correct because it's the frequency of revolution in the first excited state, calculated using the relationship between time period and orbit number.
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226
Medium
226 of 257
Application
+4 | -1
A particle of mass moves in a circular orbit in a central potential field . If Bohr's quantization conditions are applied, radii of possible orbitals vary with , where is ......
View answer and explanation
Correct option: A
3
Option A (3) is correct because by applying Bohr's quantization condition and the given potential, the radius is proportional to .
227
Medium
227 of 257
Understanding
+4 | -1
Penetrating power of X-rays depends on
View answer and explanation
Correct option: B
Applied potential difference
Option B (Applied potential difference) is correct because the energy, and thus the penetrating power, of X-rays is directly proportional to the accelerating voltage.
228
Medium
228 of 257
Application
+4 | -1
An electron beam of energy is incident on metallic foil. If the interatomic distance is . Find the angle of diffraction.
View answer and explanation
Correct option: B
Option B () is correct because it correctly uses the de Broglie wavelength and Bragg's law to find the diffraction angle.
229
Medium
229 of 257
Understanding
+4 | -1
On the basis of Bohr’s atomic model the radius of 3rd orbit of any atom is
View answer and explanation
Correct option: B
Nine times of radius of first orbit
Option B is correct because according to Bohr's model, the radius of the nth orbit is proportional to , so the radius of the 3rd orbit is nine times the radius of the first orbit.
230
Medium
230 of 257
Understanding
+4 | -1
Assertion (A): The positively charged nucleus of an atom has a radius of almost .
Reason (R): In - particle scattering experiment, the distance of closest approach for -particles is .
Reason (R): In - particle scattering experiment, the distance of closest approach for -particles is .
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because the distance of closest approach in the alpha-particle scattering experiment provides an estimate of the nuclear radius.
231
Medium
231 of 257
Understanding
+4 | -1
Which of the following pairs is an isobar
View answer and explanation
Correct option: B
and
Option D ( and ) is correct because isobars are nuclides with the same mass number (A) but different atomic numbers (Z).
232
Medium
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Application
+4 | -1
Calculate the period of revolution of an electron revolving in the first orbit of hydrogen atom. Given radius of first orbit and .
View answer and explanation
Correct option: A
Option A () is correct because it is the period calculated using the formula with the given radius and calculated velocity.
233
Medium
233 of 257
Application
+4 | -1
A stationary hydrogen atom emits photon corresponding to the first line of Lyman series. If is the Rydberg’s constant and is the mass of the atom, then the velocity acquired by the atom is (neglect energy absorbed by the photon)
View answer and explanation
Correct option: B
Option B () is correct because it applies conservation of momentum and the Rydberg formula to find the recoil velocity of the hydrogen atom.
234
Medium
234 of 257
Application
+4 | -1
Find the wavelengths present in the radiation emitted
when hydrogen atoms excited to states return to
their ground states.
when hydrogen atoms excited to states return to
their ground states.
View answer and explanation
Correct option: A
103 nm, 122 nm, 654 nm
Option A (103 nm, 122 nm, 654 nm) is correct because these wavelengths correspond to the transitions from n=3 to n=1, n=3 to n=2, and n=2 to n=1 in the hydrogen atom.
235
Medium
235 of 257
Application
+4 | -1
Hydrogen atom emits blue light when it changes from energy level to the level. Which colour of light would the atom emit when it changes from the level to the level
View answer and explanation
Correct option: D
Violet
Option D (Violet) is correct because transitions to lower energy levels release more energy, and the transition from n=5 to n=2 releases more energy than the transition from n=4 to n=2, resulting in a higher frequency (violet) light.
236
Medium
236 of 257
Analyzing
+4 | -1
The equation can be used to find the de- Broglie wavelength of an electron.
In this equation stands for:
Where m = mass of electron
P = momentum of electron
K = Kinetic energy of electron
V = Accelerating potential in volts for electron
In this equation stands for:
Where m = mass of electron
P = momentum of electron
K = Kinetic energy of electron
V = Accelerating potential in volts for electron
View answer and explanation
Correct option: D
Option D is correct. The de-Broglie wavelength equation can be expressed as λ = 1.227/√V nm, where V is the accelerating potential in volts.
237
Medium
237 of 257
Application
+4 | -1
Taking the Bohr radius as , the radius of ion in its ground state, on the basis of Bohr's model, will be about
View answer and explanation
Correct option: C
Option C () is correct because the radius of the ion is calculated using Bohr's model formula, considering the atomic number and the ground state.
238
Medium
238 of 257
Remembering
+4 | -1
The atomic hydrogen emits a line spectrum consisting of various series. Which series of hydrogen atomic spectra is lying in the visible region?
View answer and explanation
Correct option: D
Balmer series
Option D (Balmer series) is correct because the Balmer series corresponds to transitions to the n=2 energy level, resulting in photons in the visible region of the electromagnetic spectrum.
239
Medium
239 of 257
Application
+4 | -1
X-rays of wavelength 0.140 nm are scattered from a block of carbon. What will be the wavelenghts of X-rays scattered at ?
View answer and explanation
Correct option: B
0.142 nm
Option B (0.142 nm) is correct because it calculates the wavelength shift due to Compton scattering at 90 degrees.
240
Medium
240 of 257
Application
+4 | -1
Suppose, in certain conditions only those transitions are allowed to hydrogen atoms in which the principal quantum number changes by 2.
(a) Find the smallest wavelength emitted by hydrogen.
(b) List the wavelengths emitted by hydrogen in the visible range to ).
(a) Find the smallest wavelength emitted by hydrogen.
(b) List the wavelengths emitted by hydrogen in the visible range to ).
View answer and explanation
Correct option: A
(a) (b)
Option A ((a) (b) ) is correct because the smallest wavelength and the wavelength in the visible range are calculated correctly based on the given transition rule.
Revision notes and key takeaways
Review ATOMS in your textbook or class notes, then use this set to check your understanding.
Showing 211-240 of 257 questions
